Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access)
7th Edition
ISBN: 9781319125752
Author: David L. Nelson, Michael M. Cox
Publisher: W. H. Freeman
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Chapter 20, Problem 19P
(a)
Summary Introduction
To determine:
The compound X which was first compound to become labeled with
Introduction:
Photosynthesis is a process in which the solar energy that is sunlight is used for the formation of chemical energy that is glucose from the carbon dioxide and water. During the photosynthesis, oxygen gas is evolved. This process involves two types of reactions: light reaction and dark reaction.
(b)
Summary Introduction
To determine:
The condition in which X became labeled quickly, but lost its radioactivity with time, whereas Y became more radioactive with time is to be determined.
Introduction:
Photosynthesis is a process in which the solar energy that is sunlight is used for the formation of chemical energy that is glucose from the carbon dioxide and water. During the photosynthesis, oxygen gas is evolved. This process involves two types of reactions: light reaction and dark reaction.
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A culture of kidneys cells contains all intermediates of the citric acid cycle. It is treated with an irreversible inhibitor of malate dehydrogenase, and then infused withglucose. Fill in the following list to account for the number of energy molecules that are formed from that one molecule of glucose in this situation. (NTP = nucleotidetriphosphate, e.g., ATP or GTP)Net number of NTP:Net number of NADH:Net number of FADH2:
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Chapter 20 Solutions
Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access)
Ch. 20 - Prob. 1PCh. 20 - Prob. 2PCh. 20 - Prob. 3PCh. 20 - Prob. 4PCh. 20 - Prob. 5PCh. 20 - Prob. 6PCh. 20 - Prob. 7PCh. 20 - Prob. 8PCh. 20 - Prob. 9PCh. 20 - Prob. 10P
Ch. 20 - Prob. 11PCh. 20 - Prob. 12PCh. 20 - Prob. 13PCh. 20 - Prob. 14PCh. 20 - Prob. 15PCh. 20 - Prob. 16PCh. 20 - Prob. 17PCh. 20 - Prob. 18PCh. 20 - Prob. 19PCh. 20 - Prob. 20PCh. 20 - Prob. 21PCh. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35DAP
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- 2. Which one of the following alkenes undergoes the least exothermic hydrogenation upon treatment with H₂/Pd? A B C D Earrow_forward6. What is the IUPAC name of the following compound? A) (Z)-3,5,6-trimethyl-3,5-heptadiene B) (E)-2,3,5-trimethyl-1,4-heptadiene C) (E)-5-ethyl-2,3-dimethyl-1,5-hexadiene D) (Z)-5-ethyl-2,3-dimethyl-1,5-hexadiene E) (Z)-2,3,5-trimethyl-1,4-heptadienearrow_forwardConsider the reaction shown. CH2OH Ex. CH2 -OH CH2- Dihydroxyacetone phosphate glyceraldehyde 3-phosphate The standard free-energy change (AG) for this reaction is 7.53 kJ mol-¹. Calculate the free-energy change (AG) for this reaction at 298 K when [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde 3-phosphate] = 0.00300 M. AG= kJ mol-1arrow_forward
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- Fatty acids are carboxylic acids with long hydrophobic tails. Draw the line-bond structure of cis-A9-hexadecenoate. Clearly show the cis-trans stereochemistry.arrow_forwardThe formation of acetyl-CoA from acetate is an ATP-driven reaction: Acetate + ATP + COA Acetyl CoA+AMP+ PP Calculate AG for this reaction given that the AG for the hydrolysis of acetyl CoA to acetate and CoA is -31.4 kJ mol-1 (-7.5 kcal mol-¹) and that the AG for hydrolysis of ATP to AMP and PP; is -45.6 kJ mol-1 (-10.9 kcal mol-¹). AG reaction kJ mol-1 The PP, formed in the preceding reaction is rapidly hydrolyzed in vivo because of the ubiquity of inorganic pyrophosphatase. The AG for the hydrolysis of pyrophosphate (PP.) is -19.2 KJ mol-¹ (-4.665 kcal mol-¹). Calculate the AG° for the overall reaction, including pyrophosphate hydrolysis. AGO reaction with PP, hydrolysis = What effect does the presence of pyrophosphatase have on the formation of acetyl CoA? It does not affect the overall reaction. It makes the overall reaction even more endergonic. It brings the overall reaction closer to equilibrium. It makes the overall reaction even more exergonic. kJ mol-1arrow_forwardConsider the Haworth projections of ẞ-L-galactose and ẞ-L-glucose shown here. OH CH₂OH OH CH₂OH OH OH OH ОН OH он B-L-galactose B-L-glucose Which terms describe the relationship between these two sugars? epimers enantiomers anomers diastereomersarrow_forward
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