MOLECULAR NATURE OF MATTER 7/E LL W/AC
MOLECULAR NATURE OF MATTER 7/E LL W/AC
7th Edition
ISBN: 9781119664796
Author: JESPERSEN
Publisher: WILEY
Question
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Chapter 20, Problem 1PE
Interpretation Introduction

Interpretation:

The mass of the tennis ball travelling at 53.6 m s-1 is to be determined.

Concept Introduction:

Relativistic effect is defined as the difference in values in the models which consider and cannot consider the relativity.

Relativistic effect is very crucial for a heavy element having high atomic number.

The mass of the particle (m), velocity of the particle (v), rest mass of the particle (m), and the velocity of the light (c) can be related by the following equation.

m=m1(vc)2.

Expert Solution & Answer
Check Mark

Answer to Problem 1PE

Solution: 57.7 g.

Explanation of Solution

Given information: The rest mass of tennis ball is 57.7 g.

The mass of the tennis ball is calculated as:

m=m1(vc)2

Here, m is the mass of the object, m is the rest mass of the object, v is the speed of the object and c is the speed of light.

Substitute rest mass of the object as 57.7 g, velocity of the object as 53.6 ms1 and the speed of light as 3×108 ms1.

m=57.7 g1(53.6 ms13×108 ms1)2=57.7 g

Thus, the mass of tennis ball is 57.7 g.

Therefore, the tennis ball cannot have any relativistic effect due to its large size and slow speed.

Conclusion

The mass of the tennis ball is 57.7 g.

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redraw the flowchart with boxes and molecules written in them
Part I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400
• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peak

Chapter 20 Solutions

MOLECULAR NATURE OF MATTER 7/E LL W/AC

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