Business Math (11th Edition)
11th Edition
ISBN: 9780134496436
Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 21, Problem 5CT
To determine
A horizontal Analysis of a Comparative Income Statementby using the formula of the percent of sales tax when the amount of tax and the amount of item are known.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
AREA OF COMPOUND FIGURE
A compound shape is made up of basic shapes put together.
To find the area of a compound shape, follow these steps:
1. Break the compound shape into basic shapes.
2. Find the area of each basic shape.
3. Add the areas.
Example:
Area A 2 x 9 = 18
Area B = 4x4 = 16
2 ft.
Total area = 18+ 16 = 34
9 ft.
A
5 ft.
6 ft.
4 ft.
B
4 ft.
In a national park, the current population of an endangered species of bear is 80. Each year, the
population decreases by 10%. How can you model the population of bears in the park?
# of years
# of bears
9
10
2
3
4
5
6
7
8
°
1
Graph your data. Remember to title your graph.
What scale should be used on the y-axis?
What scale should be used on the x-axis?
SMOKY
19
OUNTAINS
NATIONAL
Exponential Decay Equation
y = a(1-r)*
PARK
2. Find the Bezier surface equation using the 9 control points shown below. Use
the u and v directions shown. It is required to show all the calculation processes
for finding Bernstein polynomials. Find the surface tangent, twist and normal
vectors at point u=0.5 and v=0.5. (40 points)
y
10
9
8
7
6
5
4
3
2
Poo
и
1
1 2 3 4 5 6 7 8 9
10
10
X
Chapter 21 Solutions
Business Math (11th Edition)
Ch. 21.1 - Prob. 1-1SCCh. 21.1 - Prob. 1-2SCCh. 21.1 - Prob. 1-3SCCh. 21.1 - Prob. 1-4SCCh. 21.1 - Prob. 2-1SCCh. 21.1 - Prob. 2-2SCCh. 21.1 - Prob. 2-3SCCh. 21.1 - Prob. 2-4SCCh. 21.1 - Prob. 3-1SCCh. 21.1 - Prob. 3-2SC
Ch. 21.1 - Prob. 3-3SCCh. 21.1 - Prob. 3-4SCCh. 21.1 - Prob. 1SECh. 21.1 - Prob. 2SECh. 21.1 - Prob. 3SECh. 21.1 - Prob. 4SECh. 21.1 - Prob. 5SECh. 21.1 - Prob. 6SECh. 21.1 - Prob. 7SECh. 21.1 - Prob. 8SECh. 21.1 - Prob. 9SECh. 21.1 - Prob. 10SECh. 21.1 - Prob. 11SECh. 21.1 - Prob. 12SECh. 21.2 - Prob. 1-1SCCh. 21.2 - Prob. 1-2SCCh. 21.2 - Prob. 1-3SCCh. 21.2 - Prob. 1-4SCCh. 21.2 - Prob. 2-1SCCh. 21.2 - Prob. 2-2SCCh. 21.2 - Prob. 2-3SCCh. 21.2 - Prob. 2-4SCCh. 21.2 - Prob. 1SECh. 21.2 - Prob. 2SECh. 21.2 - Prob. 3SECh. 21.2 - Prob. 4SECh. 21.2 - Prob. 5SECh. 21.2 - Prob. 6SECh. 21.2 - Prob. 7SECh. 21.3 - Prob. 1-1SCCh. 21.3 - Prob. 1-2SCCh. 21.3 - Prob. 1-3SCCh. 21.3 - Prob. 1-4SCCh. 21.3 - Prob. 1-5SCCh. 21.3 - Prob. 1-6SCCh. 21.3 - Prob. 1-7SCCh. 21.3 - Prob. 1-8SCCh. 21.3 - Prob. 1-9SCCh. 21.3 - Prob. 1-10SCCh. 21.3 - Prob. 1SECh. 21.3 - Prob. 2SECh. 21.3 - Prob. 3SECh. 21.3 - Prob. 4SECh. 21.3 - Prob. 5SECh. 21.3 - Prob. 6SECh. 21.3 - Prob. 7SECh. 21.3 - Prob. 8SECh. 21.3 - Prob. 9SECh. 21.3 - Prob. 10SECh. 21 - Prob. 1ESCh. 21 - Prob. 2ESCh. 21 - Prob. 3ESCh. 21 - Prob. 4ESCh. 21 - Prob. 5ESCh. 21 - Prob. 6ESCh. 21 - Prob. 7ESCh. 21 - Prob. 8ESCh. 21 - Prob. 9ESCh. 21 - Prob. 10ESCh. 21 - Prob. 11ESCh. 21 - Prob. 12ESCh. 21 - Prob. 13ESCh. 21 - Prob. 14ESCh. 21 - Prob. 15ESCh. 21 - Prob. 16ESCh. 21 - Prob. 17ESCh. 21 - Prob. 18ESCh. 21 - Prob. 19ESCh. 21 - Prob. 20ESCh. 21 - Prob. 21ESCh. 21 - Prob. 22ESCh. 21 - Prob. 23ESCh. 21 - Prob. 24ESCh. 21 - Prob. 25ESCh. 21 - Prob. 26ESCh. 21 - Prob. 1PTCh. 21 - Prob. 2PTCh. 21 - Prob. 3PTCh. 21 - Prob. 4PTCh. 21 - Prob. 5PTCh. 21 - Prob. 6PTCh. 21 - Prob. 7PTCh. 21 - Prob. 8PTCh. 21 - Prob. 9PTCh. 21 - Prob. 10PTCh. 21 - Prob. 11PTCh. 21 - Prob. 12PTCh. 21 - Prob. 1CTCh. 21 - Prob. 2CTCh. 21 - Prob. 3CTCh. 21 - Prob. 4CTCh. 21 - Prob. 5CTCh. 21 - Prob. 6CTCh. 21 - Prob. 7CTCh. 21 - Prob. 8CTCh. 21 - Prob. 9CTCh. 21 - Prob. 10CTCh. 21 - Prob. 11CTCh. 21 - Prob. 1CPCh. 21 - Prob. 2CPCh. 21 - Prob. 3CPCh. 21 - Prob. 1CS1Ch. 21 - Prob. 2CS1Ch. 21 - Prob. 3CS1Ch. 21 - Prob. 1CS2
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.Similar questions
