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To determine: The reason that why illumination by a combination of light of 680 nm and 700 nm gives a higher rate of photosynthesis than light of either wavelength alone.
Introduction:
The photosynthesis is a process in which the green plants and algae obtain their nutrients. This process takes place in the chloroplast where chlorophyll molecules are present. The chloroplast contains thylakoid molecules where light reaction takes place. The end product of the light reaction is the formation of ATP and NADPH which is an energy storing molecule that together helps in driving the Calvin cycle in stroma of chloroplast.
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Explanation of Solution
Explanation:
Photosynthesis is a process in which the solar energy that is sunlight is used for the formation of chemical energy that is glucose from the carbon dioxide and water. During photosynthesis, oxygen gas is evolved. This process takes place in the thylakoid membrane present in the chloroplast. This thylakoid membrane contains two photosystem units: photosystem I (PS I) and photosystem II (PS II).
PS I absorbs 700 nm light and PS II which absorb 680 nm of light. PS I absorb 700 nm of light and start catalyzing NADP reduction and cyclic photophosphorylation. PS II absorb 680 nm of light and splits the water molecules into hydrogen ion and oxygen ion. The splitting of water molecules results in the generation of oxygen molecules and releases proton. The released proton then is transferred to PS I for the production of NADPH molecules.
Thus, 680 nm of light absorption by PS II promotes the splitting of water molecules and production of oxygen (O2) for driving photosynthesis reaction, but the maximum photosynthesis rate in plants are observed only when both wavelengths of light are illuminated simultaneously. Thus, operating of both photosystem units (PS I and PS II) simultaneously increases the efficiency of photosynthesis.
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Chapter 20 Solutions
Lehninger Principles of Biochemistry
- 1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forwardProblem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forward
- Problem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forwardProblem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward
- 1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 7 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of Vmax. Report your answer to three significant figures. 1 , mM-1 1 [S] V' sμM-¹ 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward12:33 CO Problem 5 of 15 4G 54% Done On the following Lineweaver-Burk 1 plot, identify the by dragging the Vmax point to the appropriate value on the line. NI 35 30- 25 20- 15- 10 5. 1 Vmax -15 10 -5 0 5 10 15 20 20 ||| で Г 25 30 1/[S]arrow_forward
- 12:20 V 0.1- 0:09. 0.08 0:07 0.06 -0.05- 0:04- -0.03- -0.02- 4G 56% Problem 1 of 15 Done On the following Michaelis-Menten plot, estimate the value of - Vmax by 1 2 dragging the line to the appropriate value on the y-axis. 0.01 V max 0 0.5 ||| 1.5 2.5 3.5 4 ISLarrow_forward12:33 CO 4G 54% Problem 6 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the Km. 1 mM-1 1 [S]' " s mM-1 V 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forwardV 0.1- 0:09 0:08 0:07- -0.06 -0.05 0:04- 0:03 0:02 0:01- Problem 2 of 15 Done On the following Michaelis-Menten plot, estimate the value of Kм by dragging the point to the appropriate value on the x-axis. I T | 0 0.5 1.5 2 KM -0:01- ||| 25 2.5 3 3.5 4 Г [S] powered by desmosarrow_forward
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