A balanced nuclear equation that describes α decay of boron − 12 . Interpretation: A balanced nuclear equation which describes α decay of boron − 12 is to be given. Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

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Answer 1

Question

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

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Answer 2

Question

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

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Answer 3

Question

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

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Answer 4

Question

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

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Answer 5

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

Answer 6

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

Answer 7

Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes α decay of boron−12.

Interpretation: A balanced nuclear equation which describes α decay of boron−12 is to be given.

Concept introduction: The decay with α particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

Answer 8

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

Answer 9

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

Answer 10

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

Answer 11

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of manganese-50.

Interpretation: A balanced nuclear equation which describes positron emission of manganese-50. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

Answer 12

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

Answer 13

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by cadmium-104.

Interpretation: A balanced nuclear equation which describes electron captured by cadmium-104 is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

Ch. 21.2 - Prob. 1PE Ch. 21.3 - Prob. 2PE Ch. 21.4 - Prob. 3PE Ch. 21.5 - Prob. 4PE Ch. 21.6 - Prob. 5PE Ch. 21.9 - Prob. 6PE Ch. 21 - Prob. 21.1VP Ch. 21 - Prob. 21.2VP Ch. 21 - Prob. 21.3VP Ch. 21 - Prob. 21.4VP

Concept explainers

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

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Chapter 21 Solutions

Concept explainers

To determine: a balanced nuclear equation that describes β decay of boron−12. Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given. Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number

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Chapter 21 Solutions

To determine: a balanced nuclear equation that describes β decay of boron−12.

Interpretation: A balanced nuclear equation which describes β decay of boron−12 is to be given.

Concept introduction: The decay with β particle results in the formation of isotope that has one extra atomic number