Bundle: Chemistry For Today: General, Organic, And Biochemistry, 9th + Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card
Bundle: Chemistry For Today: General, Organic, And Biochemistry, 9th + Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card
9th Edition
ISBN: 9781337580632
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 20, Problem 20.53E
Interpretation Introduction

(a)

Interpretation:

The change in the concentration of hydrogen ions is to be calculated.

Concept introduction:

The concentration of hydrogen ion is calculated by the value of pH of the solution. The change in the concentration of hydrogen ion is calculated by the difference between the initial and final concentration of hydrogen ions present in the solution.

Expert Solution
Check Mark

Answer to Problem 20.53E

The change in the hydrogen ion concentration is 9×107.

Explanation of Solution

The concentration of hydrogen ions in a solution is calculated by the following formula.

[H+]=1×10pH…(1)

It is given that the initial pH of substrate solution is 7.0.

Substitute the value of initial pH in equation (1).

[H+]=1×107

Therefore, the initial concentration of hydrogen ions are 1×107.

It is given that the pH of solution after 1min is 6.0.

Substitute the value of initial pH in equation (1).

[H+]=1×106

Therefore, the final concentration of hydrogen ions are 1×106.

The change in the concentration of hydrogen ion is calculated by the following formula.

Changeinconcentration=(FinalconcentrationofhydrogenionsInitialconcentraionofhydrogenions)

The initial concentration of hydrogen ions are 1×107.

The final concentration of hydrogen ions are 1×106.

Substitute the value of initial and final concentration of hydrogen ions in the above equation.

Changeinconcentration=(1×1061×107)=107(101)=9×107

Therefore, the change in the hydrogen ion concentration is 9×107.

Conclusion

The change in the hydrogen ion concentration is 9×107.

Interpretation Introduction

(b)

Interpretation:

The number of molecules of substrate reacted to cause the change in hydrogen ion concentration is to be calculated.

Concept introduction:

The concentration of hydrogen ion is calculated by the value of pH of the solution. The change in the concentration of hydrogen ion is calculated by the difference between the initial and final concentration of hydrogen ions present in the solution.

Expert Solution
Check Mark

Answer to Problem 20.53E

The number of molecules of substrate reacted to cause the change in hydrogen ion concentration is 5.42×1017.

Explanation of Solution

The number of molecules of substrate reacted to cause the change in hydrogen ion concentration is calculated by the following formula.

Numberofmolecules=Change in the hydrogen ion concentration×NA…(2)

Where,

NA is Avogadro number.

The value of NA is 6.023×1023.

The change in the hydrogen ion concentration is 9×107.

Substitute the value of hydrogen ion concentration and Avogadro number in equation (2).

Numberofmolecules=9×107×6.023×1023=54.207×1016=5.42×1017

Therefore, the number of molecules of substrate reacted to cause the change in hydrogen ion concentration is 5.42×1017.

Conclusion

The number of molecules of substrate reacted to cause the change in hydrogen ion concentration is 5.42×1017.

Interpretation Introduction

(c)

Interpretation:

The turnover number of enzyme is to be calculated.

Concept introduction:

Enzymes are the biocatalysts. Enzyme enhances the activity of biochemical process. For increasing the rate of biochemical reaction, enzyme should be biologically active. Turnover number is the maximum number of substrate molecule converted by an enzyme in one second.

Expert Solution
Check Mark

Answer to Problem 20.53E

The turnover number of enzyme is 9.03×1015sec1.

Explanation of Solution

The turnover number is calculated by the following formula.

Turnovernumber=NumberofmoleculesreactedTime(min)×60sec…(3)

The number of molecules of substrate reacted is 5.42×1017.

It is given that the time of reaction is 1min.

Substitute the value of time and number of molecules reacted in equation (3).

Turnovernumber=5.42×10171×60sec=0.0903×1017sec1=9.03×1015sec1

Therefore, the turnover number of enzyme is 9.03×1015sec1.

Conclusion

The turnover number of enzyme is 9.03×1015sec1.

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Chapter 20 Solutions

Bundle: Chemistry For Today: General, Organic, And Biochemistry, 9th + Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card

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