Chemistry (OER)
19th Edition
ISBN: 9781947172623
Author: OpenStax
Publisher: OpenStax College
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Chapter 2, Problem 42E
Use the periodic table to give the name and symbol for each of the following elements:
- the halogen in the same period as the alkali metal with 11 protons
- the alkaline earth metal in the same period with the neutral noble gas with 18 electrons
- the noble gas in the same row as an isotope with 30 neutrons and 25 protons
- the noble gas in the same period as gold
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In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?
In the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.
In one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.
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