Integer division: When both operands are integer data types, the resultant statement will be in integer division which means the outcome of the division will also be an integer data type. If there is a remainder, it must be ignored. Example: The example for the integer division is as follows: double value; value = 5 / 3; In the above example, the outcome of the “5” by “3” is stored in the variable “value”. The value “1” is stored in the variable “value” because both “5” and “3” are integers, so the decimal part of the result must be truncated. Floating-point division: When both operands are floating-point or any one of the operand is a floating-point, the resultant statement will be in floating-point division, which means the outcome of the division will be a floating-point data type. Example: The example for the floating-point division is as follows: double value; value = 5.0 / 3; In the above example, the result of the “5.0” by “3” is stored in the variable “value”. The value “1.6667” is stored in the variable “value”, because “5.0” is the floating-point data type and “3” is an integer data type, so the result has a floating-point value.

Question

Want to see the full answer?

Answer 1

Question

Chapter 2.15, Problem 2.28CP

Program Plan Intro

Integer division:

When both operands are integer data types, the resultant statement will be in integer division which means the outcome of the division will also be an integer data type. If there is a remainder, it must be ignored.

Example:

The example for the integer division is as follows:

double value;

value = 5 / 3;

In the above example, the outcome of the “5” by “3” is stored in the variable “value”. The value “1” is stored in the variable “value” because both “5” and “3” are integers, so the decimal part of the result must be truncated.

Floating-point division:

When both operands are floating-point or any one of the operand is a floating-point, the resultant statement will be in floating-point division, which means the outcome of the division will be a floating-point data type.

Example:

The example for the floating-point division is as follows:

double value;

value = 5.0 / 3;

In the above example, the result of the “5.0” by “3” is stored in the variable “value”. The value “1.6667” is stored in the variable “value”, because “5.0” is the floating-point data type and “3” is an integer data type, so the result has a floating-point value.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…

My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…

I would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).