Explanation Given: Unit weight of water ( γ ) is 62.4 lb / ft 3 . Width of the dam ( b ) is 1 ft. Distance between point A and C ( h A C ) is 2 ft. Distance between point C and D ( h C D ) is 12 ft. Height of point C to B ( h C B ) is 2 ft. Unit weight of concrete ( γ C ) is 150 lb / ft 3 . Height of water in the dam is h . Calculation: Determine the load at point B ( w B ) . w B = γ w h b w B = 62.4 lb / ft 3 × h × 1 ft = ( 62.4 h ) lb / ft Determine the resultant force ( F ). F = 1 2 w B h F = 1 2 ( 62.4 h lb / ft ) h = 31.2 h 2 Determine the volume of the triangular region ACD ( V 1 ) . V 1 = 1 2 h A C h C D b V 1 = 1 2 × 2 ft × 12 ft × 1 ft = 12 ft 3 Determine the volume of the rectangle CDEB ( V 2 ) . V 2 = h C B h C D b V 2 = 2 ft × 12 ft × 1 ft = 24 ft 3 Determine the weight of the block ACD ( W 1 ) . W 1 = γ C V 1 W 1 = 150 lb / ft 3 × 12 ft 3 = 1 , 800 lb Determine the weight of the block CDEB ( W 2 )

2nd Edition

ISBN: 9780134649290

Author: Russell C. Hibbeler

Publisher: PEARSON

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Chapter 2, Problem 55P

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The critical height of water in the dam.

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Chapter 2, Problem 54P

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Fluid Mechanics (2nd Edition)

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