The formula of the binary compound formed from the given pairs of elements in each case is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

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Answer 1

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Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Explanation of Solution

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

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Answer 2

Question

100%

Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Explanation of Solution

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

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Answer 3

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Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Explanation of Solution

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

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Answer 4

Question

100%

Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Explanation of Solution

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

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Answer 5

Question

100%

Answer 6

Question

100%

Answer 7

Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Explanation of Solution

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

Answer 8

Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

Answer 9

Chapter 2, Problem 89E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 10

(a)

Expert Solution

Answer to Problem 89E

The formula of sodium oxide is $Na2O$

Answer 11

(a)

Expert Solution

Answer 12

(a)

Expert Solution

Answer 13

Expert Solution

Answer 14

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is $Na2O$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $Na2O$

Answer 15

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Explanation of Solution

To determine: The formula of sodium peroxide.

The formula of sodium peroxide is $Na2O2$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−1$ . It is exception case which occurs only in peroxide condition.

Sodium peroxide is formed when two sodium and oxygen atoms is combined together.

So, the formula of the given compound is $Na2O2$

Answer 16

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 17

(b)

Expert Solution

Answer to Problem 89E

The formula of sodium peroxide is $Na2O2$

Answer 18

(b)

Expert Solution

Answer 19

(b)

Expert Solution

Answer 20

Expert Solution

Answer 21

Explanation of Solution

To determine: The formula of sodium peroxide.

The formula of sodium peroxide is $Na2O2$

The oxidation state of sodium is $+1$ .

Oxygen is an anion having oxidation state $−1$ . It is exception case which occurs only in peroxide condition.

Sodium peroxide is formed when two sodium and oxygen atoms is combined together.

So, the formula of the given compound is $Na2O2$

Answer 22

(c)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(c)

Expert Solution

Answer to Problem 89E

The formula of potassium cyanide is $KCN$

Explanation of Solution

To determine: The formula of potassium cyanide

The formula of potassium cyanide is $KCN$

The oxidation state of potassium is $+1$

Cyanide $(CN)$ is an anion having oxidation state $−1$

So, the formula of the given compound is $KCN$

Answer 23

(c)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 24

(c)

Expert Solution

Answer to Problem 89E

The formula of potassium cyanide is $KCN$

Answer 25

(c)

Expert Solution

Answer 26

(c)

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

To determine: The formula of potassium cyanide

The formula of potassium cyanide is $KCN$

The oxidation state of potassium is $+1$

Cyanide $(CN)$ is an anion having oxidation state $−1$

So, the formula of the given compound is $KCN$

Answer 29

(d)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(d)

Expert Solution

Answer to Problem 89E

The formula of copper (II) nitrate is $Cu(NO3)2$

Explanation of Solution

To determine: The formula of copper (II) nitrate

The formula of copper (II) nitrate is $Cu(NO3)2$

The oxidation state of copper is $+2$ .

Nitrate $(NO3)2$ is an anion having oxidation state $−1$

So, the formula of the given compound is $Cu(NO3)2$

Answer 30

(d)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 31

(d)

Expert Solution

Answer to Problem 89E

The formula of copper (II) nitrate is $Cu(NO3)2$

Answer 32

(d)

Expert Solution

Answer 33

(d)

Expert Solution

Answer 34

Expert Solution

Answer 35

Explanation of Solution

To determine: The formula of copper (II) nitrate

The formula of copper (II) nitrate is $Cu(NO3)2$

The oxidation state of copper is $+2$ .

Nitrate $(NO3)2$ is an anion having oxidation state $−1$

So, the formula of the given compound is $Cu(NO3)2$

Answer 36

(e)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(e)

Expert Solution

Answer to Problem 89E

The formula of selenium tetrabromide is $SeBr4$

Explanation of Solution

To determine: The formula of selenium tetrabromide.

The formula of selenium tetrabromide is $SeBr4$

The oxidation state of selenium is $+4$ .

