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In Exercises 23-44, formulate but do not solve the problem. You will be asked to solve these problems in Section 2.2.
BOX-OFFICE RECEIPTS A theater has a seating capacity of 900 and charges $4 for children, $6 for students, and $8 for adults. At a certain screening with full attendance, there were half as many adults as children and students combined. The receipts totaled $5600. How many children attended the show?
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Finite Mathematics For The Managerial, Life, And Social Sciences
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- Shade the areas givenarrow_forward1. Sketch the following sets and determine which are domains: (a) |z−2+i| ≤ 1; - (c) Imz> 1; (e) 0≤ arg z≤ л/4 (z ± 0); Ans. (b), (c) are domains. (b) |2z+3| > 4; (d) Im z = 1; - (f) | z − 4| ≥ |z.arrow_forwardSo let's see, the first one is the first one, and the second one is based on the first one!!arrow_forward
- 4. In each case, sketch the closure of the set: (a) -л 0.arrow_forward1. For each of the functions below, describe the domain of definition that is understood: 1 (a) f(z) = (b) f(z) = Arg z²+1 Z 1 (c) f(z) = (d) f(z) = 1 - | z | 2° Ans. (a) z±i; (b) Rez 0.arrow_forward44 4. Write the function f(x)=2+ ANALYTIC FUNCTIONS 1 (z = 0) Z. in the form f(z) = u(r, 0) + iv(r, 0). Ans. f(z) = = (1 + ² ) cos+ir i ( r — 1 ) sin 0. r CHAP. 2arrow_forward
- Given the (3-2-1) Euler angle set (10,20,30) degrees, find the equivalent (3-1-3) Euler angles. All the following Euler angle sets are 3-2-1 Euler angles. The B frame relative to N is given through the 3-2-1 EAs (10,20,30) degrees, while R relative to N is given by the EAs (-5,5,5) degrees. What is the attitude of B relative to R in terms of the 3-2-1 EAsarrow_forward3. Suppose that f(z) = x² − y² −2y+i (2x-2xy), where z = x+iy. Use the expressions (see Sec. 6) x = z┼え 2 Z - Z and y = 2i to write f(z) in terms of z, and simplify the result. Ans. f(z)²+2iz.arrow_forward10. Prove that a finite set of points Z1, Z2, Zn cannot have any accumulation points.arrow_forward
- 6. Show that a set S is open if and only if each point in S is an interior point.arrow_forward2. Derive the component transformation equations for tensors shown be- low where [C] = [BA] is the direction cosine matrix from frame A to B. B[T] = [C]^[T][C]T 3. The transport theorem for vectors shows that the time derivative can be constructed from two parts: the first is an explicit frame-dependent change of the vector whereas the second is an active rotational change of the vector. The same holds true for tensors. Starting from the previous result, derive a version of transport theorem for tensors. [C] (^[T])[C] = dt d B dt B [T] + [WB/A]B[T] – TWB/A] (10 pt) (7pt)arrow_forwardShade the areas givenarrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageAlgebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal Littell
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin HarcourtElementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning
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