Elementary Differential Equations And Boundary Value Problems, 11th Edition
11th Edition
ISBN: 9781119375753
Author: William E. Boyce, Richard C. DiPrima, Douglas B. Meade
Publisher: WILEY
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Question
Chapter 2.1, Problem 2P
(a)
To determine
To sketch: The directional field for the differential equation
(b)
To determine
The behavior of the solution for large values of
(c)
To determine
To solve: The differential equation
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Problem 11 (a) A tank is discharging water through an orifice at a depth of T
meter below the surface of the water whose area is A m². The
following are the values of a for the corresponding values of A:
A 1.257 1.390
x 1.50 1.65
1.520 1.650 1.809 1.962 2.123 2.295 2.462|2.650
1.80 1.95 2.10 2.25 2.40 2.55 2.70
2.85
Using the formula
-3.0
(0.018)T =
dx.
calculate T, the time in seconds for the level of the water to drop
from 3.0 m to 1.5 m above the orifice.
(b) The velocity of a train which starts from rest is given by the fol-
lowing table, the time being reckoned in minutes from the start
and the speed in km/hour:
| † (minutes) |2|4 6 8 10 12
14 16 18 20
v (km/hr) 16 28.8 40 46.4 51.2 32.0 17.6 8 3.2 0
Estimate approximately the total distance ran in 20 minutes.
-
Let n = 7, let p = 23 and let S be the set of least positive residues mod p of the first (p − 1)/2
multiple of n, i.e.
n mod p, 2n mod p, ...,
p-1
2
-n mod p.
Let T be the subset of S consisting of those residues which exceed p/2.
Find the set T, and hence compute the Legendre symbol (7|23).
23
32
how come?
The first 11 multiples of 7 reduced mod 23 are
7, 14, 21, 5, 12, 19, 3, 10, 17, 1, 8.
The set T is the subset of these residues exceeding
So T = {12, 14, 17, 19, 21}.
By Gauss' lemma (Apostol Theorem 9.6),
(7|23) = (−1)|T| = (−1)5 = −1.
Let n = 7, let p = 23 and let S be the set of least positive residues mod p of the first (p-1)/2
multiple of n, i.e.
n mod p, 2n mod p, ...,
2
p-1
-n mod p.
Let T be the subset of S consisting of those residues which exceed p/2.
Find the set T, and hence compute the Legendre symbol (7|23).
The first 11 multiples of 7 reduced mod 23 are
7, 14, 21, 5, 12, 19, 3, 10, 17, 1, 8.
23
The set T is the subset of these residues exceeding
2°
So T = {12, 14, 17, 19, 21}.
By Gauss' lemma (Apostol Theorem 9.6),
(7|23) = (−1)|T| = (−1)5 = −1.
how come?
