Chapter 20, Problem 86AP

Interpretation Introduction

Interpretation:

The quantity of $\text{Zn}$ produced, in the radioactive decay of isotope of copper, after a given time is to be calculated.

Concept introduction:

The amount of a particular radioactive isotope left, after time t, is given as follows:

$\text{ln}\frac{N_t}{N_o}=-kt$

Here, $k$ is the rate constant for the radioactive decay, $N_t$ is the amount of it left after time $t$, and $N_0$ is the initial amount of the sample.

Nearly all the radioactive decay is of the first order and its rate constant is given as follows:

$k\text{ = }\frac{0.693}{t_{1/2}}$

Here, $t_{1/2}$ is the half-life of the radioactive substance.

The half-life of $\text{Cu-64}$ is $12.8\text{ hr}$.