Engineering Fundamentals
6th Edition
ISBN: 9780357112144
Author: Saeed Moaveni
Publisher: MISC PUBS
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Chapter 20, Problem 24P
To determine
Check whether the company will invest in the project or not.
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For the tower shown in Figure (2), check the
suitability of the proposed piled foundation with
the following infiormation: (minimum safety factor
against failure is (2). (neglect the group action), (V
- 2250 kN, including pile cap weight) and (M
4500 kN.m), the pile group consists of one central
the
distributed
and eight piles
circumference of a (6 m) diameter circle ( 45 )
degrees appart}.
pile
on
=
1 m
8 m diameter cap
20 m
Figure (2)
10 m
M
0.5 m diameter bored pile
-30 kPa.
y= 19 kN/m²
Gs-2,7
Sand
Clay
A group of nine piles, 12 m long and 250 mm in diameter, is to be arrenged in a square form in clay
soil with an average unconfined compressive strength of 60 kN/m². Work out the center to center
spacing of the piles for a group effeciency factor of 1. Neglect bearing at the tip of the piles.
Determine the allowable pile load
capacity of the 40 cm diameter driven
concrete pile shown in the Figure (1).
W.T.
Figure (1)
K=1
6=0.750
3 m
6 m
K = 2
6=0.750
5 m
Loose sand
Y₁ = 16 kN/m², '= 30°
Soft clay
Year = 18 kN/m,
2
C= 15 kN/m²
Dense sand
Ysat = 20 kN/m²,
-40°
Chapter 20 Solutions
Engineering Fundamentals
Ch. 20.4 - Prob. 1BYGCh. 20.4 - Prob. 2BYGCh. 20.4 - Prob. 3BYGCh. 20.4 - Prob. 4BYGCh. 20.4 - Prob. 5BYGCh. 20.4 - Prob. BYGVCh. 20.5 - Prob. 1BYGCh. 20.5 - Prob. 2BYGCh. 20.5 - Prob. 3BYGCh. 20.5 - Prob. BYGV
Ch. 20.8 - Prob. 1BYGCh. 20.8 - Prob. 2BYGCh. 20.8 - Prob. 3BYGCh. 20 - Prob. 1PCh. 20 - Prob. 2PCh. 20 - Prob. 3PCh. 20 - Prob. 4PCh. 20 - Prob. 5PCh. 20 - Prob. 6PCh. 20 - Prob. 7PCh. 20 - Prob. 8PCh. 20 - Prob. 9PCh. 20 - Prob. 10PCh. 20 - Prob. 11PCh. 20 - Prob. 12PCh. 20 - Prob. 13PCh. 20 - Prob. 14PCh. 20 - Prob. 15PCh. 20 - Prob. 16PCh. 20 - Prob. 17PCh. 20 - Prob. 18PCh. 20 - Prob. 19PCh. 20 - Prob. 20PCh. 20 - Prob. 21PCh. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - Prob. 50PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54P
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- = The allowable working load on a prestressed concrete pile 21-m long that has been driven 356 mm (see Table 9.3a). into sand is 502 kN. The pile is octagonal in shape with D Skin resistance carries 350 kN of the allowable load, and point bearing carries the rest. Use E, = 21 x 10° kN/m², E, = 25 x 103 kN/m², p, 0.35, and = 0.62. Determine the settlement of the pile. ==arrow_forwardH.W.5: A beam section is limited to a width of 300 mm, and total depth h=500 mm, and has to resist a factored moment 405 kN.m.Calculate the required reinforcement, given f'c=28 MPa, fy=420 MPa. (As=6425mm, As'=2425 mm Ans)arrow_forwardH.W.1: A rectangular beam has a width of 300 mm, and effective depth d=570 mm to centroid of tension steel bars. Tension steel reinforcement consist of 6628mm in two rows, compression reinforcement of 2022mm. Calculate the design moment strength of the beam, where f'c=28 MPa, fy=420 MPa. (Mu=822 kN.m Ans)arrow_forward
- H.W.4: A beam section is limited to a width of 250 mm, and total depth h=550 mm, and has to resist a factored moment 307 kN.m.Calculate the required reinforcement, given f'c=21 MPa, fy=350 MPa, d'=65mm. (As=5425mm, As'=2022 mm Ans) HW5 A beam section is limited to a width of 300 mm and total denth h-500 mm and has to resistarrow_forwardH.W.3: A rectangular beam has a width of 400 mm, and effective depth d=700 mm to centroid of tension steel bars. Tension steel reinforcement consist of 4036mm in two rows, compression reinforcement of 2622mm. Calculate the design moment strength of the beam, where f'c=21 MPa, fy=420 MPa, d'=65mm. (Mu=927 kN.m Ans)arrow_forwardH.W.4: A beam section is limited to a width of 250 mm, and total depth h=550 mm, and has to resist a factored moment 307 kN.m.Calculate the required reinforcement, given f'c=21 MPa, fy=350 MPa, d'=65mm. (As=5425mm, As'=2422 mm Ans)arrow_forward
