Concept explainers
Interpretation:
The foods containing carbohydrates and fats should be distinguished.
Concept introduction:
The 90% of the dry weight to the body is supplied by carbohydrates, proteins and fats. All of them provide energy to the body in calories but the amount per gram is different for each.
Carbohydrates provide 4 calories per gram but fat provides 9 calories per gram. The supply of energy is fast in carbohydrates and slow in fats. The basic units of the carbohydrates, proteins and fats are formed by their breakdown when digested in the intestine. Carbohydrate gets broken down into sugars, proteins into amino acids and fats into fatty acid and glycerol.
These basic units are used by body for the development.
Carbohydrates can be complex or simple depending on the size of the molecules. Simple carbohydrates are in the form of sugars such as glucose and sucrose. The molecules of these carbohydrates are small therefore; they can be easily broken down into simpler molecules in the body and provide energy. Complex carbohydrates are long chains of simple carbohydrates thus, they can be broken down easily and slowly provide energy to the body. Since, they are complex there is less chance of them to get converted into fat.
Fats are complex molecules composed of glycerol and fatty acids. The fats are needed by body for growth and energy. It is used in the synthesis of hormones. Fats slowly provides energy to the body as they are efficient source of energy, the excess energy is stored in body as fat. If fatty acids are required in the body, it can be synthesized. The fatty acids that cannot be synthesized by the body are known as essential fatty acids. Some examples are linoleic acid, arachidonjic acid both are examples of omega-6 fatty acids. The other fatty acids are omega-3 fatty acids example are linolenic acid, eicosapentaenoic acid etc.
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 20 Solutions
INTRO.TO GENERAL,ORGAN...-OWLV2 ACCESS
- CS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forwardThe following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forwardControl Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forward
- Collagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forwardיווי 10 20 30 40 50 60 70 3.5 3 2.5 2 1.5 1 [ppm] 3.5 3 2.5 2 1.5 1 6 [ppm] 1 1.5 -2.5 3.5arrow_forward2H2S(g)+3O2(g)→2SO2(g)+2H2O(g) A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion. Question Which of the following predicts the theoretical yield of SO2(g) from the reaction? Responses 1.2 g Answer A: 1.2 grams A 41 g Answer B: 41 grams B 77 g Answer C: 77 grams C 154 g Answer D: 154 grams Darrow_forward
- Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10arrow_forwardQ: Arrange BCC and Fec metals, in sequence from the Fable (Dr. R's slides) and Calculate Volume and Density. Aa BCC V 52 5 SFCCarrow_forwardNonearrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285869759/9781285869759_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285853918/9781285853918_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305081079/9781305081079_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133109655/9781133109655_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079243/9781305079243_smallCoverImage.gif)