We've seen that a man's higher initial acceleration means that a man can outrun a horse over a very short race. A simple—but plausible—model for a sprint by a man and a horse uses the following assumptions: The man accelerates at 6.0 m/s 2 for 1.8 s and then runs at a constant speed. A horse accelerates at a more modest 5.0 m/s 2 but continues accelerating for 4.8 s and then continues at a constant speed. A man and a horse are competing in a 200 m race. The man is given a 100 m head start, so he begins 100 m from the finish line. How much time does the man take to complete the race? How much time does the horse take? Who wins the race?
We've seen that a man's higher initial acceleration means that a man can outrun a horse over a very short race. A simple—but plausible—model for a sprint by a man and a horse uses the following assumptions: The man accelerates at 6.0 m/s 2 for 1.8 s and then runs at a constant speed. A horse accelerates at a more modest 5.0 m/s 2 but continues accelerating for 4.8 s and then continues at a constant speed. A man and a horse are competing in a 200 m race. The man is given a 100 m head start, so he begins 100 m from the finish line. How much time does the man take to complete the race? How much time does the horse take? Who wins the race?
We've seen that a man's higher initial acceleration means that a man can outrun a horse over a very short race. A simple—but plausible—model for a sprint by a man and a horse uses the following assumptions: The man accelerates at 6.0 m/s2 for 1.8 s and then runs at a constant speed. A horse accelerates at a more modest 5.0 m/s2 but continues accelerating for 4.8 s and then continues at a constant speed. A man and a horse are competing in a 200 m race. The man is given a 100 m head start, so he begins 100 m from the finish line. How much time does the man take to complete the race? How much time does the horse take? Who wins the race?
What is the resistance (in (2) of a 27.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?
0.445
ΧΩ
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d.
Ag
dFe
= 2.47
×
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d
Ag
= 2.51
dFe
×
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