Business Driven Information Systems
6th Edition
ISBN: 9781260004717
Author: Paige Baltzan
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 2, Problem PIAYKBP
To determine
Mention points on enhancing the ability to make decision by using MIS.
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8: The steel rod fits loosely inside the aluminum sleeve. Both components are attached to a rigid wall at A andjoined together by a pin at B. Because of a slight misalignmentof the pre-drilled holes, the torque T0 = 750 N-m was appliedto the steel rod before the pin could be inserted into theholes. Determine the torque (N-m) in each component afterT0 was removed. Use G = 80 GPa for steel and G = 28 GPa foraluminum
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9: The two steel shafts, each with one end builtinto a rigid support, have flanges attached to their freeends. The flanges are to be bolted together. However,initially there is a 6⁰ mismatch in the location of the boltholes as shown in the figure. Determine the maximumshear stress(ksi) in each shaft after the flanges have beenbolted together. The shear modulus of elasticity for steelis 12 x 106 psi. Neglect deformations of the bolts and theflanges.
Finally, your going to write several small javascript functions to practice with javascript core programming (basically just using javascript as a normal scripting language). For each section you can hardcode input values, and all output should go to console (we'll worry about the actual web page on Assignment 4). You can complete these all in one HTML file, or create one file for each part.
Chapter 2 Solutions
Business Driven Information Systems
Ch. 2 - Prob. 1OCQCh. 2 - Prob. 2OCQCh. 2 - Prob. 3OCQCh. 2 - Prob. 4OCQCh. 2 - Prob. 5OCQCh. 2 - Prob. 6OCQCh. 2 - Prob. 1RQCh. 2 - Prob. 2RQCh. 2 - Prob. 3RQCh. 2 - Prob. 4RQ
Ch. 2 - Prob. 5RQCh. 2 - Prob. 6RQCh. 2 - Prob. 7RQCh. 2 - Prob. 8RQCh. 2 - Prob. 9RQCh. 2 - Prob. 10RQCh. 2 - Prob. 11RQCh. 2 - Prob. 12RQCh. 2 - Prob. 13RQCh. 2 - Prob. 14RQCh. 2 - Prob. 15RQCh. 2 - Prob. 16RQCh. 2 - Prob. 17RQCh. 2 - Prob. 1CCOCh. 2 - Prob. 2CCOCh. 2 - Prob. 3CCOCh. 2 - Prob. 4CCOCh. 2 - Prob. 5CCOCh. 2 - Prob. 6CCOCh. 2 - Prob. 1CCTCh. 2 - Prob. 2CCTCh. 2 - Prob. 3CCTCh. 2 - Prob. 1CBTCh. 2 - Prob. 2CBTCh. 2 - Prob. 3CBTCh. 2 - Prob. 4CBTCh. 2 - Prob. 5CBTCh. 2 - Prob. 6CBTCh. 2 - Prob. 7CBTCh. 2 - Prob. 8CBTCh. 2 - Prob. PIAYKBPCh. 2 - Prob. PIIAYKBPCh. 2 - Prob. PIIIAYKBPCh. 2 - Prob. PIVAYKBPCh. 2 - Prob. PVAYKBPCh. 2 - Prob. PVIAYKBPCh. 2 - Prob. PVIIAYKBPCh. 2 - Prob. PVIIIAYKBPCh. 2 - Prob. PIXAYKBPCh. 2 - Prob. PXAYKBPCh. 2 - Prob. PXIAYKBP
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- The solid compound shaft, made of threedifferent materials, carries the two torques shown. Theshear moduli are 28 GPa for aluminum, 83 GPa for steel,and 35 GPa for bronze.1. Calculate the maximum shear stress (MPa) in eachmaterial.2. Find the angle of rotation (degrees) of the free endof the shaft.arrow_forwardWrite a program to calculate the function sin(x) or cos(x) using a Taylor series expansion around the point 0. In other words, you will program the sine or cosine function yourself, without using any existing solution. You can enter the angles in degrees or radians. The program must work for any input, e.g. -4500° or +8649°. The function will have two arguments: float sinus(float radians, float epsilon); For your own implementation, use one of the following relations (you only need to program either sine or cosine, you don't need both): Tip 1: Of course, you cannot calculate the sum of an infinite series indefinitely. You can see (if not, look in the program) that the terms keep getting smaller, so there will definitely be a situation where adding another term will not change the result in any way (see problem 1.3 – machine epsilon). However, you can end the calculation even earlier – when the result changes by less than epsilon (a pre-specified, sufficiently small number, e.g.…arrow_forwardWrite a C program that finds and prints the machine epsilon for the float and double data types. Also print the values of __FLT_EPSILON__ and __DBL_EPSILON__ defined in float.h. Reminder – the phrase data type tells how the compiler “understands” the ones and zeros you are working with. This identifies whether you are working with integers, letters, real numbers, and so on. Another definition:Machine epsilon is the "distance" between the number 1 and its immediate right neighbor. We work in binary (decimal is in parentheses): 1 + 0,1 = 1,1 (1 + 1/2 = 1,5) 1 + 0,01 = 1,01 (1 + 1/4 = 1,25) 1 + 0,001 = 1,001 (1 + 1/8 = 1,125) then, due to the limited accuracy of the computer at a certain number of decimal places, a situation arises where 1 + 0.0…001 = 1 (instead of the correct 1.0…001). Then the previous number 0.0…01 is called the machine epsilon . It is obvious that its value may be different on different computers. However, the machine…arrow_forward
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