Chapter 2 Solutions
Elementary Differential Equations And Boundary Value Problems, 11th Edition
Ch. 2.1 - Prob. 1PCh. 2.1 - Prob. 2PCh. 2.1 - Prob. 3PCh. 2.1 - Prob. 4PCh. 2.1 - Prob. 5PCh. 2.1 - Prob. 6PCh. 2.1 - Prob. 7PCh. 2.1 - Prob. 8PCh. 2.1 - Prob. 9PCh. 2.1 - Prob. 10P
Ch. 2.1 - Prob. 11PCh. 2.1 - Prob. 12PCh. 2.1 - Prob. 13PCh. 2.1 - Prob. 14PCh. 2.1 - Prob. 15PCh. 2.1 - Prob. 16PCh. 2.1 - Prob. 17PCh. 2.1 - Prob. 18PCh. 2.1 - Prob. 19PCh. 2.1 - Prob. 20PCh. 2.1 - Prob. 21PCh. 2.1 - Prob. 22PCh. 2.1 - Prob. 23PCh. 2.1 - Prob. 24PCh. 2.1 - Prob. 25PCh. 2.1 - Prob. 26PCh. 2.1 - Prob. 27PCh. 2.1 - Variation of Parameters. Consider the following...Ch. 2.1 - Prob. 29PCh. 2.1 - In each of Problems 29 and 30, use the method of...Ch. 2.2 - Prob. 1PCh. 2.2 - Prob. 2PCh. 2.2 - Prob. 3PCh. 2.2 - Prob. 4PCh. 2.2 - Prob. 5PCh. 2.2 - Prob. 6PCh. 2.2 - In each of Problems 1 through 8, solve the given...Ch. 2.2 - In each of Problems 1 through 8, solve the given...Ch. 2.2 - Prob. 9PCh. 2.2 - Prob. 10PCh. 2.2 - Prob. 11PCh. 2.2 - Prob. 12PCh. 2.2 - Prob. 13PCh. 2.2 - Prob. 14PCh. 2.2 - Prob. 15PCh. 2.2 - Prob. 16PCh. 2.2 - Prob. 17PCh. 2.2 - Prob. 18PCh. 2.2 - Prob. 19PCh. 2.2 - Prob. 20PCh. 2.2 - Prob. 21PCh. 2.2 - Prob. 22PCh. 2.2 - Prob. 23PCh. 2.2 - Prob. 24PCh. 2.2 - Prob. 25PCh. 2.2 - Prob. 26PCh. 2.2 - Prob. 27PCh. 2.2 - Prob. 28PCh. 2.2 - Prob. 29PCh. 2.2 - Prob. 30PCh. 2.2 - Prob. 31PCh. 2.3 - Prob. 1PCh. 2.3 - Prob. 2PCh. 2.3 - Prob. 3PCh. 2.3 - Prob. 4PCh. 2.3 - Prob. 5PCh. 2.3 - Prob. 6PCh. 2.3 - Prob. 7PCh. 2.3 - Prob. 8PCh. 2.3 - Prob. 9PCh. 2.3 - Prob. 10PCh. 2.3 - Prob. 11PCh. 2.3 - Prob. 12PCh. 2.3 - Prob. 13PCh. 2.3 - Prob. 14PCh. 2.3 - Prob. 15PCh. 2.3 - Prob. 16PCh. 2.3 - Assume that the conditions are as in Problem 16...Ch. 2.3 - Prob. 18PCh. 2.3 - Prob. 19PCh. 2.3 - Prob. 20PCh. 2.3 - Prob. 21PCh. 2.3 - Prob. 22PCh. 2.3 - Prob. 23PCh. 2.3 - Prob. 24PCh. 2.4 - In each of Problems 1 through 6, determine...Ch. 2.4 - Prob. 2PCh. 2.4 - Prob. 3PCh. 2.4 - Prob. 4PCh. 2.4 - Prob. 5PCh. 2.4 - Prob. 6PCh. 2.4 - Prob. 7PCh. 2.4 - Prob. 8PCh. 2.4 - Prob. 9PCh. 2.4 - Prob. 10PCh. 2.4 - Prob. 11PCh. 2.4 - Prob. 12PCh. 2.4 - Prob. 13PCh. 2.4 - Prob. 14PCh. 2.4 - Prob. 15PCh. 2.4 - Prob. 16PCh. 2.4 - Prob. 17PCh. 2.4 - Prob. 18PCh. 2.4 - Prob. 19PCh. 2.4 - Prob. 20PCh. 2.4 - Prob. 21PCh. 2.4 - Prob. 22PCh. 2.4 - Prob. 23PCh. 2.4 - Prob. 24PCh. 2.4 - Prob. 25PCh. 2.4 - Prob. 