EBK ELECTRICAL WIRING RESIDENTIAL
EBK ELECTRICAL WIRING RESIDENTIAL
19th Edition
ISBN: 9781337516549
Author: Simmons
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 2.1, Problem 42R
To determine

State what should be considered when the wall box installation is performing on both the sides of a common partition that separates habitable room and garage.

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1° ⑤ Aa "Human-written solution required" 2. Using the characteristics of Fig. 6.11, determine ID for the following levels of VGs (with VDS > VP): a. VGs = 0V. b. VGs=-1 V. c. VGs -1.5 V. d. VGS -1.8 V. e. VGS = -4 V. f. VGs=-6V. 3. Using the results of problem 2 plot the transfer characteristics of ID vs. VGS- 4. a. Determine Vps for VGs = 0V and Ip = 6 mA using the characteristics of Fig. 6.11. b. Using the results of part (a), calculate the resistance of the JFET for the region Ip = 0 to 6 mA for VGs =0V. c. Determine Vps for VGS = -1 V and ID = 3 mA. d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to 3 mA for VGs -1 V. e. Determine Vps for VGs = -2 V and ID = 1.5 mA. f. Using the results of part (e), calculate the resistance of the JFET for the region ID = 0 to 1.5 mA for VGS-2 V. g. Defining the result of part (b) as ro, determine the resistance for VGs -1 V using Eq. (6.1) and compare with the results of part (d). h. Repeat part (g)…
① Esterfication + R'on R Hydrolysis OH Alcohol A. 0-R Carboxylic Acid Ester NOD-10
4. a. Determine VDs for VGS = 0 V and ID = 6 mA using the characteristics of Fig. 6.11. b. Using the results of part (a), calculate the resistance of the JFET for the region ID = 0 to 6 mA for VGS = 0 V. c. Determine VDs for VGS = -1 V and ID = 3 mA. d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to 3 mA for VGS = -1 V. e. Determine VDs for VGS = -2 V and ID = 1.5 mA. f. Using the results of part (e), calculate the resistance of the JFET for the region ID = 0 to 1.5 mA for VGS = -2 V. g. Defining the result of part (b) as ro, determine the resistance for VGS = -1 V using Eq. (6.1) and compare with the results of part (d). h. Repeat part (g) for VGS = -2 V using the same equation, and compare the results with part (f). i. Based on the results of parts (g) and (h), does Eq. (6.1) appear to be a valid approximation?

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EBK ELECTRICAL WIRING RESIDENTIAL

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EBK ELECTRICAL WIRING RESIDENTIAL
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ISBN:9781337516549
Author:Simmons
Publisher:CENGAGE LEARNING - CONSIGNMENT
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