
Concept explainers
(a)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. The element which is positioned left in periodic table is named first followed by another element. The second element’s name also ends with suffix “ide”. Hence, compound’s formula can be easily be utilized to find its name.
(a)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound,
The oxidation state of the element is written in bracket after naming the element. The oxidation state of copper in the given compound is
Hence, the compound
(b)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. The element which is positioned left in periodic table is named first followed by another element. The second element’s name also ends with suffix “ide”. Hence, compound’s formula can be easily be utilized to find its name.
(b)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound,
The oxidation state of the element is written in bracket after naming the element. The oxidation state of copper in the given compound is
Hence, the compound
(c)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. The element which is positioned left in periodic table is named first followed by another element. The second element’s name also ends with suffix “ide”. Hence, compound’s formula can be easily be utilized to find its name.
(c)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound,
The oxidation state of the element is written in bracket after naming the element. The oxidation state of cobalt in the given compound is
Hence, the compound
(d)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. In case of ionic compounds, cation’s (positive ion) name is always given first followed by anion’s (negative ion) name. The cation carries its elemental name. Anion and cation combine in a way that overall neutral compound gets generated.
(d)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The cation in
The charge on sodium cation is
Hence, the compound
(e)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. In case of ionic compounds, cation’s (positive ion) name is always given first followed by anion’s (negative ion) name. The cation carries its elemental name. Anion and cation combine in a way that overall neutral compound gets generated.
(e)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The cation in
The charge on sodium cation is
Hence, the compound
(f)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. The element which is positioned left in periodic table is named first followed by another element. The second element’s name also ends with suffix “ide”. Hence, compound’s formula can be easily be utilized to find its name.
(f)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The compound contains four sulphur atoms and four nitrogen atoms. Since, sulphur is positioned left to nitrogen in periodic table, its name is written first.
Hence, the compound
(g)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. The element which is positioned left in periodic table is named first followed by another element. The second element’s name also ends with suffix “ide”. Hence, compound’s formula can be easily be utilized to find its name.
(g)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The compound contains one selenium atom and one bromine atom. Since, selenium is positioned left to bromine in periodic table, its name is written first.
The oxidation state of the element is written in bracket after naming the element. The oxidation state of selenium in the given compound is
Hence, the compound
(h)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. In case of ionic compounds, cation’s (positive ion) name is always given first followed by anion’s (negative ion) name. The cation carries its elemental name. Anion and cation combine in a way that overall neutral compound gets generated.
(h)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The cation in
The charge on sodium cation is
Hence, the compound
(i)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. In case of ionic compounds, cation’s (positive ion) name is always given first followed by anion’s (negative ion) name. The cation carries its elemental name. Anion and cation combine in a way that overall neutral compound gets generated.
(i)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The cation in
The charge on barium cation is
Hence, the compound
(j)
Interpretation: The name of the compound
Concept introduction: A chemical compound’s name can be given via elements or ions that are part of that compound. This is done using suitable suffix and prefix. In case of ionic compounds, cation’s (positive ion) name is always given first followed by anion’s (negative ion) name. The cation carries its elemental name. Anion and cation combine in a way that overall neutral compound gets generated.
(j)

Answer to Problem 55E
The name of the compound
Explanation of Solution
The given compound is
The cation in
The charge on ammonium cation is
Hence, the compound
Want to see more full solutions like this?
Chapter 2 Solutions
EBK CHEMICAL PRINCIPLES
- 3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forwardWhat is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forward
- Use the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forward
- 7. Magnesium is found in nature in the form of carbonates and sulfates. One of the major natural sources of zinc is zinc blende (ZnS). Use relevant concepts of acid-base theory to explain this combination of cations and anions in these minerals. (2 points)arrow_forward6. AlF3 is insoluble in liquid HF but dissolves if NaF is present. When BF3 is added to the solution, AlF3 precipitates. Write out chemical processes and explain them using the principles of Lewis acid-base theory. (6 points)arrow_forward5. Zinc oxide is amphoteric. Write out chemical reactions for dissolution of ZnO in HCl(aq) and in NaOH(aq). (3 points)arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning




