EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
6th Edition
ISBN: 9780100547506
Author: CRACOLICE
Publisher: YUZU
Question
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Chapter 20, Problem 49E
Interpretation Introduction

(a)

Interpretation:

The nuclear bombardment equation C2044a+H11?+n01 by supplying the nuclear symbol for the missing species is to be completed.

Concept introduction:

The nuclear reaction involves the spontaneous emission of particles or radiation due to the breaking or combination of an atomic nucleus. An alpha particle, beta particle and gamma rays are emitted during the radioactive decay. An alpha particle is a helium nucleus. In beta particle emission, an atom emits an electron (e-10).

Expert Solution
Check Mark

Answer to Problem 49E

The complete equation with the nuclear symbol for the missing species S2144c is shown below.

C2044a+H11S2144c+n01

Explanation of Solution

To complete a nuclear bombardment equation, it is required to count the total number of atomic number and atomic mass in both sides of the equation. An incomplete nuclear bombardment equation is shown below.

C2044a+H11?+n01

In the above equation, the identity of the new nuclei is to be determined.

Totalatomicnumberofthereactantspecies=20+1=21

Totalatomicnumberoftheproductspecies=0

Therefore, the atomic number of missing specie is calculated as shown below.

Atomicnumberofmissingnuclei=210=21

Scandium (Sc) has the atomic number of 21.

Totalatomicmassofthereactantspecies=44+1=45

Totalatomicmassoftheproductspecies=1

Therefore, the atomic mass of missing specie is calculated as shown below.

Atomicmassofmissingnuclei=451=44

Therefore, the missing species is S2144c, and the complete equation is shown below.

C2044a+H11S2144c+n01

Conclusion

The complete equation with the nuclear symbol for the missing species S2144c is shown below.

C2044a+H11S2144c+n01.

Interpretation Introduction

(b)

Interpretation:

The nuclear bombardment equation C98252f+B5105n01+? by supplying the nuclear symbol for the missing species is to be completed.

Concept introduction:

The nuclear reaction involves the spontaneous emission of particles or radiation due to the breaking or combination of an atomic nucleus. An alpha particle, beta particle and gamma rays are emitted during the radioactive decay. An alpha particle is a helium nucleus. In beta particle emission, an atom emits an electron (e-10).

Expert Solution
Check Mark

Answer to Problem 49E

The complete equation with the nuclear symbol for the missing species L103257r is shown below.

C98252f+B5105n01+L103257r

Explanation of Solution

To complete a nuclear bombardment equation, it is required to count the total number of atomic number and atomic mass in both sides of the equation. An incomplete nuclear bombardment equation is shown below.

C98252f+B5105n01+?

In the above equation, the identity of the new nuclei is to be determined.

Totalatomicnumberofthereactantspecies=98+5=103

Totalatomicnumberoftheproductspecies=5×0=0

Therefore, the atomic number of missing specie is calculated as shown below.

Atomicnumberofmissingnuclei=1030=103

Lawrencium (Lr) has the atomic number of 103.

Totalatomicmassofthereactantspecies=252+10=262

Totalatomicmassoftheproductspecies=5×1=5

Therefore, the atomic mass of missing specie is calculated as shown below.

Atomicmassofmissingnuclei=2625=257

Therefore, the missing specie is L103257r, and the complete equation is shown below.

C98252f+B5105n01+L103257r

Conclusion

The complete equation with the nuclear symbol for the missing species L103257r is shown below.

C98252f+B5105n01+L103257r

Interpretation Introduction

(c)

Interpretation:

The nuclear bombardment equation P46106d+H24eA47109g+? by supplying the nuclear symbol for the missing species is to be completed.

Concept introduction:

The nuclear reaction involves the spontaneous emission of particles or radiation due to the breaking or combination of an atomic nucleus. An alpha particle, beta particle and gamma rays are emitted during the radioactive decay. An alpha particle is a helium nucleus. In beta particle emission, an atom emits an electron (e-10).

Expert Solution
Check Mark

Answer to Problem 49E

The complete equation with the nuclear symbol for the missing species H11 is shown below.

P46106d+H24eA47109g+H11

Explanation of Solution

To complete a nuclear bombardment equation, it is required to count the total number of atomic number and atomic mass in both sides of the equation. An incomplete nuclear bombardment equation is shown below.

P46106d+H24eA47109g+?

In the above equation, the identity of the new nuclei is to be determined.

Totalatomicnumberofthereactantspecies=46+2=48

Totalatomicnumberoftheproductspecies=47

Therefore, the atomic number of missing specie is calculated as shown below.

Atomicnumberofmissingnuclei=4847=1

Hydrogen (H) has the atomic number of 1.

Totalatomicmassofthereactantspecies=106+4=110

Totalatomicmassoftheproductspecies=109

Therefore, the atomic mass of missing specie is calculated as shown below.

Atomicmassofmissingnuclei=110109=1

Therefore, the missing species is H11, and the complete equation is shown below.

P46106d+H24eA47109g+H11

Conclusion

The complete equation with the nuclear symbol for the missing species H11 is shown below.

P46106d+H24eA47109g+H11

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Chapter 20 Solutions

EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L

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