Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Chapter 20, Problem 50E
Interpretation Introduction

(a)

Interpretation:

The nuclear bombardment equation ?+H24eC612+n01 by supplying the nuclear symbol for the missing species is to be completed.

Concept introduction:

The nuclear reaction involves the spontaneous emission of particles or radiation due to the breaking or combination of an atomic nucleus. An alpha particle, beta particle and gamma rays are emitted during the radioactive decay. An alpha particle is a helium nucleus. In beta particle emission, an atom emits an electron (e-10).

Expert Solution
Check Mark

Answer to Problem 50E

The complete equation with the nuclear symbol for the missing species B49e is shown below.

B49e+H24eC612+n01.

Explanation of Solution

To complete a nuclear bombardment equation, it is required to count the total number of atomic number and atomic mass in both sides of the equation. An incomplete nuclear bombardment equation is shown below.

?+H24eC612+n01

In the above equation, the identity of the new nuclei is to be determined.

Totalatomicnumberofthereactantspecies=2

Totalatomicnumberoftheproductspecies=6+0=6

Therefore, the atomic number of missing specie is calculated as shown below.

Atomicnumberofmissingnuclei=62=4

Beryllium (Be) has the atomic number of 4.

Totalatomicmassofthereactantspecies=4

Totalatomicmassoftheproductspecies=12+1=13

Therefore, the atomic mass of missing specie is calculated as shown below.

Atomicmassofmissingnuclei=134=9

Therefore, the missing specie is B49e, and the complete equation is shown below.

B49e+H24eC612+n01

Conclusion

The complete equation with the nuclear symbol for the missing species B49e is shown below.

B49e+H24eC612+n01.

Interpretation Introduction

(b)

Interpretation:

The nuclear bombardment equation C48114d+H12?+H11 by supplying the nuclear symbol for the missing species is to be completed.

Concept introduction:

The nuclear reaction involves the spontaneous emission of particles or radiation due to the breaking or combination of an atomic nucleus. An alpha particle, beta particle and gamma rays are emitted during the radioactive decay. An alpha particle is a helium nucleus. In beta particle emission, an atom emits an electron (e-10).

Expert Solution
Check Mark

Answer to Problem 50E

The complete equation with the nuclear symbol for the missing species C48115d is shown below.

C48114d+H12C48115d+H11

Explanation of Solution

To complete a nuclear bombardment equation, it is required to count the total number of atomic number and atomic mass in both sides of the equation. An incomplete nuclear bombardment equation is shown below.

C48114d+H12?+H11

In the above equation, the identity of the new nuclei is to be determined.

Totalatomicnumberofthereactantspecies=48+1=49

Totalatomicnumberoftheproductspecies=1

Therefore, the atomic number of missing specie is calculated as shown below.

Atomicnumberofmissingnuclei=491=48

Cadmium (Cd) has the atomic number of 48.

Totalatomicmassofthereactantspecies=114+2=116

Totalatomicmassoftheproductspecies=1

Therefore, the atomic mass of missing specie is calculated as shown below.

Atomicmassofmissingnuclei=1161=115

Therefore, the missing specie is C48115d, and the complete equation is shown below.

C48114d+H12C48115d+H11

Conclusion

The complete equation with the nuclear symbol for the missing species C48115d is shown below.

C48114d+H12C48115d+H11.

Interpretation Introduction

(c)

Interpretation:

The nuclear bombardment equation U92235+n01?+S3892r+2n01 by supplying the nuclear symbol for the missing species is to be completed.

Concept introduction:

The nuclear reaction involves the spontaneous emission of particles or radiation due to the breaking or combination of an atomic nucleus. An alpha particle, beta particle and gamma rays are emitted during the radioactive decay. An alpha particle is a helium nucleus. In beta particle emission, an atom emits an electron (e-10).

Expert Solution
Check Mark

Answer to Problem 50E

The complete equation with the nuclear symbol for the missing species X54142e is shown below.

U92235+n01X54142e+S3892r+2n01

Explanation of Solution

To complete a nuclear bombardment equation, it is required to count the total number of atomic number and atomic mass in both sides of the equation. An incomplete nuclear bombardment equation is shown below.

U92235+n01?+S3892r+2n01

In the above equation, the identity of new nuclei is to be found.

Totalatomicnumberofthereactantspecies=92+0=92

Totalatomicnumberoftheproductspecies=38+0=38

Therefore, the atomic number of missing specie is calculated as shown below.

Atomicnumberofmissingnuclei=9238=54

Xenon (Xe) has the atomic number of 54.

Totalatomicmassofthereactantspecies=235+1=236

Totalatomicmassoftheproductspecies=92+2×1=94

Therefore, the atomic mass of missing specie is calculated as shown below.

Atomicmassofmissingnuclei=23694=142

Therefore, the missing specie is X54142e, and the complete equation is shown below.

U92235+n01X54142e+S3892r+2n01

Conclusion

The complete equation with the nuclear symbol for the missing species X54142e is shown below.

U92235+n01X54142e+S3892r+2n01

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Chapter 20 Solutions

Introductory Chemistry: An Active Learning Approach

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