(a) Explanation Given info: The constant pressure of gas is 2.50 kPa , the initial volume of gas is 1.00 m 3 , the final volume of gas is 3.00 m 3 , the initial temperature of gas is 300 K and the heat transferred to gas is 12.5 kJ . The equation for work done on the gas is, W = − P ( V 2 − V 1 ) Here, P is the constant pressure of the gas. V 1 is the initial volume of gas. V 2 is the final volume of gas. Substitute 2.50 kPa for P , 3.00 m 3 for V 2 and 1.00 m 3 for V 1 in the above equation. W = − 2 (b) To determine The final temperature of the gas.

Physics for Scientists and Engineers, Volume 1, Chapters 1-22

8th Edition

ISBN: 9781439048382

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 20, Problem 20.37P

(a)

To determine

The change in internal energy of the gas.

(b)

To determine

The final temperature of the gas.

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Chapter 20, Problem 20.36P

Chapter 20, Problem 20.38P

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Chapter 20 Solutions

Physics for Scientists and Engineers, Volume 1, Chapters 1-22

Ch. 20 - Prob. 20.1QQ Ch. 20 - Suppose the same process of adding energy to the...Ch. 20 - Prob. 20.3QQ Ch. 20 - Characterize the paths in Figure 19.12 as...Ch. 20 - Prob. 20.5QQ Ch. 20 - An ideal gas is compressed to half its initial...Ch. 20 - A poker is a stiff, nonflammable rod used to push...Ch. 20 - Assume you are measuring the specific heat of a...Ch. 20 - Prob. 20.4OQ Ch. 20 - Prob. 20.5OQ

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The change in internal energy of the gas.

Solution Summary: The author explains that the change in internal energy of the gas is 7.50kJ.

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The change in internal energy of the gas.

The final temperature of the gas.

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Chapter 20 Solutions