Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 2, Problem 8P
To determine
The names of two key influences on transit system carrying capacity.
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- If a contractor has to quit a project due to a lack of funds what would be the best way to handle the breach of contract?arrow_forwardTo determine the elevation of a point such as B in Fig. 24 in the text, the following procedure was used: With the transit set up over a point such as A whose elevation is 128.3 ft, the height of the transverse axis above A was 4.84 ft and the vertical angle b between the horizontal line CD through the transverse axis and the line of sight to the point B was +12º 42'. Then a point such as E was marked on the ground on the line between A and B and at a horizontal distance from A equal to 50.00 ft. Finally, with the transit set up over the point E, the difference in elevation between the point A and the transverse axis F of the transit at E was found to be 3.47 ft, and the vertical angle d between the horizontal line through F and the line of sight to the point B was +18º 07'. The elevation of the point B isarrow_forwardWhich of the following statements is not true when considering precision in surveying?A. Measuring angles to the nearest minute and distances to the nearest hundredth of a foot is usually sufficient for locating theroute of a highway.B. A very accurate survey provides a very high degree of precision.C. Precision is defined as the degree of correctness applied in instruments.D. The most precise instruments can produce inaccurate results i f subjected to mechanical or human error.arrow_forward
- Which of the following is not desirable when marking a transit point for conducting a survey?A. Embedding a nail into soft concreteB. Driving a tack flush with the top o f a wooden hubC. Chiseling a cross on an embedded rockD. Driving a nail with flagging into undisturbed eartharrow_forwardA one-story building as shown in the plan, if the height of the concrete floor is 320 m, the width of the wall is 0.24 and the roof is made of reinforced concrete, the amount of iron for the roof is 100 kg m3 and there are downward depressions with a depth of 0.40 and a width of 0.25 along the wall and the amount of reinforcing iron is 89 kg m3 and there are 14 columns with dimensions of 0.500.30 and a height of 2.80, the amount of reinforcing iron is 120 kg m3 Find The amount of bricks used for construction The amount of mortar used for construction (cement + sand) -1 -2 The amount of plaster for the building from the inside is 2 cm thick (cement + sand) -3 Quantity of floor tiles for the room Quantity of concrete for the ceiling and beams. Ceiling thickness: 0.20 m. Total amount of reinforcing steel for the roof (tons) Quantity of reinforcing steel for columns (tons) Total amount of reinforcing steel for balls (tons) -4 -5 -6 -7 -8arrow_forwardK Course Code CE181303 Course Title Hours per week L-T-P Credit C Fluid Mechanics 3-1-0 MODULE 1: Fluid Properties: Fluid-definition, types; physical properties of fluid-density, specific weight, specific volume, specific gravity, viscosity- Newton's law of viscosity, surface tension, compressibility of fluids, capillarity. MODULE 2: Fluid Statics: Hydrostatic pressure, pressure height relationship, absolute and gauge pressure, measurement of pressure-manometer, pressure on submerged plane and curved surfaces, centre of pressure; buoyancy, equilibrium of floating bodies, metacentre; fluid mass subjected to accelerations. MODULE 3: Fluid Kinematics: Types of motion- steady and unsteady flow, uniform and no uniform flow, laminar and turbulent flow, and path lines, stream tube, stream function compressible and incompressible flow, one, two & three dimensional flow; stream lines, streak lines and velocity potential, flow net and its drawing: free and forced vortex. MODITE Q. A closed…arrow_forward
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- What would be the best way to handle when a contractor misses a concrete pour deadline which causes delays for other contractors?arrow_forwardPlease solve manuallyarrow_forward. The free fall distance was 1753 mm. The times for the release and catch recorded on the fall experiments were in millisecond: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Calculate the time taken for the fall for each experiment. Calculate for each fall the acceleration based on time and distance. Calculate the mean of the accelerations. Give in the answer window the calculated mean of accelerations in m/s2.arrow_forward
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