Explanation Formula used: The standard equation of the circle with center at ( h , k ) and radius r is ( x − h ) 2 + ( y − k ) 2 = r 2 . Theorem used: Pythagorean Theorem: In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides. Calculation: Let the radius of the earth is r 1 = 3960 mi . In order to find the distance of the satellite from earth’s center add 22,500 mi to r 1 = 3960 mi as follows, r 2 = r 1 + 22 , 500 mi =3960 mi + 22 , 500 mi =26460 mi By Pythagoras theorem, v 2 = ( v H ) 2 + ( v V ) 2 The angular speed w is w = 1

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 21.3, Problem 64E

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To show: The equation relating vH and vV (in mi/h) is that of a circle. when A communications satellite remains stationary at an altitude of 22,500 mi over a point on Earth’s equator. It therefore rotates once each day about Earth’s center. Its velocity is constant, but the horizontal and vertical components, vH and vV, of the velocity constantly change. The radius of earth is 3960 mi.

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Chapter 21.3, Problem 63E

Chapter 21.3, Problem 65E

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Chapter 21 Solutions

Basic Technical Mathematics

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