EBK HUMAN BIOLOGY
11th Edition
ISBN: 8220100545931
Author: MCMILLAN
Publisher: Cengage Learning US
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Chapter 20, Problem 3RQ
What evidence indicates that a trait is coded by a dominant allele on an autosome?
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In a woman who is a carrier of a mutant OTC deficiency allele, her sons who receive the mutant allele will be affected and her daughters will be carriers who may or may not be symptomatic, depending on random X inactivation in the liver.
1) Is this a single gene inheritance or multifactorial disease?
2) Is there a strong genetic or environmental cause to the development of this disease? If both genetic and environmental causes are implicated, you have to indicate each of them separately.
Please atleast answer this question
Assume that a gene controls the expression of a trait in which affected children occur only in families where one or both parents are also affected; children who are normal may have parents who are (1) both normal, (2) one normal and one affected, or (3) both affected. Is the gene for the affected condition completely dominant, co-dominant, incompletely dominant or recessive?
Chapter 20 Solutions
EBK HUMAN BIOLOGY
Ch. 20 - Prob. 1RQCh. 20 - What is a carrier of a genetic trait?Ch. 20 - What evidence indicates that a trait is coded by a...Ch. 20 - Prob. 4RQCh. 20 - Explain what nondisjunction is, and give two...Ch. 20 - _______ segregate during ______. a. Homologues;...Ch. 20 - Prob. 2SQCh. 20 - Genes on the same chromosome tend to stay together...Ch. 20 - Prob. 4SQCh. 20 - A chromosomes structure can be altered by _______....
Ch. 20 - Nondisjunction can be caused by ________. a....Ch. 20 - A gamete affected by nondisjunction could have...Ch. 20 - Genetic disorders can be caused by __________. a....Ch. 20 - A person who is a carrier for a genetic trait...Ch. 20 - Prob. 10SQCh. 20 - If a couple has six boys, what is the probability...Ch. 20 - Human sex chromosomes are XX for females and XY...Ch. 20 - People with Down syndrome have an extra copy of...Ch. 20 - Prob. 4CTCh. 20 - Prob. 5CTCh. 20 - About 4 percent of people of Northern European...Ch. 20 - The following pedigree shows the pattern of...
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- In rats, the following genotypes of two independently assorting autosomal genes determine coat color: A_B_ (gray); A_bb (yellow); aaB_ (black); aabb (cream). A third gene pair on a separate autosome determines whether or not any color will be produced. The CC and Cc genotypes allow color according to the expression of the A and B alleles. However, the cc genotype results in albino rats regardless of the A and Balleles present. Determine the F1 phenotypic ratio of the following crosses: (a) AAbbCC x aaBBcc; (b) AAbbCC x aaBBcc; (c) AABBCC x AABbcc.arrow_forwardShown below is a karyotype from a human being. How many total autosomes does this individual have? A) 2 B) 44 C) 46 D) 23arrow_forwardHuman females who are heterozygous for an X-linked recessive allele sometimes exhibit mild expression of the trait. However, such mild expression of X-linked traits in females who are heterozygous for Xlinked alleles is not seen in Drosophila. What might cause this difference in the expression of X-linked genes between human females and female Drosophila? (Hint: In Drosophila, dosage compensation is accomplished by doubling the activity of genes on the X chromosome of males.)arrow_forward
- a) Assume that colour is controlled by a single sex-influenced gene where green is expressed preferentially in males. Individuals I-1 and I-2 are homozygous for red and green respectively. Which individual/s in generation II will be red? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be green?arrow_forwardProduce a Punnett square to illustrate the dihybrid cross described below: There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the dominant causative mutation. The mother is homozygous wild type at the same locus. Add a file here showing your diagram.arrow_forwardFor a particular gene, homozygous dominant AA and heterozygous Aa individuals produce green pigment, while homozygous recessive aa individuals produce yellow pigment. During the course of your research you discover the a1 allele that contains a class IlI transposon insertion. Allele A is dominant to a1. Which genotype is capable of producing a mixture of green and yellow pigment?arrow_forward
- Regarding Mendelian inheritance in diploid individuals, (Read each statement carefully. Select all of the statements below that are true (that you agree with). Leave any statements that are false (that you do not agree with) un- selected.) a diploid individual receives two copies of every autosome from the previous generation. for every autosomal gene inherited by an individual, both copies can come from one parent. a diploid individual gives two copies of every autosome to a child in the next generation. to be diploid means that two independent genes are specified in the individual's genotype.arrow_forward1) In the plant Salvia, two genes determine the inheritance of flower colour. For one gene, P is the allele for purple colour and p for pink. However, at least one dominant allele at the other locus is required for the colour to be expressed, Plants with the genotype aa have white flowers. Write down all possible genotypes for a) purple flowered b) pink flowered c) white flowers d) which gene, A/a or P/p is the epistatic gene and which is the hypostatic gene? e) What type of epistasis is this?arrow_forwardIn mice, the trait for high cholesterol is specified by a dominant allele designated HC, whereas the wild-type allele for normal cholesterol levels is designated hc. Black fur is specified by a recessive allele designated bl, whereas the wild-type allele which gives brown fur is designated BL. The genes for both of these traits are 30cM apart on the same autosome. A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. What is the probability that the black mouse in the progeny of the first cross will also have high cholesterol?arrow_forward
- Several loci affect hair development in dogs. The allele for wire hair (W) is dominant to Its allele for straight hair (w). Allow H to represent hairlessness in the Mexican hairless dog and its recessive allele h to represent the gene for typical hair growth in other breeds. The Mexican hairless dog is homozygous for straight hair, but because of epistatic effects of H, alleles for hair formation cannot be expressed. Write genotypes of the following animals with respect to the two loci mentioned. a.) a Mexican hairless dog b.) a dog with straight hair c.) a dog from a strain that is pure breeding for wire hair.arrow_forwardThere are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype Phenotype MM White Mm Half colour (Grey or light red) mm Full colour (Black or Red) Two dogs heterozygous for both traits were crossed. What phenotypic ratio is expected in the F1 generation? Answer: Phenotype: White Grey Black Light Red Redarrow_forwardThere are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype Phenotype MM White Mm Half colour (Grey or light red) mm Full colour (Black or Red) A grey dog that is heterozygous for the eumelanin gene mates with a light red dog. 1. What is the probability they would have a grey puppy? 2. What is the probability they would have a grey or light red puppy?arrow_forward
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