Interpretation:
Whether an achiral or two equal enantiomeric products would be given has to be predicted in the product of the given reaction and explained with chair like transition state.
Concept Introduction:
Cope-rearrangement:
It is a pericyclic reaction that involves the redistribution of six electrons through the formation of a cyclic transition state from which a
Example with mechanism of cope-arrangement:
In this mechanism, two pi-bonds and one sigma bond of the reactant molecule has been rearranged and formed two new pi-bonds through a cyclic transition state.
Identification of cope-rearrangement in a
In the cope-rearrangement, the flow of electrons takes place between six bonds that are bonded as
The carbon atoms that are involving in the cope-rearrangement are shown in bold.
Stereochemistry in a product formed:
- • In the product of a
chemical reaction , if a carbon atom has been attached with four different carbon atoms, then it is known as chiral carbon atom or stereocenter in the product. - • The bonds of the
functional groups because of which a new chiral carbon is supposed to form have to be represented in solid wedge bond and hashed-wedge bonds according to the particular enantiomer. - • Racemic mixture is the mixture of two enantiomers in equal proportions.
- • Enantiomers are non-superimposable mirror images.
- • Achiral product is the product in which there won’t be any chiral centre or stereocenter.

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Chapter 20 Solutions
OWL V2 with MindTap Reader and Student Solutions Manual eBook for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition
- X 5 Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. CI Br Br Br 0 None of these molecules have a total of five ẞ hydrogens. Explanation Check esc F1 F2 tab caps lock fn Q @2 A W # 3 OH O OH HO © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility IK F7 F7 F8 TA F9 F10 & 6 28 * ( > 7 8 9 0 80 F3 O F4 KKO F5 F6 S 64 $ D % 25 R T Y U பட F G H O J K L Z X C V B N M H control option command P H F11 F12 + || { [ command optionarrow_forwardAn open vessel containing water stands in a laboratory measuring 5.0 m x 5.0 m x 3.0 m at 25 °C ; the vapor pressure (vp) of water at this temperature is 3.2 kPa. When the system has come to equilibrium, what mass of water will be found in the air if there is no ventilation? Repeat the calculation for open vessels containing benzene (vp = 13.1 kPa) and mercury (vp = 0.23 Pa)arrow_forwardEvery chemist knows to ‘add acid to water with constant stirring’ when diluting a concentrated acid in order to keep the solution from spewing boiling acid all over the place. Explain how this one fact is enough to prove that strong acids and water do not form ideal solutions.arrow_forward
- The predominant components of our atmosphere are N₂, O₂, and Ar in the following mole fractions: χN2 = 0.780, χO2 = 0.21, χAr = 0.01. Assuming that these molecules act as ideal gases, calculate ΔGmix, ΔSmix, and ΔHmix when the total pressure is 1 bar and the temperature is 300 K.arrow_forwarddG = Vdp - SdT + μA dnA + μB dnB + ... so that under constant pressure and temperature conditions, the chemical potential of a component is the rate of change of the Gibbs energy of the system with respect to changing composition, μJ = (∂G / ∂nJ)p,T,n' Using first principles prove that under conditions of constant volume and temperature, the chemical potential is a measure of the partial molar Helmholtz energy (μJ = (∂A / ∂nJ)V,T,n')arrow_forwardThe vapor pressure of dichloromethane at 20.0 °C is 58.0 kPa and its enthalpy of vaporization is 32.7 kJ/mol. Estimate the temperature at which its vapor pressure is 66.0 kPa.arrow_forward
- Draw the structure of A, the minor E1 product of the reaction. Cl Skip Part Check F1 esc CH_CH OH, D 3 2 Click and drag to start drawing a structure. 80 R3 F4 F2 F3 @ 2 # $ 4 3 Q W 95 % KO 5 F6 A F7 × G ☐ Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ►II A A F8 F9 F10 FL 6 7 88 & * 8 9 LLI E R T Y U A S D lock LL F G H 0 P J K L Z X C V B N M 9 Harrow_forwardFrom the choices given, which two substances have the same crystal structure? (Select both) Group of answer choices ZnS (zincblende) Diamond TiO2 (rutile) ZnS (wurtzite)arrow_forwardPotassium (K) blends with germanium (Ge) to form a Zintl phase with a chemical formula of K4Ge4. Which of the following elements would you expect potassium to blend with to form an alloy? Electronegativities: As (2.0), Cl (3.0), Ge (1.8), K (0.8), S (2.5), Ti (1.5) Group of answer choices Arsenic (As) Sulfur (S) Chlorine (Cl) Titanium (Ti)arrow_forward
- Consider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forwardHow many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forwardV Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

