To find out is a beta emitter with a half-life of 44.5 days. Concept Introduction: The time take for the material to reduce into half from the initial value is known as Half-life period. In nuclear physics , how fast the unstable atoms undergo and also it deals with how long the atoms survive. It is also used to denote exponential and non-exponential decay. The half life can be shown as t 1 2 = 0.693 k K is decay constant

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Chapter 21, Problem 6SAQ

Interpretation Introduction

Interpretation:

To find out is a beta emitter with a half-life of 44.5 days.

Concept Introduction:

The time take for the material to reduce into half from the initial value is known as Half-life period. In nuclear physics, how fast the unstable atoms undergo and also it deals with how long the atoms survive. It is also used to denote exponential and non-exponential decay.

The half life can be shown as

$t_{\frac{1}{2}} = \frac{0.693}{k}$

K is decay constant

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