General Physics, 2nd Edition
General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
Question
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Chapter 20, Problem 38E

(a)

To determine

The inductance of the coil.

(a)

Expert Solution
Check Mark

Answer to Problem 38E

The inductance of the coil is 394.78H.

Explanation of Solution

Write the expression for the inductance in a coil.

    L=4πkmkn2Al        (1)

Here, L is the inductance, km is the magnetic constant, k is a constant, n is the number of turns per unit length, A is the area of the coil and l is the length.

Substitute (πr2) for A and (Nl) for n in equation (1).

    L=4πkmk(Nl)2(πr2)l        (2)

Here, N is the number of turns of the coil and r is the radius of the coil.

Conclusion:

Substitute 1 for km, (107TmA-1) for k, 1000 for N, 10m for l and 100m for r in equation (2).

    L=4π(1)((107TmA-1))(1000100m)2(π(100m)2)(100m)=394.78H

Thus, the inductance of the coil is 394.78H.

(b)

To determine

The energy stored in the coil

(b)

Expert Solution
Check Mark

Answer to Problem 38E

The energy is 4.4×1012J.

Explanation of Solution

Write the expression for the energy stored in the coil.

    U=12Li2        (3)

Here, U is the energy, L is the inductance and i is the current.

Conclusion:

Substitute 394.78H for L and 1.5×105A for i in equation (3).

    U=12(394.78H)(1.5×105A)2=4.4×1012J

Thus, the energy is 4.4×1012J.

(c)

To determine

The time for supply the energy to the power plant.

(c)

Expert Solution
Check Mark

Answer to Problem 38E

The time required to supply the power is 4.4×103s.

Explanation of Solution

Write the expression for the power.

    U=Pt.

Here, U is the energy, P is the power and t is the time.

Rearrange the above equation to find the required time.

    t=UP        (4)

Conclusion:

Substitute 4.4×1012J for U and 109W for P in equation (4).

    t=4.4×1012J109W=4.4×103s

Thus, the time required to supply the power is 4.4×103s.

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Chapter 20 Solutions

General Physics, 2nd Edition

Ch. 20 - Prob. 11RQCh. 20 - Prob. 12RQCh. 20 - Prob. 13RQCh. 20 - Prob. 1ECh. 20 - Prob. 2ECh. 20 - Prob. 3ECh. 20 - Prob. 4ECh. 20 - Prob. 5ECh. 20 - Prob. 6ECh. 20 - Prob. 7ECh. 20 - Prob. 8ECh. 20 - Prob. 9ECh. 20 - Prob. 10ECh. 20 - Prob. 11ECh. 20 - Prob. 12ECh. 20 - Prob. 13ECh. 20 - Prob. 14ECh. 20 - Prob. 15ECh. 20 - Prob. 16ECh. 20 - Prob. 17ECh. 20 - Prob. 18ECh. 20 - Prob. 19ECh. 20 - Prob. 20ECh. 20 - Prob. 21ECh. 20 - Prob. 22ECh. 20 - Prob. 23ECh. 20 - Prob. 24ECh. 20 - Prob. 25ECh. 20 - Prob. 26ECh. 20 - Prob. 27ECh. 20 - Prob. 28ECh. 20 - Prob. 29ECh. 20 - Prob. 30ECh. 20 - Prob. 31ECh. 20 - Prob. 32ECh. 20 - Prob. 33ECh. 20 - Prob. 34ECh. 20 - Prob. 35ECh. 20 - Prob. 36ECh. 20 - Prob. 37ECh. 20 - Prob. 38ECh. 20 - Prob. 39ECh. 20 - Prob. 40ECh. 20 - Prob. 41ECh. 20 - Prob. 42ECh. 20 - Prob. 43ECh. 20 - Prob. 44ECh. 20 - Prob. 45ECh. 20 - Prob. 46ECh. 20 - Prob. 47ECh. 20 - Prob. 48ECh. 20 - Prob. 49ECh. 20 - Prob. 50ECh. 20 - Prob. 51ECh. 20 - Prob. 52ECh. 20 - Prob. 53ECh. 20 - Prob. 54ECh. 20 - Prob. 55ECh. 20 - Prob. 56ECh. 20 - Prob. 57ECh. 20 - Prob. 58ECh. 20 - Prob. 59ECh. 20 - Prob. 60ECh. 20 - Prob. 61ECh. 20 - Prob. 62ECh. 20 - Prob. 63ECh. 20 - Prob. 64ECh. 20 - Prob. 65ECh. 20 - Prob. 66ECh. 20 - Prob. 67ECh. 20 - Prob. 68ECh. 20 - Prob. 69ECh. 20 - Prob. 70ECh. 20 - Prob. 71ECh. 20 - Prob. 72ECh. 20 - Prob. 73ECh. 20 - Prob. 74ECh. 20 - Prob. 75ECh. 20 - Prob. 76ECh. 20 - Prob. 77ECh. 20 - Prob. 78ECh. 20 - Prob. 79ECh. 20 - Prob. 80ECh. 20 - Prob. 81ECh. 20 - Prob. 82ECh. 20 - Prob. 83ECh. 20 - Prob. 84ECh. 20 - Prob. 85ECh. 20 - Prob. 86ECh. 20 - Prob. 87ECh. 20 - Prob. 88ECh. 20 - Prob. 89ECh. 20 - Prob. 90ECh. 20 - Prob. 91ECh. 20 - Prob. 92ECh. 20 - Prob. 93ECh. 20 - Prob. 94ECh. 20 - Prob. 95E
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