The magnitude of a vector can never be less than the magnitude of one of its components. True False

Please don't use Chatgpt will upvote and give handwritten solution

Please don't use Chatgpt will upvote and give handwritten solution

No chatgpt pls

Consider the situation in the figure below; a neutral conducting ball hangs from the ceiling by an insulating string, and a charged insulating rod is going to be placed nearby. A. First, if the rod was not there, what statement best describes the charge distribution of the ball? 1)  Since it is a conductor, all the charges are on the outside of the ball. 2)  The ball is neutral, so it has no positive or negative charges anywhere. 3)  The positive and negative charges are separated from each other, but we don't know what direction the ball is polarized. 4)  The positive and negative charges are evenly distributed everywhere in the ball.  B. Now, when the rod is moved close to the ball, what happens to the charges on the ball? 1)  There is a separation of charges in the ball; the side closer to the rod becomes positively charged, and the opposite side becomes negatively charged. 2)  Negative charge is drawn from the ground (via the string), so the ball acquires a net negative charge. 3)…

answer question  5-9

AMPS VOLTS OHMS 5) 50 A 110 V 6) .08 A 39 V 7) 0.5 A 60 8) 2.5 A 110 V

The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m², while surface (2) has an area of 3.90 m². The electric field in the drawing is uniform and has a magnitude of 215 N/C. Find the magnitude of the electric flux through surface (1 and 2 combined) if the angle 8 made between the electric field with surface (2) is 30.0°. Solve in Nm²/C 1 Ө Surface 2 Surface 1

PROBLEM 5 What is the magnitude and direction of the resultant force acting on the connection support shown here? F₁ = 700 lbs F2 = 250 lbs 70° 60° F3 = 700 lbs 45° F4 = 300 lbs 40° Fs = 800 lbs 18° Free Body Diagram F₁ = 700 lbs 70° 250 lbs 60° F3= = 700 lbs 45° F₁ = 300 lbs 40° = Fs 800 lbs 18°