CHEMISTRY W/WRKBK AND SMARTWORK (LL)
CHEMISTRY W/WRKBK AND SMARTWORK (LL)
5th Edition
ISBN: 9780393693447
Author: Gilbert
Publisher: NORTON
bartleby

Concept explainers

Question
Book Icon
Chapter 20, Problem 20.69QP

(a)

Interpretation Introduction

Interpretation: The questions based on the Table 20.4 are to be answered.

Concept introduction: Fats are the biomolecular compounds which are also known as triglycerides or lipids. It is one of the important macro nutrient found in our blood. Polyunsaturated triglycerides are the compounds comprises of double or triple bonds between the carbons.

Triglycerides are the tri-esters of fatty acid and glycerol. It is formed by the addition of glycerol with three fatty acids. Glycerol molecule comprises of three hydroxyl (OH) groups. All lipids are water insoluble. These are the store houses of energy in the body. The fatty acids are of both types that are saturated and unsaturated. The unsaturated fatty acids are those which contain one or more CH=CH double bonds in their chain.

To determine: The fat that consume more hydrogen in 1.0kg of oleic acid or 0.50kg of α linolenic acid.

(a)

Expert Solution
Check Mark

Answer to Problem 20.69QP

Solution

The fat that consumes more hydrogen is 0.50kg of α linolenic acid.

Explanation of Solution

Explanation

The consumption of hydrogen is decided by the number of double or triple bonds. The molecular structure of oleic acid is given by following figure,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 20, Problem 20.69QP , additional homework tip  1

Figure 1

This contains a double bond at the carbon position 9 . From the molecular formula it is clear that for saturation of 18 carbons 36 hydrogen atoms are required. It means for saturation one molecule of hydrogen is required. In the molecular hydrogen form carbon –hydrogen ratio is represented as,

18:181:1

This ratio indicates that for one mole carbon one mole of hydrogen is required. Then in the given oleic acid compound one mole hydrogen is required to make it saturated.

The given mass of oleic acid is 1kg that is 1000g . The number of moles is calculated by the formula,

Numberofmoles=GivenmassMolarmass

Substitute the values in the above formula.

Numberofmoles=GivenmassMolarmass=1000g282g/mol=3.55mol

Calculated moles of carbon are 3.55 . Therefore, required moles of hydrogen is calculated as,

3.55×1=3.55mol

The molecular structure of α linolenic acid is given by following figure,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 20, Problem 20.69QP , additional homework tip  2

Figure 2

This contains three double bonds at the carbon positions 9,12,15 . From the molecular formula it is clear that for saturation of 18 carbons 36 hydrogen atoms are required. It means for saturation one molecule of hydrogen is required. In the molecular hydrogen form carbon –hydrogen ratio is represented as,

18:181:1

This ratio indicates that for one mole carbon one mole of hydrogen is required. Then in the given α linolenic acid compound three moles of hydrogen is required to make it saturated.

The given mass of oleic acid is 0.50kg that is 500g . The number of moles is calculated by the formula,

Numberofmoles=GivenmassMolarmass

Substitute the values in the above formula.

Numberofmoles=GivenmassMolarmass=500g278g/mol=1.78mol

Calculated moles of carbon are 1.78 . Therefore, required moles of hydrogen is calculated as,

1.78×3=5.34mol

From the calculated value of moles of hydrogen it is clear that 0.50kg of α linolenic acid consumes more hydrogen than 1.0kg of oleic acid.

(b)

Interpretation Introduction

To determine: The distinction between the two fatty acids; an explanation regarding the answer.

(b)

Expert Solution
Check Mark

Answer to Problem 20.69QP

Solution

The distinction between the two fatty acids has been explained below.

Explanation of Solution

Explanation

The required moles of hydrogen for the two fatty acids are calculated in the part (a). On that basis the two fatty acids can be distinguished.

The hydrogenation reaction of α linolenic acid as well as oleic acid is given in the following figure.

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 20, Problem 20.69QP , additional homework tip  3

Figure 3

The above Figure 3 clearly explains the distinction between two fatty acids by determining the identity of their hydrogenation products.

Conclusion

  1. a) The fat that consumes more hydrogen is 0.50kg of α linolenic acid.
  2. b) The distinction between the two fatty acids has been explained

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Protecting Groups and Carbonyls 6) The synthesis generates allethrolone that exhibits high insect toxicity but low mammalian toxicity. They are used in pet shampoo, human lice shampoo, and industrial sprays for insects and mosquitos. Propose detailed mechanistic steps to generate the allethrolone label the different types of reagents (Grignard, acid/base protonation, acid/base deprotonation, reduction, oxidation, witting, aldol condensation, Robinson annulation, etc.) III + VI HS HS H+ CH,CH,Li III I II IV CI + P(Ph)3 V ༼ Hint: no strong base added VI S VII IX HO VIII -MgBr HgCl2,HgO HO. isomerization aqeuous solution H,SO, ༽༽༤༽༽ X MeOH Hint: enhances selectivity for reaction at the S X ☑
Draw the complete mechanism for the acid-catalyzed hydration of this alkene. esc 田 Explanation Check 1 888 Q A slock Add/Remove step Q F4 F5 F6 A བྲA F7 $ % 5 @ 4 2 3 & 6 87 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce W E R T Y U S D LL G H IK DD 요 F8 F9 F10 F1 * ( 8 9 0 O P J K L Z X C V B N M H He command
Explanation Check F1 H₂O H₂ Pd 1) MCPBA 2) H3O+ 1) Hg(OAc)2, H₂O 2) NaBH4 OH CI OH OH OH hydration halohydrin formation addition halogenation hydrogenation inhalation hydrogenation hydration ☐ halohydrin formation addition halogenation formation chelation hydrogenation halohydrin formation substitution hydration halogenation addition Ohalohydrin formation subtraction halogenation addition hydrogenation hydration F2 80 F3 σ F4 F5 F6 1 ! 2 # 3 $ 4 % 05 Q W & Å © 2025 McGraw Hill LLC. All Rights Reserved. F7 F8 ( 6 7 8 9 LU E R T Y U A F9