- 3 00 By changing to circular coordinates, evaluate foo √²²+v³ dx dy.arrow_forwardA cable runs along the wall from C to P at a cost of $24 per meter, and straight from P to M at a cost of $26 per meter. If M is 10 meters from the nearest point A on the wall where P lies, and A is 72 meters from C, find the distance from C to P such that the cost of installing the cable is minimized and find this cost. C 72 P A 10 Marrow_forwardThe number of bank robberies in a country for the years 2010-2018 is given in the following figure. Consider the closed interval [2010,2018]. (a) Give all relative maxima and minima and when they occur on the interval. (b) Give the absolute maxima and minima and when they occur on the interval. Incidents 7000- 6000-5 5482 5000- 4424 4273 4822 4000- 3708 3748 4229 4089 3000- 2582 2000- 1000- 0 2010 2012 2014 2016 2018 Yeararrow_forward
- please do 8.1 q7arrow_forwardplease do 8.1 q6arrow_forwardIf the price charged for a candy bar is p(x) cents, then x thousand candy bars will be sold in a certain city, where p(x)=158- X 10° a. Find an expression for the total revenue from the sale of x thousand candy bars. b. Find the value of x that leads to maximum revenue. c. Find the maximum revenue.arrow_forward
- 3 The total profit P(X) (in thousands of dollars) from the sale of x hundred thousand automobile tires is approximated by P(x) = -x³ + 12x² + 60x - 200, x≥5. Find the number of hundred thousands of tires that must be sold to maximize profit. Find the maximum profit. The maximum profit is $ when hundred thousand tires are sold.arrow_forwardA fence must be built to enclose a rectangular area of 5000 ft². Fencing material costs $4 per foot for the two sides facing north and south and $8 per foot for the other two sides. Find the cost of the least expensive fence. The cost of the least expensive fence is $ (Simplify your answer.)arrow_forwardThe number of fish swimming upstream to spawn is approximated by the function given below, where x represents the temperature of the water in degrees Celsius. Find the water temperature that produces the maximum number of fish swimming upstream. F(x) = x3 + 3x² + 360x + 5017, 5≤x≤18arrow_forward
- A campground owner has 500 m of fencing. He wants to enclose a rectangular field bordering a river, with no fencing along the river. (See the sketch.) Let x represent the width of the field. (a) Write an expression for the length of the field as a function of x. (b) Find the area of the field (area = length x width) as a function of x. (c) Find the value of x leading to the maximum area. (d) Find the maximum area. x Riverarrow_forwardA rectangular tank with a square base, an open top, and a volume of 1372 ft³ is to be constructed of sheet steel. Find the dimensions of the tank that has the minimum surface area. The dimensions of the tank with minimum surface area are (Simplify your answer. Use a comma to separate answers.) ft.arrow_forwardWrite an equation for the function graphed below 5+ 4 - -7 -6 -5 -4 -3 -2 -1 y = 3. 2 1 + 1 2 3 4 5 6 7 -1 -3 -4 5 -5+ aarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
Elementary AlgebraAlgebraISBN:9780998625713Author:Lynn Marecek, MaryAnne Anthony-SmithPublisher:OpenStax - Rice University
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Elementary Algebra
Algebra
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:OpenStax - Rice University
Use of ALGEBRA in REAL LIFE; Author: Fast and Easy Maths !;https://www.youtube.com/watch?v=9_PbWFpvkDc;License: Standard YouTube License, CC-BY
Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=P182Abv3fOk;License: Standard YouTube License, CC-BY
Applications of Algebra (Digit, Age, Work, Clock, Mixture and Rate Problems); Author: EngineerProf PH;https://www.youtube.com/watch?v=Y8aJ_wYCS2g;License: Standard YouTube License, CC-BY