
EBK STARTING OUT WITH C++
8th Edition
ISBN: 8220100794438
Author: GADDIS
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 20, Problem 3PC
Program Plan Intro
Leaf Counter
Program Plan:
Main.cpp:
- Include required header files.
- Inside the “main ()” function,
- Display the number of leaf nodes by calling the function “num_LeafNodes ()”.
- Insert nodes into the binary tree by using the function “insert_Node ()”.
- Display those nodes by using the function “display_InOrder ()”.
- Now, display the number of leaf nodes by calling the function “num_LeafNodes ()”.
- Delete two nodes from the binary tree by using the function “remove ()”.
- Display remaining nodes by using the function “display_InOrder ()”.
- Finally, display the number of leaf nodes by calling the function “num_LeafNodes ()”.
BinaryTree.h:
- Include required header files.
- Create a class template.
- Declare a class named “BinaryTree”. Inside the class,
- Inside the “private” access specifier,
- Give the structure declaration for the creation of node.
- Create an object for the template.
- Create two pointers named “left_Node” and “right_Node” to access the value left and right nodes respectively.
- Declare a variable “leafCount”.
- Create a pointer named “root” to access the value of root node.
- Give function declaration for “insert ()”, “destroy_SubTree ()”, “delete_Node ()”, “make_Deletion ()”, “display_InOrder ()”, “display_PreOrder ()”, “display_PostOrder ()”, “count_Nodes ()”, “count_Leaves ()”.
- Give the structure declaration for the creation of node.
- Inside “public” access specifier,
- Give the definition for constructor and destructor.
- Give function declaration.
- Inside the “private” access specifier,
- Declare template class.
- Give function definition for “insert ()”.
- Check if “nodePtr” is null.
- If the condition is true then, insert node.
- Check if value of new node is less than the value of node pointer
- If the condition is true then, Insert node to the left branch by calling the function “insert ()” recursively.
- Else
- Insert node to the right branch by calling the function “insert ()” recursively.
- Check if “nodePtr” is null.
- Declare template class.
- Give function definition for “insert_Node ()”.
- Create a pointer for new node.
- Assign the value to the new node.
- Make left and right node as null
- Call the function “insert ()” by passing parameters “root” and “newNode”.
- Declare template class.
- Give function definition for “destroy_SubTree ()”.
- Check if the node pointer points to left node
- Call the function recursively to delete the left sub tree.
- Check if the node pointer points to the right node
- Call the function recursively to delete the right sub tree.
- Delete the node pointer.
- Check if the node pointer points to left node
- Declare template class.
- Give function definition for “search_Node ()”.
- Assign false to the Boolean variable “status”.
- Assign root pointer to the “nodePtr”.
- Do until “nodePtr” exists.
- Check if the value of node pointer is equal to “num”.
- Assign true to the Boolean variable “status”
- Check if the number is less than the value of node pointer.
- Assign left node pointer to the node pointer.
- Else
- Assign right node pointer to the node pointer.
- Check if the value of node pointer is equal to “num”.
- Return the Boolean variable.
- Declare template class.
- Give function definition for “remove ()”.
- Call the function “delete_Node ()”
- Declare template class.
- Give function definition for “delete_Node ()”
- Check if the number is less than the node pointer value.
- Call the function “delete_Node ()” recursively.
- Check if the number is greater than the node pointer value.
- Call the function “delete_Node ()” recursively.
- Else,
- Call the function “make_Deletion ()”.
- Check if the number is less than the node pointer value.
- Declare template class.
- Give function definition for “make_Deletion ()”
- Create pointer named “tempPtr”.
- Check if the nodePtr is null.
- If the condition is true then, print “Cannot delete empty node.”
- Check if right node pointer is null.
- If the condition is true then,
- Make the node pointer as the temporary pointer.
- Reattach the left node child.
- Delete temporary pointer.
- If the condition is true then,
- Check is left node pointer is null
- If the condition is true then,
- Make the node pointer as the temporary pointer.
- Reattach the right node child.
- Delete temporary pointer.
- If the condition is true then,
- Else,
- Move right node to temporary pointer
- Reach to the end of left-Node using “while” condition.
- Assign left node pointer to temporary pointer.
- Reattach left node sub tree.
- Make node pointer as the temporary pointer.
- Reattach right node sub tree
- Delete temporary pointer.
