To Prove: The power loss in transmission lines, P L is given by P L = ( P T ) 2 R L V 2 ,where P T is the power transmitted to the user, V is the delivered voltage and R L is the resistance of the power lines.

Question

Is work function of a metals surface related to surface energy and surface tension? What is the need to the work function component in the math of tension of metal surfaces that cannot be provided by existing equations of surface energy and surface tension? What are the key differences in each parameter and variables that allow for a differentiation of each function? What has a more significant meaning work function, surface tension or surface energy? Are there real differences and meaning? Please clarify and if possible provide examples . Does surface tension dependant on thickness of a metal or type of metal surface all having the same thickness? Clearly temperature has a profound change on surface tension what other variables besides temperature are key to surface tension. What if any is there a connection between crystal structure of the element and surface energy and tension? This is NOT a Assignment Question!!!

Answer 1

Question

Chapter 21, Problem 83GP

To determine

To Prove:

The power loss in transmission lines, $P_{L}$ is given by $P_{L} = {(P_{T})}^{2} \frac{R_{L}}{V^{2}}$ ,where $P_{T}$ is the power transmitted to the user, V is the delivered voltage and $R_{L}$ is the resistance of the power lines.

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