The many codons code for these amino acids andnucleotides. Dimeric protein contains 142 amino acids in one stand and 148 in the other. Concept Introduction: A codon codes for one amino acid. Therefore, 290 codons are required to code for 290 (142+148) amino acids. A codon is a sequence of three nucleotides , so 290 codons contain 290 × 3 = 870 nucleotides.

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Chapter 21, Problem 70E

Interpretation Introduction

Interpretation: The many codons code for these amino acids andnucleotides. Dimeric protein contains 142 amino acids in one stand and 148 in the other.

Concept Introduction:

A codon codes for one amino acid. Therefore, 290 codons are required to code for 290 (142+148) amino acids.

A codon is a sequence of three nucleotides, so 290 codons contain 290×3=870 nucleotides.

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