Proton is a fundamental particle which has positive charge and present in the nucleus of an atom. Concept introduction: Density is defined as the ratio of mass and volume. Density = Mass volume Volume of sphere = 4 3 π r 3 Here, r = radius of sphere. To determine: The density of proton

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Answer 1

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Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

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A proton has a radius of approximately 1.0×10−13 cmcm and a mass of 1.7×10−24 gg. Determine the density of a proton. For a sphere V=(43)πr3V=(43)πr3.

Jupiter’s mass is estimated to be 1.90 x 1027 kg, and it has a diameter of 142,984 km. Assuming that Jupiter is spherical, estimate its density [the volume of a sphere is (4πr3)/3].

On the planet Xgnu, the most common units of length are the blim (for long distances) and the kryll (for shorter distances). Because the Xgnuese have 14 fingers, it is not perhaps surprising that 1400 kryll = 1 blim. Two cities on Xgnu are 21.2 blim apart. What is this distance in kryll?

Answer 2

Question

Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

Answer 6

Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

Answer 7

Chapter 2, Problem 62E

Interpretation Introduction

Interpretation:

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

Concept introduction:

Density is defined as the ratio of mass and volume.

$Density = \frac{Mass}{volume}$

Volume of sphere $= \frac{4}{3} π r^{3}$

Here, $r =$ radius of sphere.

To determine:

The density of proton

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 2 - Prob. 1SAQ Ch. 2 - Convert 1,285 cm2 to m2. a) 1.285 X 107 m2 b)...Ch. 2 - Prob. 3SAQ Ch. 2 - Prob. 4SAQ Ch. 2 - Prob. 5SAQ Ch. 2 - Prob. 6SAQ Ch. 2 - Prob. 7SAQ Ch. 2 - A solid copper cube contains 4.3 X 1023 atoms....Ch. 2 - Determine the number of atoms in 1.85 mLof...Ch. 2 - Prob. 10SAQ

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom. Concept introduction: Density is defined as the ratio of mass and volume. Density = Mass volume Volume of sphere = 4 3 π r 3 Here, r = radius of sphere. To determine: The density of proton

Solution Summary: The author explains that proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

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Chapter 2 Solutions

Proton is a fundamental particle which has positive charge and present in the nucleus of an atom. Concept introduction: Density is defined as the ratio of mass and volume. Density = Mass volume Volume of sphere = 4 3 π r 3 Here, r = radius of sphere. To determine: The density of proton

Solution Summary: The author explains that proton is a fundamental particle which has positive charge and present in the nucleus of an atom.

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Videos

Interpretation: Proton is a fundamental particle which has positive charge and present in the nucleus of an atom. Concept introduction: Density is defined as the ratio of mass and volume. Density=Massvolume Volume of sphere =43πr3 Here, r= radius of sphere. To determine: The density of proton

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Chapter 2 Solutions