26PCh. 2.4 - Prob. 27PCh. 2.5 - Prob. 1PCh. 2.5 - Prob. 2PCh. 2.5 - Prob. 3PCh. 2.5 - Prob. 4PCh. 2.5 - Prob. 5PCh. 2.5 - Prob. 6PCh. 2.5 - Prob. 7PCh. 2.5 - Prob. 8PCh. 2.5 - Prob. 9PCh. 2.5 - Prob. 10PCh. 2.5 - Prob. 11PCh. 2.5 - Prob. 12PCh. 2.5 - Prob. 13PCh. 2.5 - Prob. 14PCh. 2.5 - Prob. 15PCh. 2.5 - Prob. 16PCh. 2.5 - Prob. 17PCh. 2.5 - Prob. 18PCh. 2.5 - Prob. 19PCh. 2.5 - Prob. 20PCh. 2.5 - Prob. 21PCh. 2.5 - Prob. 22PCh. 2.5 - Prob. 23PCh. 2.5 - Prob. 24PCh. 2.5 - Prob. 25PCh. 2.5 - Prob. 26PCh. 2.5 - Prob. 27PCh. 2.6 - Prob. 1PCh. 2.6 - Prob. 2PCh. 2.6 - Prob. 3PCh. 2.6 - Prob. 4PCh. 2.6 - Prob. 5PCh. 2.6 - Prob. 6PCh. 2.6 - Prob. 7PCh. 2.6 - Prob. 8PCh. 2.6 - Prob. 9PCh. 2.6 - Prob. 10PCh. 2.6 - Prob. 11PCh. 2.6 - Prob. 12PCh. 2.6 - Prob. 13PCh. 2.6 - Prob. 14PCh. 2.6 - Prob. 15PCh. 2.6 - Prob. 16PCh. 2.6 - Prob. 17PCh. 2.6 - Prob. 18PCh. 2.6 - Prob. 19PCh. 2.6 - Prob. 20PCh. 2.6 - Prob. 21PCh. 2.6 - Prob. 22PCh. 2.7 - Prob. 1PCh. 2.7 - Prob. 2PCh. 2.7 - Prob. 3PCh. 2.7 - Prob. 4PCh. 2.7 - Prob. 5PCh. 2.7 - Prob. 6PCh. 2.7 - Prob. 7PCh. 2.7 - Prob. 8PCh. 2.7 - Prob. 9PCh. 2.7 - Prob. 10PCh. 2.7 - Prob. 11PCh. 2.7 - Prob. 12PCh. 2.7 - Prob. 14PCh. 2.7 - Prob. 15PCh. 2.7 - Prob. 16PCh. 2.7 - Prob. 17PCh. 2.8 - Prob. 1PCh. 2.8 - Prob. 2PCh. 2.8 - Prob. 3PCh. 2.8 - Prob. 4PCh. 2.8 - Prob. 5PCh. 2.8 - Prob. 6PCh. 2.8 - Prob. 7PCh. 2.8 - Prob. 8PCh. 2.8 - Prob. 9PCh. 2.8 - Prob. 10PCh. 2.8 - Prob. 11PCh. 2.8 - Prob. 12PCh. 2.8 - Prob. 13PCh. 2.8 - Prob. 14PCh. 2.8 - Prob. 15PCh. 2.8 - Prob. 16PCh. 2.8 - Prob. 17PCh. 2.8 - Prob. 18PCh. 2.9 - Prob. 1PCh. 2.9 - Prob. 2PCh. 2.9 - Prob. 3PCh. 2.9 - Prob. 4PCh. 2.9 - Prob. 5PCh. 2.9 - Prob. 6PCh. 2.9 - Prob. 7PCh. 2.9 - Prob. 8PCh. 2.9 - Prob. 9PCh. 2.9 - Prob. 10PCh. 2 - Prob. 1MPCh. 2 - Prob. 2MPCh. 2 - Prob. 3MPCh. 2 - Prob. 4MPCh. 2 - Prob. 5MPCh. 2 - Prob. 6MPCh. 2 - Prob. 7MPCh. 2 - Prob. 8MPCh. 2 - Prob. 9MPCh. 2 - Prob. 10MPCh. 2 - Prob. 11MPCh. 2 - Prob. 12MPCh. 2 - Prob. 13MPCh. 2 - Prob. 14MPCh. 2 - Prob. 15MPCh. 2 - Prob. 16MPCh. 2 - Prob. 17MPCh. 2 - Prob. 18MPCh. 2 - Prob. 19MPCh. 2 - Prob. 20MPCh. 2 - Prob. 21MPCh. 2 - Prob. 22MPCh. 2 - Prob. 23MPCh. 2 - Prob. 24MPCh. 2 - Prob. 25MPCh. 2 - Prob. 28MPCh. 2 - Prob. 29MPCh. 2 - Prob. 31MPCh. 2 - Prob. 32MPCh. 2 - Prob. 33MPCh. 2 - Prob. 34MPCh. 2 - Prob. 35MPCh. 2 - Prob. 36MPCh. 2 - Prob. 37MP
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