(a) Interpretation: Among the following species, the species with equal numbers of neutrons and protons should be identified. 24 Mg 2 + , 47 Cr, 60 Co 3 + , 35 Cl − , 124 Sn 2 + , 226 Th, 90 Sr Concept introduction: The atomic number is equal to the number of protons of an element whereas sum of number of protons and number of neutrons is equal to mass number. A form of chemical element having same atomic number but differ by mass number is known as isotopes. In nuclide notation of isotope, the mass number of the isotope is present in superscript in front of the symbol of given element and atomic number is present in subscript in front of the symbol of the element. The expression is given by: E z A where, A = mass number and Z = atomic number
(a) Interpretation: Among the following species, the species with equal numbers of neutrons and protons should be identified. 24 Mg 2 + , 47 Cr, 60 Co 3 + , 35 Cl − , 124 Sn 2 + , 226 Th, 90 Sr Concept introduction: The atomic number is equal to the number of protons of an element whereas sum of number of protons and number of neutrons is equal to mass number. A form of chemical element having same atomic number but differ by mass number is known as isotopes. In nuclide notation of isotope, the mass number of the isotope is present in superscript in front of the symbol of given element and atomic number is present in subscript in front of the symbol of the element. The expression is given by: E z A where, A = mass number and Z = atomic number
Solution Summary: The author explains that the species with equal numbers of neutrons and protons should be identified.
Among the following species, the species with equal numbers of neutrons and protons should be identified.
24Mg2+, 47Cr, 60Co3+, 35Cl−, 124Sn2+, 226Th, 90Sr
Concept introduction:
The atomic number is equal to the number of protons of an element whereas sum of number of protons and number of neutrons is equal to mass number.
A form of chemical element having same atomic number but differ by mass number is known as isotopes. In nuclide notation of isotope, the mass number of the isotope is present in superscript in front of the symbol of given element and atomic number is present in subscript in front of the symbol of the element.
The expression is given by: EzA
where, A = mass number and Z = atomic number
Interpretation Introduction
(b)
Interpretation:
Among the following species, the species in which protons contributing 50% of the mass.
24Mg2+, 47Cr, 60Co3+, 35Cl−, 124Sn2+, 226Th, 90Sr
Concept introduction:
The atomic number is equal to the number of protons of an element whereas sum of number of protons and number of neutrons is equal to mass number.
A form of chemical element having same atomic number but differ by mass number is known as isotopes. In nuclide notation of isotope, the mass number of the isotope is present in superscript in front of the symbol of given element and atomic number is present in subscript in front of the symbol of the element.
The expression is given by: XzA
where, A = mass number and Z = atomic number
Interpretation Introduction
(c)
Interpretation:
Among the following species, the species which has about 50% more neutrons than protons should be identified.
24Mg2+, 47Cr, 60Co3+, 35Cl−, 124Sn2+, 226Th, 90Sr
Concept introduction:
The atomic number is equal to the number of protons of an element whereas sum of number of protons and number of neutrons is equal to mass number.
A form of chemical element having same atomic number but differ by mass number is known as isotopes. In nuclide notation of isotope, the mass number of the isotope is present in superscript in front of the symbol of given element and atomic number is present in subscript in front of the symbol of the element.
1. Determine the relationship between the following molecules as identical, diastereomers, or enantiomers (6
points, 2 points each).
OH
OH
OH
A-A
OH
HOT
HO-
ACHN
and
HO-
ACHN
OH
HO
HO
°
OH
and
OH
OH
SH
and
...SH
20,0
Complete the electron pushing mechanism to
y drawing the necomery unicaciones and carved on for
Step 1: Add curved arms for the tint step, traiment with NalilĻ. The Nation
458
Step 2: Added for the second step, inalment with), how the "counterion
bar
Step 3: Daw the products of the last simplom organic and one incoganic spacient, including all nonbonding
please provide the structure for this problem, thank you!