(a)
Interpretation:
Molecular formula of the given formula has to be written.
Concept Introduction:
Molecular formula shows that the actual number of atoms of each element that are present in a molecule of the compound.
(b)
Interpretation:
Number of
Concept Introduction:
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
The steric number is the combination of both number of
If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
(c)
Interpretation:
Number of
Concept Introduction:
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
The steric number is the combination of both number of
If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
(d)
Interpretation:
Number of
Concept Introduction:
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
The steric number is the combination of both number of
If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
(e)
Interpretation:
The lone pair of electrons present in the given structure has to be identified.
Concept introduction:
The unshared electrons of an atom that does not involve in bonding are called lone pair.
Steps to determine the lone of pair of electrons,
- Appropriate valence electron has to be known.
- The actual number of valence electrons exhibited by the atom has to be known.
- Count the number of bonds and assign the number of lone pair.
A formal charge (FC) is the charge assigned to an atom in a molecule, irrespective of relative electronegativity by thinking that electrons in all
(f)
Interpretation:
The lone pair of electrons on nitrogen is delocalized or not has to be identified.
Concept introduction:
The unshared electrons of an atom that does not involve in bonding are called lone pair.
Steps to determine the lone of pair of electrons,
- Appropriate valence electron has to be known.
- The actual number of valence electrons exhibited by the atom has to be known.
- Count the number of bonds and assign the number of lone pair.
A formal charge (FC) is the charge assigned to an atom in a molecule, irrespective of relative electronegativity by thinking that electrons in all chemical bonds are shared equally among atoms. Electrons can be tracked by formal charge.
(g)
Interpretation:
Geometry of the atoms except hydrogen has to be identified.
Concept introduction:
The steric number is the combination of both number of
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
trigonal pyramidal(if one lone pair of electron is present).
bent geometry (if two lone pair of electrons are present).
(h)
Interpretation:
The resonance structures of cycloserine have to be drawn.
Concept Introduction:
The unshared electrons of an atom that does not involve in bonding are called lone pair.
Curved arrows are necessary in drawing the resonance structure.
Curved arrows has a head indicating that the electrons are coming and tail indicating that the electrons are going.
The two rules in drawing the resonance structure is,
- Breaking of single bond is not allowed.
- Never exceed an octet for second row elements.
When a single Lewis structure does not represent a structure adequately, the true structure is the intermediate between the two or more structure referred to as resonance structure.

Want to see the full answer?
Check out a sample textbook solution
Chapter 2 Solutions
ORGANIC CHEMISTRY 1 TERM ACCESS
- 10. The most important reason why Br- is a better nucleophile than Cl-is ___. A. polarizability; B. size; C. solvation; D. basicity; E. polarity. Please include all steps. Thanks!arrow_forwardPredicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid Ка K₁₁ name formula name formula nitrous acid HNO2 4.5×10 4 pyridine CHEN 1.7 × 10 9 4 hydrofluoric acid HF 6.8 × 10 methylamine CH3NH2 | 4.4 × 10¯ Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution 0.1 M NaNO2 0.1 M KF pH choose one v choose one v 0.1 M C5H5NHBr 0.1 M CH3NH3CI choose one v ✓ choose one 1 (lowest) 2 ☑ 3 4 (highest) 000 18 Ararrow_forward4. The major product from treatment of 2-propanol with the Jonesreagent is ___.A. acetone; B. none of the other answers is correct C. propene; D.propanoic acid; E carbon dioxide. Please include all steps! Thank you!arrow_forward
- 7. All of the following compounds that are at the same oxidation levelare ___.u. methyl epoxide, v. propyne, w. propanal, x. propene,y. 2,2-dihydroxypropane, z. isopropanol?A. u,v,w,y; B. u,v,w; C. v,w,y,z; D. v, z; E. x,y,z Please include all steps. Thank you!arrow_forward9. Which one of the following substituents is the worst leaving group inan SN2 reaction? A. -NH2; B. -OH; C. –F; D. NH3; E. H2O Please include all steps. Thanks!arrow_forwardUsing the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 2.5 × 105: CO(g) + H2O(g) CO2(g) + H2(g) Use this information to complete the following table. Suppose a 7.0 L reaction vessel is filled with 1.7 mol of CO and 1.7 mol of H2O. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. CO2(9)+H2(g) CO(g)+H₂O(g) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 3 CO(g)+3H2O(g) = 3 CO2(g)+3H2(g) There will be very little CO and H2O. x10 There will be very little CO2 and H2. 000 Neither of the above is true. K = ☐ K = ☐ 18 Ararrow_forward
- 8. When ethane thiol is treated with hydrogen peroxide the product is___.A. ethane disulfide; B. diethyl sulfide; C. ethane sulfoxide; D. ethanesulfate; E. ethyl mercaptan. Please include all steps. Thanks!arrow_forward5. The major product of the three step reaction that takes place when 1-propanol is treated with strong acid is?A. dipropyl ether; B. propene; C. propanal; D. isopropyl propyl ether;E. 1-hexanol Please include all steps. Thank you!arrow_forward6. The formula of the product of the addition of HCN to benzaldehydeis ___.A. C8H7NO; B. C8H6NO; C. C14H11NO; D. C9H9NO; E. C9H8NO Please include all steps. Thank you!arrow_forward
- Predicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid K K a name formula name formula nitrous acid HNO2 4.5×10 hydroxylamine HONH2 1.1 × 10 8 hypochlorous acid HCIO 8 3.0 × 10 methylamine CH3NH2 | 4.4 × 10¯ 4 Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. 0.1 M KCIO solution PH choose one 0.1 M NaNO2 0.1 M CH3NH3Br 0.1 M NaBr choose one ✓ choose one v ✓ choose one 1 (lowest) ☑ 2 3 4 (highest)arrow_forwardFor this Orgo problem, don't worry about question 3 below it. Please explain your thought process, all your steps, and also include how you would tackle a similar problem. Thank you!arrow_forwardUsing the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.84: H2(g) + 2(g) 2 HI(g) = Use this information to complete the following table. Suppose a 34. L reaction vessel is filled with 0.79 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and 12. ☐ x10 There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 HI(g) H₂(9)+12(9) K = What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 H2(g)+212(9) 4 HI(g) K = ☐ ☑arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





