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(a)
Interpretation: The band that is the valence band should be determined.
Concept Introduction:The band that forms from bonding molecular orbital in a semiconductor is called the valence band
(b)
Interpretation: The band that is the conduction band should be determined.
Concept Introduction: The band that forms from anti-bonding molecular orbital in a semiconductor is called the conduction band.
(c)
Interpretation: The region of the diagram that represents the band gap should be determined.
Concept Introduction: The band gap is the gap between the valence band and conduction band.
(d)
Interpretation: The band that consists of bonding molecular orbital should be determined.
Concept Introduction:The band that forms from bonding molecular orbital in a semiconductor is called the valence band that contains bonding molecular orbital
(e)
Interpretation: The type of semiconductor represented by the diagram should be explained.
Concept Introduction:An n-type semiconductor is one in which the dopant element has more number of valence electrons than the host element and this leads to an increase in number of negatively charged electrons in the conduction band that can move easily. So, in an n-type semiconductor conduction band is not completely empty.
A p-type semiconductor is one in which the dopant element has less number of valence electrons than the host element and this leads to electron vacancies, known as holes, in the valence band. Thus in a p-type semiconductor the valence band has electron vacancies and is not completely filled with electrons.
(f)
Interpretation: The elements that could be dopant from the given elements
Concept Introduction:The doped semiconductor given in the diagram is a p-type semiconductor. It means the dopant element must have less valence electron than germanium.
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Chapter 20 Solutions
Chemistry the Central Science 13th Edition Custom for Lamar University
- Provide steps and explanation please.arrow_forwardDraw a structural formula for the major product of the acid-base reaction shown. H 0 N + HCI (1 mole) CH3 N' (1 mole) CH3 You do not have to consider stereochemistry. ● • Do not include counter-ions, e.g., Na+, I, in your answer. . In those cases in which there are two reactants, draw only the product from 989 CH3 344 ? [Farrow_forwardQuestion 15 What is the major neutral organic product for the following sequence? 1. POCI₂ pyridine ? 2. OsO4 OH 3. NaHSO Major Organic Product ✓ OH OH 'OH OH 'OH 'CIarrow_forward
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
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