Bromine is an anion having oxidation state $−1$

So, the formula of the given compound is $SeBr4$

Answer 37

(e)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 38

(e)

Expert Solution

Answer to Problem 89E

The formula of selenium tetrabromide is $SeBr4$

Answer 39

(e)

Expert Solution

Answer 40

(e)

Expert Solution

Answer 41

Expert Solution

Answer 42

Explanation of Solution

To determine: The formula of selenium tetrabromide.

The formula of selenium tetrabromide is $SeBr4$

The oxidation state of selenium is $+4$ .

Bromine is an anion having oxidation state $−1$

So, the formula of the given compound is $SeBr4$

Answer 43

(f)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(f)

Expert Solution

Answer to Problem 89E

The formula of iodous acid is $HIO2$

Explanation of Solution

To determine: The formula of iodous acid

The formula of iodous acid is $HIO2$

The oxidation state of hydrogen cation is $+1$ .

Iodite $(IO2)$ is anion having oxidation state $−1$

So, the formula of the given compound is $HIO2$

Answer 44

(f)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 45

(f)

Expert Solution

Answer to Problem 89E

The formula of iodous acid is $HIO2$

Answer 46

(f)

Expert Solution

Answer 47

(f)

Expert Solution

Answer 48

Expert Solution

Answer 49

Explanation of Solution

To determine: The formula of iodous acid

The formula of iodous acid is $HIO2$

The oxidation state of hydrogen cation is $+1$ .

Iodite $(IO2)$ is anion having oxidation state $−1$

So, the formula of the given compound is $HIO2$

Answer 50

(g)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(g)

Expert Solution

Answer to Problem 89E

The formula of lead (IV) sulfide is $PbS2$

Explanation of Solution

To determine: The formula of of lead (IV) sulfide.

The formula of lead (IV) sulfide is $PbS2$

The oxidation state of lead $(Pb)$ is $+4$ .

Sulfide is an anion having oxidation state $−2$

So, the formula of the given compound is $PbS2$

Answer 51

(g)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 52

(g)

Expert Solution

Answer to Problem 89E

The formula of lead (IV) sulfide is $PbS2$

Answer 53

(g)

Expert Solution

Answer 54

(g)

Expert Solution

Answer 55

Expert Solution

Answer 56

Explanation of Solution

To determine: The formula of of lead (IV) sulfide.

The formula of lead (IV) sulfide is $PbS2$

The oxidation state of lead $(Pb)$ is $+4$ .

Sulfide is an anion having oxidation state $−2$

So, the formula of the given compound is $PbS2$

Answer 57

(h)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(h)

Expert Solution

Answer to Problem 89E

The formula of copper (I) chloride is $CuCl$

Explanation of Solution

To determine: The formula of copper (I) chloride.

The formula of copper (I) chloride is $CuCl$

The oxidation state of copper $(Cu)$ is $+1$ .

Chlorine $(Cl)$ is an anion having oxidation state $−1$

So, the formula of the given compound is $CuCl$

Answer 58

(h)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 59

(h)

Expert Solution

Answer to Problem 89E

The formula of copper (I) chloride is $CuCl$

Answer 60

(h)

Expert Solution

Answer 61

(h)

Expert Solution

Answer 62

Expert Solution

Answer 63

Explanation of Solution

To determine: The formula of copper (I) chloride.

The formula of copper (I) chloride is $CuCl$

The oxidation state of copper $(Cu)$ is $+1$ .

Chlorine $(Cl)$ is an anion having oxidation state $−1$

So, the formula of the given compound is $CuCl$

Answer 64

(i)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(i)

Expert Solution

Answer to Problem 89E

The formula of gallium arsenide is $GaAs$

Explanation of Solution

To determine: The formula of gallium arsenide

The formula of gallium arsenide is $GaAs$

The oxidation state of gallium $(Ga)$ is $+3$ .