- Declare template class.
- Give function definition for “display_InOrder ()”.
- Check if the node pointer exists.
- Call the function “display_InOrder ()” recursively.
- Print the value
- Call the function “display_InOrder ()” recursively.
- Check if the node pointer exists.
- Declare template class.
- Give function definition for “display_PreOrder ()”.
- Print the value.
- Call the function “display_PreOrder ()” recursively.
- Call the function “display_PreOrder ()” recursively.
- Declare template class.
- Give function definition for “display_PostOrder ()”.
- Call the function “display_PostOrder ()” recursively.
- Call the function “display_PostOrder ()” recursively.
- Print value
- Declare template class.
- Give function definition for “numNodes ()”.
- Call the function “count_Nodes ()”.
- Declare template class.
- Give function definition for “count_Nodes ()”.
- Declare a variable named “count”.
- Check if the node pointer is null
- Assign 0 to count.
- Else,
- Call the function “count_Nodes ()” recursively.
- Return the variable “count”.
- Declare template class.
- Give function definition for “num_LeafNodes()”.
- Assign 0 to “leafCount”
- Call the function “count_Leaves ()”
- Return the variable.
- Declare template class.
- Give function definition for “count_Leaves()”.
- Call the function “count_Leaves ()” recursively by passing left node pointer as the parameter.
- Call the function “count_Leaves ()” recursively by passing right node pointer as the parameter.
- Check if left and right node pointers are null.
- Increment the variable “leafCount”.
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Whats wrong with my pseudocode? Where did I make an error?Code:
Module main()
Declare Real mileage
Call getMileage()
Display “You’ve drive a total of “, mileage, “ miles
End Module
Module getMilage() Display “Enter your mileage: “
Input mileage
End Module
I need help!! Writing a long pseudocode for a modular program that will display the monthly payment on a mortgage. P=Principal amount borrowed (loan)R=Rate of interest computed for each monthN=Number of months to pay back the loan or mortgageThe help I need is creating a module that you can input the principle, rate of percentage, and years to repay the loan, and another module "displaypayment" that accepts the 3 values and calculates the monthly payment needed for the rates. Lastly 2 local variables needed!Equation:Monthly Payment=[(R*(1+R)^N)/((1+R)^N-1)]*P
Two pseudocode questions I need help with: How do I design a module called findSum that will display the sum of two integer passed by parameter, and a module called findArea that will display the area of a rectangle when passed 2 real values for the length and width of the rectangle?
Chapter 20 Solutions
EBK STARTING OUT WITH C++
Ch. 20.1 - Prob. 21.1CPCh. 20.1 - Prob. 21.2CPCh. 20.1 - Prob. 21.3CPCh. 20.1 - Prob. 21.4CPCh. 20.1 - Prob. 21.5CPCh. 20.1 - Prob. 21.6CPCh. 20.2 - Prob. 21.7CPCh. 20.2 - Prob. 21.8CPCh. 20.2 - Prob. 21.9CPCh. 20.2 - Prob. 21.10CP
Ch. 20.2 - Prob. 21.11CPCh. 20.2 - Prob. 21.12CPCh. 20 - Prob. 1RQECh. 20 - Prob. 2RQECh. 20 - Prob. 3RQECh. 20 - Prob. 4RQECh. 20 - Prob. 5RQECh. 20 - Prob. 6RQECh. 20 - Prob. 7RQECh. 20 - Prob. 8RQECh. 20 - Prob. 9RQECh. 20 - Prob. 10RQECh. 20 - Prob. 11RQECh. 20 - Prob. 12RQECh. 20 - Prob. 13RQECh. 20 - Prob. 14RQECh. 20 - Prob. 15RQECh. 20 - Prob. 16RQECh. 20 - Prob. 17RQECh. 20 - Prob. 18RQECh. 20 - Prob. 19RQECh. 20 - Prob. 20RQECh. 20 - Prob. 21RQECh. 20 - Prob. 22RQECh. 20 - Prob. 23RQECh. 20 - Prob. 24RQECh. 20 - Prob. 25RQECh. 20 - Prob. 1PCCh. 20 - Prob. 2PCCh. 20 - Prob. 3PCCh. 20 - Prob. 4PCCh. 20 - Prob. 5PCCh. 20 - Prob. 6PCCh. 20 - Prob. 7PCCh. 20 - Prob. 8PC
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- For the pseudocode module, what is displayed with the call findValue(1, 4, 2)?Module findValue(Integer a, Integer b, Integer c) Declare Integer value value = b + c - a Display valuearrow_forwardI need help finishing my python rock paper scissors code, where it asks the user "rock, paper, scissors", the user types either option (repeatedly asks until its one of the three), and for a random option from the code to select also rock paper scissors. The end result would be you winning, code winning, or a tie.My code:import randomOPTIONS = ("ROCK", "PAPER", "SCISSOR") def getInput(): """ Function getInput() will receive and validate user input to be the string ROCK, PAPER, or SCISSOR. Input must be spelled correctly and in all capital letters. Function will return the validated input @return user input as ROCK, PAPER, OR SCISSOR """ #need help here def checkWinner(user, computer): """ Function checkWinner will accept 2 string parameters that must be unique values of ROCK, PAPER, or SCISSOR. Functions should