Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
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Chapter 20, Problem 15RP
To determine
Find the maximum and minimum transmit times for light travelling from Jupiter to mars.
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please answer c,d,e
What is the value of the IR transmission factor (f) for a Venus-like planet, if the
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planet: E, = 2.60x10³ W m² and a = 0.71.
Would the average temperature increase or decrease if f decreased?
d&e
Chapter 20 Solutions
Applied Physics (11th Edition)
Ch. 20.2 - Find the distance (in metres) traveled by a radio...Ch. 20.2 - Prob. 2PCh. 20.2 - A television signal is sent to a communications...Ch. 20.2 - How long does it take for a radio signal from the...Ch. 20.2 - The sun is 9.30107mi from the earth. How long does...Ch. 20.2 - A radar wave is bounced off an airplane and...Ch. 20.2 - How long does it take for a radio wave to travel...Ch. 20.2 - How long does it take for a flash of light to...Ch. 20.2 - How long does it take for a police radar beam to...Ch. 20.2 - How far away (in km) is an airplane if the radar...
Ch. 20.2 - An auto mechanic uses a strobe light to time a...Ch. 20.2 - A construction company uses GPS technology to...Ch. 20.2 - (a) How long does it take for light to reach the...Ch. 20.2 - Prob. 14PCh. 20.2 - How long does it take light to reach the earth...Ch. 20.2 - Preparing for reentry, astronauts use radar to...Ch. 20.2 - Prob. 17PCh. 20.2 - Light from the sun travels 1.50108 km to reach the...Ch. 20.3 - c=3.00108m/s =4.55105m f=?Ch. 20.3 - c=3.00108m/s =9.701010m f=?Ch. 20.3 - c=3.00108m/s f=9.701011Hz =?Ch. 20.3 - c=3.00108m/s f=24.2 MHz =?Ch. 20.3 - c=3.00108m/s f=45.6 MHz =?Ch. 20.3 - Prob. 6PCh. 20.3 - Prob. 7PCh. 20.3 - Prob. 8PCh. 20.3 - Find the wavelength of a radio wave from an AM...Ch. 20.3 - Find the wavelength of a radio wave from an FM...Ch. 20.3 - Find the frequency of an electromagnetic wave if...Ch. 20.3 - Find the frequency of an electromagnetic wave if...Ch. 20.3 - Prob. 13PCh. 20.3 - Prob. 14PCh. 20.3 - Prob. 15PCh. 20.3 - An AM radio station broadcasts a signal with a...Ch. 20.4 - Prob. 1PCh. 20.4 - Prob. 2PCh. 20.4 - Prob. 3PCh. 20.4 - Find the frequency of electromagnetic radiation...Ch. 20.4 - Find the frequency of electromagnetic radiation...Ch. 20.4 - Prob. 6PCh. 20.4 - Find the frequency of electromagnetic radiation...Ch. 20.4 - Prob. 8PCh. 20.4 - Prob. 9PCh. 20.4 - Prob. 10PCh. 20.4 - Prob. 11PCh. 20.4 - Prob. 12PCh. 20.4 - An AM radio station in a nearby town broadcasts a...Ch. 20.5 - I=48.0 cd I=___mCh. 20.5 - Prob. 2PCh. 20.5 - I=765 m I=___ cdCh. 20.5 - I=432 m I=___ cdCh. 20.5 - I=75.0 cd I=___ mCh. 20.5 - I=650 m I=___ cdCh. 20.5 - I=900 m r=7.00 ft E=?Ch. 20.5 - I=741 m r=6.50 m E=?Ch. 20.5 - I=893 m r=3.25 ft E=?Ch. 20.5 - E=4.32 lux r=9.00 m I=?Ch. 20.5 - E=10.5 ft-candles r=6.00 ft I=?Ch. 20.5 - Prob. 12PCh. 20.5 - Prob. 13PCh. 20.5 - Prob. 14PCh. 20.5 - If an observer triples her distance from a light...Ch. 20.5 - If the illuminated surface is slanted at an angle...Ch. 20.5 - Find the illumination on a surface by three light...Ch. 20.5 - Find the intensity of two identical light sources...Ch. 20.5 - Find the intensity of two identical light sources...Ch. 20.5 - A desk is 3.35 m below an 1850-m incandescent...Ch. 20 - Which of the following are examples of...Ch. 20 - Prob. 2RQCh. 20 - Prob. 3RQCh. 20 - Light behaves a. as a massive particle. b. always...Ch. 20 - Does the wavelength of light depend on its...Ch. 20 - Prob. 6RQCh. 20 - How does the intensity of illumination depend on...Ch. 20 - In your own words, explain how the speed of light...Ch. 20 - Does light always travel at the same speed?...Ch. 20 - What name is given to the entire range of waves...Ch. 20 - Prob. 11RQCh. 20 - Who developed the wave packet theory of light?Ch. 20 - Who made the first estimate of the speed of light?Ch. 20 - How was the first estimate of the speed of light...Ch. 20 - What are the units of luminous intensity?Ch. 20 - In your own words, explain luminous intensity.Ch. 20 - Find the distance (in metres) traveled by a radio...Ch. 20 - A radar wave that is bounced off an airplane...Ch. 20 - How long does it take for a police radar beam to...Ch. 20 - Prob. 4RPCh. 20 - How long does it take for a radio signal to travel...Ch. 20 - Find the wavelength of a radio wave from an AM...Ch. 20 - Find the frequency of a radio wave if its...Ch. 20 - Prob. 8RPCh. 20 - Prob. 9RPCh. 20 - Prob. 10RPCh. 20 - Prob. 11RPCh. 20 - Prob. 12RPCh. 20 - Prob. 13RPCh. 20 - Find the intensity of the light source necessary...Ch. 20 - Prob. 15RPCh. 20 - Find the intensity of two identical light sources...Ch. 20 - Find the illumination on a surface by three light...Ch. 20 - Prob. 1ACCh. 20 - (a) When the Apollo astronauts landed on the moon,...Ch. 20 - Prob. 3ACCh. 20 - The individual rods on rooftop antennas are...Ch. 20 - Prob. 5AC
