(a)
Interpretation:
The number of orbitals contained in first shell (n=1) should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:
(b)
Interpretation:
The number of orbitals contained in second shell (n=2) should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The atomic number of the elements represents the number of protons or electrons in a neutral atom. All known elements are arranged in a tabular form in increasing order of their atomic number that is called as the periodic table.
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:
(c)
Interpretation:
The number of orbitals contained in third shell (n=3) should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The atomic number of the elements represents the number of protons or electrons in a neutral atom. All known elements are arranged in a tabular form in increasing order of their atomic number that is called as the periodic table.
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:
(d)
Interpretation:
The number of orbitals contained in firth shell (n=4) should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The atomic number of the elements represents the number of protons or electrons in a neutral atom. All known elements are arranged in a tabular form in increasing order of their atomic number that is called as the periodic table.
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:

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Chapter 2 Solutions
CONNECT IA GENERAL ORGANIC&BIO CHEMISTRY
- . Draw the products for addition reactions (label as major or minor) of the reaction between 2-methyl-2-butene and with following reactants : Steps to follow : A. These are addition reactions you need to break a double bond and make two products if possible. B. As of Markovnikov rule the hydrogen should go to that double bond carbon which has more hydrogen to make stable products or major product. Here is the link for additional help : https://study.com/academy/answer/predict-the-major-and-minor-products-of-2-methyl- 2-butene-with-hbr-as-an-electrophilic-addition-reaction-include-the-intermediate- reactions.html H₂C CH3 H H3C CH3 2-methyl-2-butene CH3 Same structure CH3 IENCESarrow_forwardDraw everything on a piece of paper including every single step and each name provided using carbons less than 3 please.arrow_forwardTopics] [References] Write an acceptable IUPAC name for the compound below. (Only systematic names, not common names are accepted by this question.) Keep the information page open for feedback reference. H The IUPAC name isarrow_forward
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- An open tubular column has an inner diameter of 207 micrometers, and the thickness of the stationary phase on the inner wall is 0.50 micrometers. Unretained solute passes through in 63 seconds and a particular solute emerges at 433 seconds. Find the distribution constant for this solute and find the fraction of time spent in the stationary phase.arrow_forwardConsider a chromatography column in which Vs= Vm/5. Find the retention factor if Kd= 3 and Kd= 30.arrow_forwardTo improve chromatographic separation, you must: Increase the number of theoretical plates on the column. Increase the height of theoretical plates on the column. Increase both the number and height of theoretical plates on the column. Increasing the flow rate of the mobile phase would Increase longitudinal diffusion Increase broadening due to mass transfer Increase broadening due to multiple paths You can improve the separation of components in gas chromatography by: Rasing the temperature of the injection port Rasing the temperature of the column isothermally Rasing the temperature of the column using temperature programming In GC, separation between two different solutes occurs because the solutes have different solubilities in the mobile phase the solutes volatilize at different rates in the injector the solutes spend different amounts of time in the stationary phasearrow_forward
- please draw and example of the following: Show the base pair connection(hydrogen bond) in DNA and RNAarrow_forwardNaming and drawing secondary Write the systematic (IUPAC) name for each of the following organic molecules: CH3 Z structure CH3 CH2 CH2 N-CH3 CH3-CH2-CH2-CH-CH3 NH CH3-CH-CH2-CH2-CH2-CH2-CH2-CH3 Explanation Check ☐ name ☐ 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C Garrow_forwardC This question shows how molecular orbital (MO) theory can be used to understand the chemical properties of elemental oxygen O₂ and its anionic derivative superoxide Oz. a) Draw the MO energy diagram for both O2 and O2. Clearly label your diagram with atomic orbital names and molecular orbital symmetry labels and include electrons. Draw the Lewis structure of O2. How does the MO description of O2 differ from the Lewis structure, and how does this difference relate to the high reactivity and magnetic properties of oxygen? ) Use the MO diagram in (a) to explain the difference in bond length and bond energy between superoxide ion (Oz, 135 pm, 360 kJ/mol) and oxygen (O2, 120.8 pm, 494 kJ/mol).arrow_forward
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