Chemistry with Access Code, Hybrid Edition
Chemistry with Access Code, Hybrid Edition
9th Edition
ISBN: 9781285188492
Author: Steven S. Zumdahl
Publisher: CENGAGE L
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Chapter 2, Problem 85E

(a)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(a)

Expert Solution
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Answer to Problem 85E

The formula of sodium oxide is Na2O

Explanation of Solution

To determine: The formula of sodium oxide.

The formula of sodium oxide is Na2O

The oxidation state of sodium is +1.

Oxygen is an anion having oxidation state −2

So, the formula of the given compound is Na2O

(b)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(b)

Expert Solution
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Answer to Problem 85E

The formula of sodium peroxide is Na2O2

Explanation of Solution

To determine: The formula of sodium peroxide.

The formula of sodium peroxide is Na2O2

The oxidation state of sodium is +1.

Oxygen is an anion having oxidation state −1. It is exception case which occurs only in peroxide condition.

Sodium peroxide is formed when two sodium and oxygen atoms is combined together.

So, the formula of the given compound is Na2O2

(c)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(c)

Expert Solution
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Answer to Problem 85E

The formula of potassium cyanide is KCN

Explanation of Solution

To determine: The formula of potassium cyanide

The formula of potassium cyanide is KCN

The oxidation state of potassium is +1

Cyanide (CN) is an anion having oxidation state −1

So, the formula of the given compound is KCN

(d)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(d)

Expert Solution
Check Mark

Answer to Problem 85E

The formula of copper (II) nitrate is Cu(NO3)2

Explanation of Solution

To determine: The formula of copper (II) nitrate

The formula of copper (II) nitrate is Cu(NO3)2

The oxidation state of copper is +2.

Nitrate (NO3)2 is an anion having oxidation state −1

So, the formula of the given compound is Cu(NO3)2

(e)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(e)

Expert Solution
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Answer to Problem 85E

The formula of selenium tetrabromide is SeBr4

Explanation of Solution

To determine: The formula of selenium tetrabromide.

The formula of selenium tetrabromide is SeBr4

The oxidation state of selenium is +4.

Bromine is an anion having oxidation state −1

So, the formula of the given compound is SeBr4

 (f)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

 (f)

Expert Solution
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Answer to Problem 85E

The formula of iodous acid is HIO2

Explanation of Solution

To determine: The formula of iodous acid

The formula of iodous acid is HIO2

The oxidation state of hydrogen cation is +1.

Iodite (IO2) is anion having oxidation state −1

So, the formula of the given compound is HIO2

(g)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(g)

Expert Solution
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Answer to Problem 85E

The formula of lead (IV) sulfide is PbS2

Explanation of Solution

To determine: The formula of of lead (IV) sulfide.

The formula of lead (IV) sulfide is PbS2

The oxidation state of lead (Pb) is +4.

Sulfide is an anion having oxidation state −2

So, the formula of the given compound is PbS2

(h)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(h)

Expert Solution
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Answer to Problem 85E

The formula of copper (I) chloride is CuCl

Explanation of Solution

To determine: The formula of copper (I) chloride.

The formula of copper (I) chloride is CuCl

The oxidation state of copper (Cu) is +1.

Chlorine (Cl) is an anion having oxidation state −1

So, the formula of the given compound is CuCl

 (i)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

 (i)

Expert Solution
Check Mark

Answer to Problem 85E

The formula of gallium arsenide is GaAs

Explanation of Solution

To determine: The formula of gallium arsenide

The formula of gallium arsenide is GaAs

The oxidation state of gallium (Ga) is +3.

Arsenic (As) is an anion having oxidation state +3

So, the formula of the given compound is GaAs

 (j)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

 (j)

Expert Solution
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Answer to Problem 85E

The formula of cadmium selenide is CdSe

Explanation of Solution

To determine: The formula of cadmium selenide.

The formula of cadmium selenide is CdSe

The oxidation state of cadmium (Cd) is +2.

Selenium (Se) is an anion having oxidation state −2

So, the formula of the given compound is CdSe

 (k)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

 (k)

Expert Solution
Check Mark

Answer to Problem 85E

The formula of zinc sulfide is ZnS

Explanation of Solution

To determine: The formula of of zinc sulfide.

The formula of zinc sulfide is ZnS

The oxidation state of zinc (Zn) is +2.

Sulfide is an anion having oxidation state −2

So, the formula of the given compound is ZnS

(l)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(l)

Expert Solution
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Answer to Problem 85E

The formula of nitrous acid is HNO2

Explanation of Solution

To determine: The formula of of nitrous acid.

The formula of nitrous acid is HNO2

The oxidation state of hydrogen (H) is +1.

Nitrous (NO2) is an anion having oxidation state −1

So, the formula of the given compound is HNO2

(m)

Interpretation Introduction

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.

Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.

(m)

Expert Solution
Check Mark

Answer to Problem 85E

The formula of diphosphorous pentaoxide is P2O5

Explanation of Solution

To determine: The formula of of diphosphorous pentaoxide.

The formula of diphosphorous pentaoxide is P2O5

The oxidation state of phosphorous (P) is +5.

Oxygen is an anion having oxidation state −2

So, the formula of the given compound is P2O5

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Chapter 2 Solutions

Chemistry with Access Code, Hybrid Edition

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