- H.W.6: Design the steel reinforcement for flexural for the beam shown in the fig. below. Given f'c=28 MPa, fy=420 MPa. D.L 100 kN/m L.L=200 kN 3 m 3 m 600 mm- A =? 300 mm.arrow_forwardThe tension member shown in the figure below must resist a service dead load of 60 kips and a service live load of 45 kips. Does the member have enough strength? The steel is A588: Fy = 50 ksi, F₁ = 70 ksi; and the bolts are 11/8 inches in diameter. Assume that A = An PL 38 x 72 оо a. Use LRFD. Determine the design strength and the factored load. Make a conclusion about the member. (Express your answers to three significant figures.) +Pn Pu = = kips kips -Select- b. Use ASD. Determine the allowable strength and required strength. Make a conclusion about the member. (Express your answers to three significant figures.) Ft Ae = P₁ = -Select- kips kipsarrow_forwardA single-angle tension member of A36 steel must resist a dead load of 49 kips and a live load of 84 kips. The length of the member is 18 feet, and it will be connected with a single line of 1-inch-diameter bolts, as shown in the figure below. There will be four or more bolts in this line. For the steel Fy = 36 ksi and F₁ = 58 ksi. Try the tension members given in the table below. Tension member 4, (in.) rz (in.) 7 L6 × 6 × 9.75 1.17 8 L 5 × 3 × 4.93 0.746 L 5 × 3 × 5 2.56 0.758 16 7 L5 × 3 × 3.31 0.644 16 Bolt line a. Select a single-angle tension member to resist the loads. Use LRFD. A) L 6 × 6 × B) L 5 × 3 × CL5×3× D) L 5 × 3 × -Select- 5 16 7 16 What is the required gross area? (Express your answer to three significant figures.) A₁ = in.² What is the required effective area? (Express your answer to three significant figures.) A = in.2 What is the minimum radius of gyration? (Express your answer to three significant figures.) "min = in. b. Select a single-angle tension member to…arrow_forward
- An L6 × 4 × 5/8 tension member of A36 steel is connected to a gusset plate with 1-inch-diameter bolts, as shown in the figure below. It is subjected to the following service loads: dead load = 40 kips, live load = 100 kips, and wind load = 45 kips. Use the equation for U: U = 1 − For A36 steel: Fy = 36 ksi, F = 58 ksi. x l For L6 × 4×5/8: Ag = 5.86 in.², x = 1.03 in. 21/4" L6 × 4 × 5/8 11/2" 21/2" 11/2" a. Determine whether this member is adequate using LRFD. -Select- What is the design strength for LFRD? (Express your answer to three significant figures.) Φι Ρη - = kips Which AISC load combination controls? -Select- What is the controlling AISC load combination? (Express your answer to three significant figures.) Pu = kips b. Determine whether this member is adequate using ASD. -Select- What is the allowable strength for ASD? (Express your answer to three significant figures.) Pn Sit kips Which ASD load combination controls? -Select- What is the controlling ASD load combination?…arrow_forwardA double-angle shape, 2L7 × 4 × 5/8, is used as a tension member. The two angles are connected to a gusset plate with 7/8-inch-diameter bolts through the 7-inch legs, as shown in the figure below. A572 Grade 50 steel is used: Fy Fu = 65 ksi. Suppose that t = 5/8 in. = 50 ksi, For L7 x 4 x 5/8: Ag = 6.5 in.², x = 0.958 in. 21/2" оо 11/2" 2L7 x 4 x t a. Compute the design strength. (Express your answer to three significant figures.) ФЕРП = kips b. Compute the allowable strength. (Express your answer to three significant figures.) 'n Sit = kipsarrow_forwardI really need help on barrow_forward
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