
Applied Physics
11th Edition
ISBN: 9780132719865
Author: EWEN, Dale
Publisher: PEARSON
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Textbook Question
Chapter 2.1, Problem 19P
V = E – Ir for l
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Part A:
kg
(a) Water at 20 °C (p = 998.3 and v = 1 × 10-6 m²/s) flows through a galvanised
m³
iron pipe (k = 0.15 mm) with a diameter of 25 mm, entering the room at point A and
discharging at point C from the fully opened gate valve B at a volumetric flow rate of
0.003 m³/s. Determine the required pressure at A, considering all the losses that occur
in the system described in Figure Q1. Loss coefficients for pipe fittings have been
provided in Table 1.
[25 marks]
(b) Due to corrosion within the pipe, the average flow velocity at C is observed to be
V2 m/s after 10 years of operation whilst the pressure at A remains the same as
determined in (a). Determine the average annual rate of growth of k within the pipe.
[15 marks]
4₁
Figure Q1. Pipe system
Page 2
25 mm
For an independent study project, you design an experiment to measure the speed of light. You propose to bounce laser light off a mirror that is 53.5 km due east and have it detected by a light sensor that is 119 m due south of the laser. The first problem is to orient the mirror so that the laser light reflects off the mirror and into the light sensor.
(a) Determine the angle that the normal to the mirror should make with respect to due west.(b) Since you can read your protractor only so accurately, the mirror is slightly misaligned and the actual angle between the normal to the mirror and due west exceeds the desired amount by 0.003°. Determine how far south you need to move the light sensor in order to detect the reflected laser light.
A mirror hangs 1.67 m above the floor on a vertical wall. A ray of sunlight, reflected off the mirror, forms a spot on the floor 1.41 m from the wall. Later in the day, the spot has moved to a point 2.50 m from the
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(a) What is the change in the angle of elevation of the Sun, between the two observations?
Chapter 2 Solutions
Applied Physics
Ch. 2.1 - =stforSCh. 2.1 - a=tforVCh. 2.1 - w = mg for mCh. 2.1 - F = ma for aCh. 2.1 - E = IR for RCh. 2.1 - V = lwh for wCh. 2.1 - Ep = mgh for gCh. 2.1 - Ep = mgh for hCh. 2.1 - 2 = 2gh for hCh. 2.1 - XL = 2 f L for f
Ch. 2.1 - P=WtforWCh. 2.1 - p=FAforFCh. 2.1 - P=WtforiCh. 2.1 - p=FAforACh. 2.1 - Ek=12m2formCh. 2.1 - Ek=12m2Ch. 2.1 - W = Fs for SCh. 2.1 - f = i + at for aCh. 2.1 - V = E Ir for lCh. 2.1 - 2 = 1 + at for tCh. 2.1 - R=2PforPCh. 2.1 - R=kLd2forLCh. 2.1 - Prob. 23PCh. 2.1 - XC=12fCforfCh. 2.1 - R=LAforLCh. 2.1 - RT = R1 + R2 + R3 + R4 for R3Ch. 2.1 - Q1 = P(Q2 Q1) for Q2Ch. 2.1 - ISIP=NPNSforIPCh. 2.1 - VPVS=NPNSforNSCh. 2.1 - Prob. 31PCh. 2.1 - Prob. 32PCh. 2.1 - Prob. 33PCh. 2.1 - Ft=m(V2V1)forV1Ch. 2.1 - Q=I2RtJforRCh. 2.1 - x=xi+it+12at2forX1Ch. 2.1 - A = r2 for r, Where r is a radiusCh. 2.1 - V = r2h for r, Where r is a radiusCh. 2.1 - R=kLd2 for d, where d is a diameterCh. 2.1 - V=13r2h for r, where r is a radiusCh. 2.1 - Solve each formula for the quantity given. 41....Ch. 2.1 - Solve each formula for the quantity given. 42....Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.3 - Find the volume of the box in Fig. 2.3. Figure 2.3Ch. 2.3 - Find the volume of a cylinder whose height is 7.50...Ch. 2.3 - Find the volume of a cone whose height is 9.30 cm...Ch. 2.3 - Find the volume of the cylinder. Figure 2.6Ch. 2.3 - Find the cross-sectional area of the cylinder....Ch. 2.3 - Find the lateral surface area of the cylinder....Ch. 2.3 - Find the total volume of the building shown in...Ch. 2.3 - Find the cross-sectional area of the concrete...Ch. 2.3 - Find the volume of a rectangular storage facility...Ch. 2.3 - Find the cross-sectional area of a piston head...Ch. 2.3 - Find the area of a right triangle that has legs of...Ch. 2.3 - Find the length of the hypotenuse of the right...Ch. 2.3 - Find the cross-sectional area of a pipe with outer...Ch. 2.3 - Find the volume of a spherical water tank with...Ch. 2.3 - The area of a rectangular parking lot is 900m2. If...Ch. 2.3 - The volume of a rectangular crate is 192 ft3. If...Ch. 2.3 - Find the volume of a brake cylinder whose diameter...Ch. 2.3 - Find the volume of a tractor engine cylinder whose...Ch. 2.3 - A cylindrical silo has a circumference of 29.5 m....Ch. 2.3 - If the silo in Problem 19 has a capacity of...Ch. 2.3 - A wheel 30.0 cm in diameter moving along level...Ch. 2.3 - The side of the silo in Problems 19 and 20 needs...Ch. 2.3 - You are asked to design a cylindrical water tank...Ch. 2.3 - If the height of the water tank in Problem 23 were...Ch. 2.3 - A ceiling is 12.0 ft by 15.0 ft. How many...Ch. 2.3 - Find the cross-sectional area of the dovetail...Ch. 2.3 - Find tile volume of the storage bin shown in Fig....Ch. 2.3 - The maximum cross-sectional area of a spherical...Ch. 2.3 - How many cubic yards of concrete are needed to...Ch. 2.3 - What length of sidewalk 4.00 in. thick and 4.00 ft...Ch. 2.3 - Find the volume of each figure.Ch. 2.3 - Inside diameter: 20.0 cm Outside diameter: 50.0 cmCh. 2 - A formula is a. the amount of each value needed....Ch. 2 - Subscripts are a. the same as exponents. b. used...Ch. 2 - A working equation a. is derived from the basic...Ch. 2 - Cite two examples in industry in which formulas...Ch. 2 - How are subscripts used in measurement?Ch. 2 - Why is reading the problem carefully the most...Ch. 2 - How can making a sketch help in problem solving?Ch. 2 - What do we call the relationship between data that...Ch. 2 - How is a working equation different from a basic...Ch. 2 - How can analysis of the units in a problem assist...Ch. 2 - How can making an estimate of your answer assist...Ch. 2 - Solve F = ma for (a) m and (b) a.Ch. 2 - Solve =2ghforh.Ch. 2 - Solve s=12(f+i)tforf.Ch. 2 - Prob. 4RPCh. 2 - Given P = a + b + c, with P = 36 ft, a = 12 ft,...Ch. 2 - Given A=(a+b2)h, with A=210m2, b = 16.0 m, and h =...Ch. 2 - Given A = r2, if A. = 15.0 m2, find r.Ch. 2 - Given A=12bh, if b = 12.2 cm and h = 20.0 cm, what...Ch. 2 - A cone has a volume of 314 cm3 and radius of 5.00...Ch. 2 - A right triangle has a side of 41.2 mm and a side...Ch. 2 - Given a cylinder with a radius of 7 .20 cm and a...Ch. 2 - A rectangle has a perimeter of 40.0 cm. One side...Ch. 2 - The formula for the volume of a cylinder is V =...Ch. 2 - The formula for the area of a triangle is A=12bh....Ch. 2 - Find the volume of the lead sleeve with the cored...Ch. 2 - A rectangular plot of land measure 40.0 m by...Ch. 2 - You run a landscaping business and know that you...Ch. 2 - A room that measures 10.0 ft wide, 32.0 ft long,...Ch. 2 - Instead of using a solid iron beam, structural...Ch. 2 - A shipping specialist at a craft store needs to...Ch. 2 - A crane needs to lift a spool of fine steel cable...
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Length contraction: the real explanation; Author: Fermilab;https://www.youtube.com/watch?v=-Poz_95_0RA;License: Standard YouTube License, CC-BY