Suppose 2.00 mol of a diatomic gas is taken reversibly around the cycle shown in the T-S diagram of Fig. 20-35. where S 1 = 6.00 J/K and S 2 = 8.00 J/K. The molecules do not rotate or oscillate. What is the energy transferred as heat Q for (a) path 1 → 2, (b) path 2 → 3, and (c) the full cycle? (d) What is the work W for the isothermal process? The volume V 1 in state 1 is 0.200 m 3 . What is the volume in (e) state 2 and (f) state 3? What is the change Δ E int for (g) path 1 → 2, (h) path 2 → 3, and (i) the full cycle? ( Hint: (h) can be done with one or two lines of calculation using Module 19-7 or with a page of calculation using Module 19-9.) (j) What is the work W for the adiabatic process? Figure 20-35 Problem 62.
Suppose 2.00 mol of a diatomic gas is taken reversibly around the cycle shown in the T-S diagram of Fig. 20-35. where S 1 = 6.00 J/K and S 2 = 8.00 J/K. The molecules do not rotate or oscillate. What is the energy transferred as heat Q for (a) path 1 → 2, (b) path 2 → 3, and (c) the full cycle? (d) What is the work W for the isothermal process? The volume V 1 in state 1 is 0.200 m 3 . What is the volume in (e) state 2 and (f) state 3? What is the change Δ E int for (g) path 1 → 2, (h) path 2 → 3, and (i) the full cycle? ( Hint: (h) can be done with one or two lines of calculation using Module 19-7 or with a page of calculation using Module 19-9.) (j) What is the work W for the adiabatic process? Figure 20-35 Problem 62.
Suppose 2.00 mol of a diatomic gas is taken reversibly around the cycle shown in the T-S diagram of Fig. 20-35. where S1 = 6.00 J/K and S2 = 8.00 J/K. The molecules do not rotate or oscillate. What is the energy transferred as heat Q for (a) path 1 → 2, (b) path 2 → 3, and (c) the full cycle? (d) What is the work W for the isothermal process? The volume V1 in state 1 is 0.200 m3. What is the volume in (e) state 2 and (f) state 3?
What is the change ΔEint for (g) path 1 → 2, (h) path 2 → 3, and (i) the full cycle? (Hint: (h) can be done with one or two lines of calculation using Module 19-7 or with a page of calculation using Module 19-9.) (j) What is the work W for the adiabatic process?
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d
Ag
= 2.51
dFe
×
Show that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R.
Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [?
v2
v2
A, are equivalent to J/C ✓ X . Therefore, 1
= 1
= 1 A V1 J/s
Ω
V-A X
= 1 W.
. The units for resistance, Q, are equivalent to ?
The units for current,
Please solve and answer the question correctly please. Thank you!!
Human Biology: Concepts and Current Issues (8th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.