return true if the string in parameter user beats the string in parameter computer in a game of rock…arrow_forwardI need help understanding how could I got the IP Address for the 1st Host on this Subnet, the IP Address for the Last Host on this Subnet & the Broadcast Address for this Subnet My Explanation:8 bits --> 17 & 0 128 64 32 16 | 8 4 2 1 0 0 0 1 0 0 0 1 -->17+ 0 0 0 0 0 0 0 0 --> 0 0 0 0 0 0 0 0 0 --> 0 (The Major (Base) Network Address): 142.20.33.0 To find the broadcast address, we can set all the bits in the host portion of the address to 1, which gives us 142.20.33.255. Based on the subnet mask 255.255.255.0, no bits were borrowed from the host portion, meaning 8 bits remain in the host portion. Using the formula 2^h – 2 (where h represents the number of host bits), we get 2^8 - 2 = 254 hosts. 8 bits --> 17 & 252 128 64 32 16 | 8 4 2 1 0 0 0 1 0 0 0 1 --> 17+ 1 1 1 1 1 1 0 0 --> 252 0 0 0 1…arrow_forward
- Which of the following opens when you click the launcher in the Size group on the Ribbon? Question 19Select one: a. Size dialog box b. Layout dialog box c. Width and Height dialog box d. Format dialog boxarrow_forwardHow do you resize a graphic object horizontally while keeping the center position fixed? Question 20Select one: a. Drag a side sizing handle. b. Press [Ctrl] and drag a side sizing handle. c. Press [Alt] and drag a side sizing handle. d. Press [Shift] and drag a side sizing handle.arrow_forwardWhich of the following indicates that a graphic is anchored to the nearest paragraph? Question 18Select one: a. X and Y coordinates b. An anchor symbol c. A paragraph symbol d. ruler marksarrow_forward
- Which command in the Adjust group allows you to change one picture for another but retain the original picture's size and formatting? Question 17Select one: a. Change Picture b. Replace c. Swap d. Relinkarrow_forwardHow do you insert multiple rows at the same time? Question 10Select one: a. Select the number of rows you want to insert, then use an Insert Control or use the buttons on the Ribbon. b. Click Insert Multiple Rows in the Rows & Columns group. c. Select one row and click the Insert Above or Insert Below button. You will be prompted to choose how many rows to insert. d. You cannot insert multiple rows at the same time.arrow_forwardHow do you center the text vertically in each table cell? Question 9Select one: a. Select the table and click the Distribute Columns button. b. Select the table and click the Center button in the Paragraph group on the Home tab. c. Select the table and click the AutoFit button. d. Click the Select button in the Table group, click Select Table, then click the Align Center Left button in the Alignment group.arrow_forward
- A(n) ____ is a box formed by the intersection of a column and a row. Question 8Select one: a. divider b. table c. border d. cellarrow_forwardA ____ row is the first row of a table that contains the column headings. Question 7Select one: a. header b. primary c. title d. headingarrow_forwardThe Horse table has the following columns: ID - integer, auto increment, primary key RegisteredName - variable-length string Breed - variable-length string Height - decimal number BirthDate - date Delete the following rows: Horse with ID 5 All horses with breed Holsteiner or Paint All horses born before March 13, 2013 To confirm that the deletes are correct, add the SELECT * FROM HORSE; statement.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- C++ Programming: From Problem Analysis to Program...Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage LearningNew Perspectives on HTML5, CSS3, and JavaScriptComputer ScienceISBN:9781305503922Author:Patrick M. CareyPublisher:Cengage LearningEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT
- Programming Logic & Design ComprehensiveComputer ScienceISBN:9781337669405Author:FARRELLPublisher:CengageC++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology PtrMicrosoft Visual C#Computer ScienceISBN:9781337102100Author:Joyce, Farrell.Publisher:Cengage Learning,

C++ Programming: From Problem Analysis to Program...
Computer Science
ISBN:9781337102087
Author:D. S. Malik
Publisher:Cengage Learning

New Perspectives on HTML5, CSS3, and JavaScript
Computer Science
ISBN:9781305503922
Author:Patrick M. Carey
Publisher:Cengage Learning

EBK JAVA PROGRAMMING
Computer Science
ISBN:9781337671385
Author:FARRELL
Publisher:CENGAGE LEARNING - CONSIGNMENT
Programming Logic & Design Comprehensive
Computer Science
ISBN:9781337669405
Author:FARRELL
Publisher:Cengage

C++ for Engineers and Scientists
Computer Science
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Course Technology Ptr

Microsoft Visual C#
Computer Science
ISBN:9781337102100
Author:Joyce, Farrell.
Publisher:Cengage Learning,