Chemistry with Access Code, Hybrid Edition
Chemistry with Access Code, Hybrid Edition
9th Edition
ISBN: 9781285188492
Author: Steven S. Zumdahl
Publisher: CENGAGE L
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Textbook Question
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Chapter 2, Problem 86E

Write the formula for each of the following compounds:

  1. a. ammonium hydrogen phosphate
  2. b. mercury (I) sulfide
  3. c. silicon dioxide
  4. d. sodium sulfite
  5. e. aluminum hydrogen sulfate
  6. f. nitrogen trichloride
  7. g. hydiobromic acid
  8. h. bromous acid
  9. i. perbromic acid
  10. j. potassium hydrogen sulfide
  11. k. calcium iodide
  12. l. cesium perchlorate

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of ammonium hydrogen phosphate is (NH4)2HPO4

Explanation of Solution

To determine: The formula of ammonium hydrogen phosphate.

The oxidation state of ammonium (NH4) is +1.

Hydrogen phosphate HPO4  is an anion having oxidation state −1

So, the formula of the given compound is (NH4)2HPO4

Conclusion

The formula of ammonium hydrogen phosphate is (NH4)2HPO4

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of mercury (I) sulfide is Hg2S

Explanation of Solution

To determine: The formula of mercury (I) sulfide.

The oxidation state of mercury is +1.

Sulfide is an anion having oxidation state −2.

So, the formula of the given compound is Hg2S

Conclusion

The formula of mercury(I) sulfide is Hg2S

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of silicon dioxide is SiO2

Explanation of Solution

To determine: The formula of silicon dioxide

The oxidation state of silicon is +2

Dioxide is an anion having oxidation state −1

So, the formula of the given compound is SiO2

Conclusion

The formula of silicon dioxide is SiO2

(d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of sodium sulfite is Na2(SO3)

Explanation of Solution

To determine: The formula of sodium sulfite

The oxidation state of sodium is +1.

Sulfite (SO3) is an anion having oxidation state −2

So, the formula of the given compound is Na2(SO3)

Conclusion

The formula of sodium sulfite is Na2(SO3)

(e)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of alumunium hydrogen sulfate is Al(HSO4)3

Explanation of Solution

To determine: The formula of alumunium hydrogen sulfate.

The oxidation state of alumunium is +3.

Hydrogen sulfate (HSO4) is an anion having oxidation state −1

So, the formula of the given compound is Al(HSO4)3

Conclusion

The formula of alumunium hydrogen sulfate is Al(HSO4)3

(f)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of nitrogen trichloride is NCl3

Explanation of Solution

To determine: The formula of nitrogen trichloride.

The oxidation state of nitrogen is −3.

The oxidation state of chlorine is −1

So, the formula of the given compound is NCl3

Conclusion

The formula of nitrogen trichloride is NCl3

(g)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of hydrobromic acid is HBr

Explanation of Solution

To determine: The formula of of hydrobromic acid

The oxidation state of hydrogen (H) is +1.

Bromine is an anion having oxidation state −1

So, the formula of the given compound is HBr

Conclusion

The formula of hydrobromic acid is HBr

(h)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of bromous acid is HBrO2

Explanation of Solution

To determine: The formula of bromous acid

The oxidation state of hydrogen (H) is +1.

Bromite (BrO2) is an anion having oxidation state −1

So, the formula of the given compound is HBrO2

Conclusion

The formula of bromous acid is HBrO2

(i)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of perbromic acid is HBrO4

Explanation of Solution

To determine: The formula of perbromic acid

The oxidation state of hydrogen (H) is +1.

Perbromate (BrO4) is an anion having oxidation state −1

So, the formula of the given compound is HBrO4

Conclusion

The formula of perbromic acid is HBrO4

(j)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of potassium hydrogen sulfide is KHS

Explanation of Solution

To determine: The formula of potassium hydrogen sulfide

The oxidation state of potassium (K) is +1.

Hydrogen sulfide is an anion having oxidation state −1

So, the formula of the given compound is KHS

Conclusion

The formula of potassium hydrogen sulfide is KHS

(k)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of calcium iodide is CaI2

Explanation of Solution

To determine: The formula of of calcium iodide

The oxidation state of calcium (Ca) is +2.

Iodine is an anion having oxidation state −1

So, the formula of the given compound is CaI2

Conclusion

The formula of calcium iodide is CaI2

(l)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

Answer to Problem 86E

The formula of cesium perchlorate is CsClO4

Explanation of Solution

To determine: The formula of of cesium perchlorate.

The oxidation state of cesium (Cs) is +1.

Perchlorate (ClO4) is an anion having oxidation state −1

So, the formula of the given compound is CsClO4

Conclusion

The formula of cesium perchlorate is CsClO4

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Chapter 2 Solutions

Chemistry with Access Code, Hybrid Edition

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