The name of the binary compound formed from the given structures and compound is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
The name of the binary compound formed from the given structures and compound is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
Solution Summary: The author explains that the name of the binary compound formed from the given structures and compound is to be stated.
Interpretation: The name of the binary compound formed from the given structures and compound is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(b)
Interpretation Introduction
Interpretation: The name of the binary compound formed from the given structures and compound is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(c)
Interpretation Introduction
Interpretation: The name of the binary compound formed from the given structures and compound is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(d)
Interpretation Introduction
Interpretation: The name of the binary compound formed from the given structures and compound is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
JON
Determine the bund energy for
UCI (in kJ/mol Hcl) using me
balanced chemical equation and
bund energies listed?
का
(My (9) +36/2(g)-(((3(g) + 3(g)
A Hryn = -330. KJ
bond energy
и-н 432
bond
bond
C-1413
C=C 839 N-H
391
C=O 1010
S-H 363
б-н 467
02 498
N-N
160
N=N
243
418
C-C 341
C-0 358
C=C
C-C 339 N-Br
243
Br-Br
C-Br 274
193
614
(-1 214||(=olin (02) 799
C=N
615
AAL
Determine the bond energy for HCI (
in kJ/mol HCI) using he balanced
cremiculequecticnand bund energles
listed? also c double bond to N is
615, read numbets carefully please!!!!
Determine the bund energy for
UCI (in kJ/mol cl) using me
balanced chemical equation and
bund energies listed?
51
(My (9) +312(g)-73(g) + 3(g)
=-330. KJ
спод
bond energy
Hryn
H-H
bond
band
432
C-1 413
C=C 839 NH
391
C=O 1010
S-1 343
6-H
02 498
N-N
160
467
N=N
C-C
341
CL-
243
418
339 N-Br
243
C-O
358
Br-Br
C=C
C-Br 274
193
614
(-1 216 (=olin (02) 799
C=N
618
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