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- Auroras are caused by collisions between particles such as electrons released by the Sun, and atoms in a planet’s atmosphere. These collisions transfer energy to the atmospheric atoms causing them to emit specific colors (wavelengths) of light. On Earth, auroras occur in a layer of the atmosphere known as the ionosphere, 80 km to 400 km above the surface. If solar activity increases, the number of sunspots increases, and more particles are released by the Sun. If, on average, there were 150 sunspots in 2014, 5 in 2020, and 160 in 2023, which year(s) will have the most auroras, and which year(s) the least? Can you explain why? Answer:arrow_forwardThe planet Mercury is closer to the Sun than the Earth is, so it can sometimes come between Earth and Sun. That's called a transit. A transit is like a failed solar eclipse: In a solar eclipse, the Moon gets between Earth and Sun and blocks all sunlight. In a transit, Mercury blocks only a small fraction of the Sun's light because Mercury isn't close enough to us to completely block our view of the Sun. We want to calculate by how much the Sun will be dimmed when such a transit occurs, because that's important to know for satellites which are powered by solar panels (shown hovering around the Earth in the image above). Without Mercury in the way, the radiation intensity that hits the top of the Earth's atmosphere from the Sun is 1,360.8 W/m2 (W stands for Watt, measuring energy transferred per second). The fraction of this intensity that is blocked by Mercury during a transit is equal to the ratio between the cross-sectional area of Mercury (as seen from Earth) and the…arrow_forwardVoyager 2. When the Voyager 2 spacecraft was approaching towards its Neptune encounter in 1989, it was 4.5 × 10° km away from the earth. Its radio transmitter, with which it communicated with us (and we communicated with it), broadcast with a mere 22 Watt of power at the S-band (2.1 GHz). (Your home wi-fi router emits around 2 Watt at 2.4 GHz wi-fi band). Assuming the Voyager transmitter broadcast equally in all directions, (a) What signal intensity was received on the earth? (b) What electric and magnetic field amplitudes were detected? (c) How many 2.1 GHz photons were arriving per second on a radio-receiver antenna with a circular cross-section of diameter 34 meters? Two counter-propagating plane waves (a) Let E(z, t) = E0 cos(kz – wt)â + E, cos(kz + wt)x. Write E(z, t) in simpler form and find the associated magnetic field. (b) For the fields in part (a), find the instantaneous and time-averaged electric and magnetic field energy densities. (c) Let E(z, t) = E, cos(kz – wt)x + E,…arrow_forward
- Small differences in the wavelengths in the sun’s spectrum are detected when measurements are taken from different parts of the sun’s disk. Specifi cally, measurements of the 656-nm line in hydrogen taken from opposite sides on the sun’s equator—one side approaching Earth and the other receding—differ from each other by 0.0090 nm. Use this information to fi nd the rotational period of the sun’s equator. Express your answer in days. (The sun’s equatorial radius is 6.96 x 108 m.)arrow_forwardKepler’s First Law: Elliptical Planetary Orbits: The solar system major planet in the most elliptical solar orbit is little Mercury, which is the closest planet to the Sun. At Perihelion, Mercury’s distance from the Sun (Rp) is 0.31 AU. At Aphelion, Mercury’s distance from the Sun (Ra) is 0.47 AU. The intensity of Sunlight (I) that a planet receives from the Sun is inversely proportional to the square of that planet’s distance from the Sun (R). in other words, I = Constant / R2. Calculate how much more intense the Sunlight received by Mercury is at perihelion (p) than at aphelion (a): Rp2 = Ra2 = Ip / Ia = Ra2 / Rp2 =arrow_forwardSuppose a star 1000 times brighter than our Sun (that is, emitting 1000 times the power) suddenly goes supernova. Using data from Table: (a) By what factor does its power output increase? (b) How many times brighter than our entire Milky Way galaxy is the supernova? (c) Based on your answers, discuss whether it should be possible to observe supernovas in distant galaxies. Note that there are on the order of 1011 observable galaxies, the average brightness of which is somewhat less than our own galaxy.arrow_forward
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