The reaction given below is product-favored or not has to be determined. 2Al(s) + Cr 2 O 3 (s) → 2Cr(s) + Al 2 O 3 (s) Concept Introduction: In order to find whether the reaction is product-favored or not, Δ r G ° value can be used. If the value of Δ r G ° is negative, then the reaction is product-favored and if the value of Δ r G ° is positive, then the reaction is not product-favored. Δ r G ° = ∑ [ ( coefficient of product ) × Δ f G ° ( product ) ] − ∑ [ ( coefficient of reactant ) × Δ f G ° ( r e a c tan t ) ]

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Answer 1

Question

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$

As the value of $ΔrG°$ is negative, the given reaction is product-favored.

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Answer 2

Question

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$

As the value of $ΔrG°$ is negative, the given reaction is product-favored.

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Answer 3

Question

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$

As the value of $ΔrG°$ is negative, the given reaction is product-favored.

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Answer 4

Question

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$

As the value of $ΔrG°$ is negative, the given reaction is product-favored.

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Answer 5

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$

As the value of $ΔrG°$ is negative, the given reaction is product-favored.

Answer 6

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$

As the value of $ΔrG°$ is negative, the given reaction is product-favored.

Answer 7

Chapter 20, Problem 42QRT

Interpretation Introduction

Interpretation:

The reaction given below is product-favored or not has to be determined.

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

Concept Introduction:

In order to find whether the reaction is product-favored or not, $ΔrG°$ value can be used. If the value of $ΔrG°$ is negative, then the reaction is product-favored and if the value of $ΔrG°$ is positive, then the reaction is not product-favored.

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)]$

Answer 8

Expert Solution & Answer

Explanation of Solution

Given reaction is,

$2Al(s) + Cr2O3(s) → 2Cr(s) + Al2O3(s)$

$ΔrG°$ can be calculated as shown below,

$ΔrG° = ∑[(coefficient of product) × ΔfG°(product)] −∑[(coefficient of reactant) × ΔfG°(reactant)] = 2 ΔfG° {Cr(s)} + ΔfG° {Al2O3(s)} − 2 ΔfG° {Al(s)} − ΔfG° {Cr2O3(s)} = 2(0) + (−1528.3 kJ/mol) − 2(0) −(−1058.1 kJ/mol) = −1528.3 kJ/mol + 1058.1 kJ/mol = −470.2 kJ/mol$