Arsenic $(As)$ is an anion having oxidation state $+3$

So, the formula of the given compound is $GaAs$

Answer 65

(i)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 66

(i)

Expert Solution

Answer to Problem 89E

The formula of gallium arsenide is $GaAs$

Answer 67

(i)

Expert Solution

Answer 68

(i)

Expert Solution

Answer 69

Expert Solution

Answer 70

Explanation of Solution

To determine: The formula of gallium arsenide

The formula of gallium arsenide is $GaAs$

The oxidation state of gallium $(Ga)$ is $+3$ .

Arsenic $(As)$ is an anion having oxidation state $+3$

So, the formula of the given compound is $GaAs$

Answer 71

(j)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(j)

Expert Solution

Answer to Problem 89E

The formula of cadmium selenide is $CdSe$

Explanation of Solution

To determine: The formula of cadmium selenide.

The formula of cadmium selenide is $CdSe$

The oxidation state of cadmium $(Cd)$ is $+2$ .

Selenium $(Se)$ is an anion having oxidation state $−2$

So, the formula of the given compound is $CdSe$

Answer 72

(j)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 73

(j)

Expert Solution

Answer to Problem 89E

The formula of cadmium selenide is $CdSe$

Answer 74

(j)

Expert Solution

Answer 75

(j)

Expert Solution

Answer 76

Expert Solution

Answer 77

Explanation of Solution

To determine: The formula of cadmium selenide.

The formula of cadmium selenide is $CdSe$

The oxidation state of cadmium $(Cd)$ is $+2$ .

Selenium $(Se)$ is an anion having oxidation state $−2$

So, the formula of the given compound is $CdSe$

Answer 78

(k)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(k)

Expert Solution

Answer to Problem 89E

The formula of zinc sulfide is $ZnS$

Explanation of Solution

To determine: The formula of of zinc sulfide.

The formula of zinc sulfide is $ZnS$

The oxidation state of zinc $(Zn)$ is $+2$ .

Sulfide is an anion having oxidation state $−2$

So, the formula of the given compound is $ZnS$

Answer 79

(k)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 80

(k)

Expert Solution

Answer to Problem 89E

The formula of zinc sulfide is $ZnS$

Answer 81

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Expert Solution

Answer 82

(k)

Expert Solution

Answer 83

Expert Solution

Answer 84

Explanation of Solution

To determine: The formula of of zinc sulfide.

The formula of zinc sulfide is $ZnS$

The oxidation state of zinc $(Zn)$ is $+2$ .

Sulfide is an anion having oxidation state $−2$

So, the formula of the given compound is $ZnS$

Answer 85

(l)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(l)

Expert Solution

Answer to Problem 89E

The formula of nitrous acid is $HNO2$

Explanation of Solution

To determine: The formula of of nitrous acid.

The formula of nitrous acid is $HNO2$

The oxidation state of hydrogen $(H)$ is $+1$ .

Nitrous $(NO2)$ is an anion having oxidation state $−1$

So, the formula of the given compound is $HNO2$

Answer 86

(l)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 87

(l)

Expert Solution

Answer to Problem 89E

The formula of nitrous acid is $HNO2$

Answer 88

(l)

Expert Solution

Answer 89

(l)

Expert Solution

Answer 90

Expert Solution

Answer 91

Explanation of Solution

To determine: The formula of of nitrous acid.

The formula of nitrous acid is $HNO2$

The oxidation state of hydrogen $(H)$ is $+1$ .

Nitrous $(NO2)$ is an anion having oxidation state $−1$

So, the formula of the given compound is $HNO2$

Answer 92

(m)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(m)

Expert Solution

Answer to Problem 89E

The formula of diphosphorous pentaoxide is $P2O5$

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

Answer 93

(m)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, $group number−8$ . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer 94

(m)

Expert Solution

Answer to Problem 89E

The formula of diphosphorous pentaoxide is $P2O5$

Answer 95

(m)

Expert Solution

Answer 96

(m)

Expert Solution

Answer 97

Expert Solution

Answer 98

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is $P2O5$

The oxidation state of phosphorous $(P)$ is $+5$ .

Oxygen is an anion having oxidation state $−2$

So, the formula of the given compound is $P2O5$

Answer 99

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Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

Answer to Problem 89E

Explanation of Solution

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