![Bundle: General Chemistry, Loose-leaf Version, 11th + OWLv2, 4 terms (24 months) Printed Access Card](https://www.bartleby.com/isbn_cover_images/9781337128391/9781337128391_largeCoverImage.gif)
(a)
Interpretation:
A complete and balanced equation for the following reaction has to be written. ‘NR’ has to be written in case of no reaction.
Concept introduction:
- There is a Law for conversion of mass in a
chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants. - The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
- First write the reaction from the given information.
- Then count the number of atoms of each element in reactants as well as products.
- Finally obtained values could place it as coefficients of reactants as well as products.
- Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized. Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
Oxidation reduction and reduction reaction occur simultaneously in same reaction.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 21.61QP
The balanced equation for the given reaction is,
Explanation of Solution
Halide ions and Halogens act as oxidizing and reducing agents. Reaction between halide ions and halogens depend upon their strength as oxidizing and reducing agent. A reducing agent loses electron whereas an oxidizing agent gains electrons.
A halide ion or halogen which is stronger oxidizing agent reacts only with a halide ion or halogen which is stronger reducing agent. Iodine, in presence of Chloride ion is not a strong oxidizing agent that it doesn’t react with chloride ion.
(b)
Interpretation:
A complete and balanced equation for the following reaction has to be written. ‘NR’ has to be written in case of no reaction.
Concept introduction:
- There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
- The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
- First write the reaction from the given information.
- Then count the number of atoms of each element in reactants as well as products.
- Finally obtained values could place it as coefficients of reactants as well as products.
- Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized. Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
- Oxidation reduction and reduction reaction occur simultaneously in same reaction.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 21.61QP
The balanced equation for the given reaction is,
Explanation of Solution
Halide ions and Halogens act as oxidizing and reducing agents. Reaction between halide ions and halogens depend upon their strength as oxidizing and reducing agent. A reducing agent loses electron whereas an oxidizing agent gains electrons.
A halide ion or halogen which is stronger oxidizing agent reacts only with a halide ion or halogen which is stronger reducing agent. Chlorine, in presence of Bromide ion is a strong reducing agent that it reduces bromide ion to bromine.
The balanced equation for the given reaction is,
(c)
Interpretation:
A complete and balanced equation for the following reaction has to be written. ‘NR’ has to be written in case of no reaction.
Concept introduction:
- There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
- The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
- First write the reaction from the given information.
- Then count the number of atoms of each element in reactants as well as products.
- Finally obtained values could place it as coefficients of reactants as well as products.
- Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized. Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
- Oxidation reduction and reduction reaction occur simultaneously in same reaction.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 21.61QP
The balanced equation for the given reaction is,
Explanation of Solution
Halide ions and Halogens act as oxidizing and reducing agents. Reaction between halide ions and halogens depend upon their strength as oxidizing and reducing agent. A reducing agent loses electron whereas an oxidizing agent gains electrons.
A halide ion or halogen which is stronger oxidizing agent reacts only with a halide ion or halogen which is stronger reducing agent. Bromine, in presence of Iodide ion is a strong reducing agent that it reduces iodide ion to iodine.
The balanced equation for the given reaction is,
(d)
Interpretation:
A complete and balanced equation for the following reaction has to be written. ‘NR’ has to be written in case of no reaction.
Concept introduction:
- There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
- The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
- First write the reaction from the given information.
- Then count the number of atoms of each element in reactants as well as products.
- Finally obtained values could place it as coefficients of reactants as well as products.
- Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized. Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
- Oxidation reduction and reduction reaction occur simultaneously in same reaction.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 21.61QP
The balanced equation for the given reaction is,
Explanation of Solution
Halide ions and Halogens act as oxidizing and reducing agents. Reaction between halide ions and halogens depend upon their strength as oxidizing and reducing agent. A reducing agent loses electron whereas an oxidizing agent gains electrons.
A halide ion or halogen which is stronger oxidizing agent reacts only with a halide ion or halogen which is stronger reducing agent. Bromine, in presence of Chloride ion is not a strong reducing agent that it reduce chloride ion to chlorine.
Want to see more full solutions like this?
Chapter 21 Solutions
Bundle: General Chemistry, Loose-leaf Version, 11th + OWLv2, 4 terms (24 months) Printed Access Card
- Nonearrow_forwardH2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forward
- Nonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forward
- IV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forward
- Nonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399074/9781337399074_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133949640/9781133949640_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079243/9781305079243_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133611097/9781133611097_smallCoverImage.gif)