Chapter 20 Solutions

CHEMISTRY W/WRKBK AND SMARTWORK (LL)

Ch. 20 - Prob. 20.3VPCh. 20 - Prob. 20.4VPCh. 20 - Prob. 20.5VPCh. 20 - Prob. 20.6VPCh. 20 - Prob. 20.7VPCh. 20 - Prob. 20.8VPCh. 20 - Prob. 20.9VPCh. 20 - Prob. 20.10VPCh. 20 - Prob. 20.11QPCh. 20 - Prob. 20.12QPCh. 20 - Prob. 20.13QPCh. 20 - Prob. 20.14QPCh. 20 - Prob. 20.15QPCh. 20 - Prob. 20.16QPCh. 20 - Prob. 20.17QPCh. 20 - Prob. 20.18QPCh. 20 - Prob. 20.19QPCh. 20 - Prob. 20.20QPCh. 20 - Prob. 20.21QPCh. 20 - Prob. 20.22QPCh. 20 - Prob. 20.23QPCh. 20 - Prob. 20.24QPCh. 20 - Prob. 20.25QPCh. 20 - Prob. 20.26QPCh. 20 - Prob. 20.27QPCh. 20 - Prob. 20.28QPCh. 20 - Prob. 20.29QPCh. 20 - Prob. 20.30QPCh. 20 - Prob. 20.31QPCh. 20 - Prob. 20.32QPCh. 20 - Prob. 20.33QPCh. 20 - Prob. 20.34QPCh. 20 - Prob. 20.35QPCh. 20 - Prob. 20.36QPCh. 20 - Prob. 20.37QPCh. 20 - Prob. 20.38QPCh. 20 - Prob. 20.39QPCh. 20 - Prob. 20.40QPCh. 20 - Prob. 20.41QPCh. 20 - Prob. 20.42QPCh. 20 - Prob. 20.43QPCh. 20 - Prob. 20.44QPCh. 20 - Prob. 20.45QPCh. 20 - Prob. 20.46QPCh. 20 - Prob. 20.47QPCh. 20 - Prob. 20.48QPCh. 20 - Prob. 20.49QPCh. 20 - Prob. 20.50QPCh. 20 - Prob. 20.51QPCh. 20 - Prob. 20.52QPCh. 20 - Prob. 20.53QPCh. 20 - Prob. 20.54QPCh. 20 - Prob. 20.55QPCh. 20 - Prob. 20.56QPCh. 20 - Prob. 20.57QPCh. 20 - Prob. 20.58QPCh. 20 - Prob. 20.59QPCh. 20 - Prob. 20.60QPCh. 20 - Prob. 20.61QPCh. 20 - Prob. 20.62QPCh. 20 - Prob. 20.63QPCh. 20 - Prob. 20.64QPCh. 20 - Prob. 20.65QPCh. 20 - Prob. 20.66QPCh. 20 - Prob. 20.67QPCh. 20 - Prob. 20.68QPCh. 20 - Prob. 20.69QPCh. 20 - Prob. 20.70QPCh. 20 - Prob. 20.71QPCh. 20 - Prob. 20.72QPCh. 20 - Prob. 20.73QPCh. 20 - Prob. 20.74QPCh. 20 - Prob. 20.75QPCh. 20 - Prob. 20.76QPCh. 20 - Prob. 20.77QPCh. 20 - Prob. 20.78QPCh. 20 - Prob. 20.79QPCh. 20 - Prob. 20.80QPCh. 20 - Prob. 20.81APCh. 20 - Prob. 20.82APCh. 20 - Prob. 20.83APCh. 20 - Prob. 20.84APCh. 20 - Prob. 20.85APCh. 20 - Prob. 20.86APCh. 20 - Prob. 20.87APCh. 20 - Prob. 20.88APCh. 20 - Prob. 20.89APCh. 20 - Prob. 20.90APCh. 20 - Prob. 20.91APCh. 20 - Prob. 20.92APCh. 20 - Prob. 20.93APCh. 20 - Prob. 20.94APCh. 20 - Prob. 20.95APCh. 20 - Prob. 20.96APCh. 20 - Prob. 20.97APCh. 20 - Prob. 20.98APCh. 20 - Prob. 20.99APCh. 20 - Prob. 20.100AP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY