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Materials Science and Engineering
9th Edition
ISBN: 9781118324578
Author: Jr. William D. Callister
Publisher: WILEY
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Question
Chapter 2.10, Problem 3FEQP
To determine
The type of bonding for bronze (a copper tin alloy).
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Please explain in detail how to solve this question.
Show detailed steps in terms of calculation and theory.
thank you
Let the user choose encryption or decryption.
For encryption, let user input the key in Hexadecimal number, the plain text in Hexadecimal number, output the ciphertext (in hexadecimal numbers).
For decryption, let user input the key in Hexadecimal number, the ciphertext (in hexadecimal numbers), output the decrypted message (Hexadecimal number).
Both encryption and decryption should output the different operation results for each round like the following:
For example:
Round 1:
E(R0) = ...... (Hex or Binary)
K1 = ……
E(Ro) xor K1 =
S-box outputs = ……
f(Ro1, K1) = …..
L2 =R1 =…….
La = Ra
Round 2:
.....•
No Encryption/Decryption libraries or functions provided by the third party are allowed.
Submit your program codes to Moodle with the notes of how to compile and run your program.
3-141
Chapter 2 Solutions
Materials Science and Engineering
Ch. 2.10 - Prob. 1QPCh. 2.10 - Prob. 2QPCh. 2.10 - Prob. 3QPCh. 2.10 - Prob. 4QPCh. 2.10 - Prob. 5QPCh. 2.10 - Prob. 6QPCh. 2.10 - Prob. 7QPCh. 2.10 - Prob. 8QPCh. 2.10 - Prob. 9QPCh. 2.10 - Prob. 10QP
Ch. 2.10 - Prob. 11QPCh. 2.10 - Prob. 12QPCh. 2.10 - Prob. 13QPCh. 2.10 - Prob. 14QPCh. 2.10 - Prob. 15QPCh. 2.10 - Prob. 16QPCh. 2.10 - Prob. 17QPCh. 2.10 - Prob. 18QPCh. 2.10 - Prob. 19QPCh. 2.10 - Prob. 20QPCh. 2.10 - Prob. 21QPCh. 2.10 - Prob. 22QPCh. 2.10 - Prob. 23QPCh. 2.10 - Prob. 24QPCh. 2.10 - Prob. 25QPCh. 2.10 - Prob. 26QPCh. 2.10 - Prob. 27QPCh. 2.10 - Prob. 1SSPCh. 2.10 - Prob. 2SSPCh. 2.10 - Prob. 1FEQPCh. 2.10 - Prob. 2FEQPCh. 2.10 - Prob. 3FEQPCh. 2.10 - Prob. 4FEQP
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- Finding crystallographic direction Z pt. 2 head pt. 1: ៩ Example 2: pt. 1 x₁ = a, y₁ = b/2, z₁ = 0 pt. 2 x2=-a, y₂ = b, Z₂ = c -a-a b-b/2 c-0 a b c tail => -2, 1/2, 1 Multiplying by 2 to eliminate the fraction -4,1,2 => [412] where the overbar represents a negative index families of directionsarrow_forward(read image)arrow_forwardQu 2 Schematically plot attractive, repulsive, and net energies versus interatomic separation for two atoms or ions. Note on this plot the equilibrium separation (distance) ro and the bonding energy Eo. Qu 3 How many atoms (or molecules) are in one mole of the substance? Qu 4 Mole, in the context of this book, is taken in units of gram-mole. On this basis, how many atoms are there in a pound-mole of a substance? Qu 5 The atomic radii of Mg* and F ions are 0.072 and 0.133 nm, respectively. Calculate the force of attraction between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another). What is the force of repulsion at this same separation distance?show all work step by step problems formulaarrow_forward
- Qu 4 Silver has FCC crystal structure at room temperature, and a lattice constant, a, of 0.407 nm. Draw a reduced sphere silver unit cell in the grids provided below, clearly label the lattice dimensions. Within the unit cell you drew, shade the (1 0 0) plane. How many atoms are contained within the (1 0 0) plane? Calculate the area of (1 0 0) plane in [nm?]. Express your answer in [nm?] to three significant figures. Calculate the planar density of the (1 0 0) plane in [atoms/nm?]. Express the answer in atoms/nm to three significant figures. show all work step by steparrow_forwardCrystallographic planes Crystallographic planes are denoted by Miller indices. 5b Algorithm for Miller indices 1. Read off intercepts of plane with axes in terms of a, b, c 2. Take reciprocals of intercepts 3. Reduce to smallest integer values 4. Enclose in parentheses, no commas. 353 1/3 1/5 1/3 535 (535) In the cubic system, a plane and a direction with the same indices are orthogonal. E.g. [100] direction is perpendicular to (100) plane. Correspondingly, [123] direction is perpendicular to (123) plane. [2,3,3] Plane intercepts axes at 3a, 2b, 2c 2 11 1 Reciprocal numbers are: 3'2'2 b. Indices of the plane (Miller): (2,3,3) 2 a Indices of the direction: [2,3,3] X (200) (100) (110) (111) (100) Indices of crystallographic plane can be found from cross product of indices of any two non-parallel directions in this plane.arrow_forwardCrystallographic positions Crystallographic position is denoted by three numbers, which are coefficients of the position vector, e.g. ½½½ for the red atom. Here the 'new' atom is at a/2 + b/2 + c/2 Silicon crystal has so-called "diamond type lattice". Each Si atom has 4 nearest neighbors. Diamond lattice starts with a FCC lattice and then adds four additional INTERNAL atoms at locations r = a/4+b/4+c/4 away from each of the atoms. In other words, diamond lattice is formed by two FCC lattices sifted by the vector r.arrow_forward
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