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48. A
purpose is to extract heat from a cold reservoir. The same engine
running backward is called a heat pump if its purpose is to ex-
haust warm air into the hot reservoir. Heat pumps are widely used
for home heating. You can think of a heat pump as a refrigera-
tor that is cooling the already cold outdoors and, with its exhaust
heat QH, warming the indoors. Perhaps this seems a little silly, but
consider the following. Electricity can be directly used to heat a
home by passing an
is a direct, 100% conversion of work to heat. That is, 15 kW of
electric power (generated by doing work at the rate of 15 kJ/s at
the power plant) produces heat energy inside the home at a rate of
15 kJ/s. Suppose that the neighbor's home has a heat pump with
a coefficient of performance of 5.0, a realistic value. Note that
"what you get" with a heat pump is heat delivered, QH, so a heat
pump's coefficient of performance is defined as K = QH/ Win.
a. How much electric power (in kW) does the heat pump use to
deliver 15 kJ/s of heat energy to the house?
b. An average price for electricity is about 40 MJ per dollar. A
furnace or heat pump will run typically 250 hours per month
during the winter. What does one month's heating cost in the
home with a 15 kW electric heater and in the home of the
neighbor who uses a heat pump?
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Chapter 21 Solutions
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
- No chatgpt pls will upvote instantarrow_forwardKirchoff's Laws. A circuit contains 3 known resistors, 2 known batteries, and 3 unknown currents as shown. Assume the current flows through the circuit as shown (this is our initial guess, the actual currents may be reverse). Use the sign convention that a potential drop is negative and a potential gain is positive. E₂ = 8V R₁₁ = 50 R₂ = 80 b с w 11 www 12 13 E₁ = 6V R3 = 20 a) Apply Kirchoff's Loop Rule around loop abefa in the clockwise direction starting at point a. (2 pt). b) Apply Kirchoff's Loop Rule around loop bcdeb in the clockwise direction starting at point b. (2 pt). c) Apply Kirchoff's Junction Rule at junction b (1 pt). d) Solve the above 3 equations for the unknown currents I1, 12, and 13 and specify the direction of the current around each loop. (5 pts) I1 = A 12 = A 13 = A Direction of current around loop abef Direction of current around loop bcde (CW or CCW) (CW or CCW)arrow_forwardNo chatgpt pls will upvotearrow_forward
- 4.) The diagram shows the electric field lines of a positively charged conducting sphere of radius R and charge Q. A B Points A and B are located on the same field line. A proton is placed at A and released from rest. The magnitude of the work done by the electric field in moving the proton from A to B is 1.7×10-16 J. Point A is at a distance of 5.0×10-2m from the centre of the sphere. Point B is at a distance of 1.0×10-1 m from the centre of the sphere. (a) Explain why the electric potential decreases from A to B. [2] (b) Draw, on the axes, the variation of electric potential V with distance r from the centre of the sphere. R [2] (c(i)) Calculate the electric potential difference between points A and B. [1] (c(ii)) Determine the charge Q of the sphere. [2] (d) The concept of potential is also used in the context of gravitational fields. Suggest why scientists developed a common terminology to describe different types of fields. [1]arrow_forward3.) The graph shows how current I varies with potential difference V across a component X. 904 80- 70- 60- 50- I/MA 40- 30- 20- 10- 0+ 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 VIV Component X and a cell of negligible internal resistance are placed in a circuit. A variable resistor R is connected in series with component X. The ammeter reads 20mA. 4.0V 4.0V Component X and the cell are now placed in a potential divider circuit. (a) Outline why component X is considered non-ohmic. [1] (b(i)) Determine the resistance of the variable resistor. [3] (b(ii)) Calculate the power dissipated in the circuit. [1] (c(i)) State the range of current that the ammeter can measure as the slider S of the potential divider is moved from Q to P. [1] (c(ii)) Describe, by reference to your answer for (c)(i), the advantage of the potential divider arrangement over the arrangement in (b).arrow_forward1.) Two long parallel current-carrying wires P and Q are separated by 0.10 m. The current in wire P is 5.0 A. The magnetic force on a length of 0.50 m of wire P due to the current in wire Q is 2.0 × 10-s N. (a) State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P. [2] (b) Calculate the current in wire Q. [2] (c) Another current-carrying wire R is placed parallel to wires P and Q and halfway between them as shown. wire P wire R wire Q 0.05 m 0.05 m The net magnetic force on wire Q is now zero. (c.i) State the direction of the current in R, relative to the current in P.[1] (c.ii) Deduce the current in R. [2]arrow_forward
- 2.) A 50.0 resistor is connected to a cell of emf 3.00 V. The voltmeter and the ammeter in the circuit are ideal. V A 50.00 (a) The current in the ammeter is 59.0 mA. Calculate the internal resistance of the cell. The circuit is changed by connecting another resistor R in parallel to the 50.0 resistor. V A 50.00 R (b) Explain the effect of this change on R is made of a resistive wire of uniform cross-sectional area 3.1 × 10-8 m², resistivity 4.9 × 10-70m and length L. The resistance of R is given by the equation R = KL where k is a constant. (b.i) the reading of the ammeter. [2] (b.ii) the reading of the voltmeter. [2] (c) Calculate k. State an appropriate unit for your answer. [3] [2]arrow_forwardNo chatgpt pls will upvotearrow_forwardNo chatgpt pls will upvotearrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
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