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Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
For
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
- 1. Chiral center: Chiral molecules contain at least one carbon atom with four non-identical substitutions (or) groups this type of molecule is called a chiral center.
- 2. Constitutional Isomers: The compounds that have the same molecular formula but different in their chemical structures.
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Chapter 20 Solutions
Organic Chemistry, 3e WileyPLUS Registration Card + Loose-leaf Print Companion
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- Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 IZ IN Molecule 4 Molecule 5 ZI none of the above ☐ Molecule 3 Х IN www Molecule 6 NH Garrow_forwardHighlight each chiral center in the following molecule. If there are none, then check the box under the drawing area. There are no chiral centers. Cl Cl Highlightarrow_forwardA student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ பarrow_forward
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- NG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardShow work...don't give Ai generated solutionarrow_forward
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