Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 2, Problem 34AP
In Figure 2.11b, the area under the velocity–time graph and between the vertical axis and time t (vertical dashed line) represents the displacement. As shown, this area consists of a rectangle and a triangle. (a) Compute their areas. (b) Explain how the sum of the two areas compares with the expression on the right-hand side of Equation 2.16.
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is 0.3026 a finite number
Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that
system of all three beads is zero.
91
E field lines
93
92
What charge does each bead carry?
91
92
-1.45
=
=
What is the net charge of the system? What charges have to be equal? μC
2.9
×
What is the net charge of the system? What charges have to be equal? μC
93 = 2.9
μС
92
is between and
91 93°
The sum of the charge on q₁ and 92 is 91 + 92 = −2.9 μC, and the net charge of the
Chapter 2 Solutions
Physics for Scientists and Engineers with Modern Physics
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Ch. 2 - The position of a pinewood derby car was observed...Ch. 2 - An athlete leaves one end of a pool of length L at...Ch. 2 - A positiontime graph for a particle moving along...Ch. 2 - A car travels along a straight line at a constant...Ch. 2 - A person takes a trip, driving with a constant...Ch. 2 - A child rolls a marble on a bent track that is 100...Ch. 2 - Figure P2.9 shows a graph of vx versus t for the...Ch. 2 - (a) Use the data in Problem 3 to construct a...Ch. 2 - A particle starts from rest and accelerates as...Ch. 2 - Draw motion diagrams for (a) an object moving to...Ch. 2 - Each of the strobe photographs (a), (b), and (c)...Ch. 2 - An electron in a cathode-ray tube accelerates...Ch. 2 - A parcel of air moving in a straight tube with a...Ch. 2 - In Example 2.7, we investigated a jet landing on...Ch. 2 - An object moving with uniform acceleration has a...Ch. 2 - Solve Example 2.8 by a graphical method. On the...Ch. 2 - A glider of length moves through a stationary...Ch. 2 - Why is the following situation impossible?...Ch. 2 - A glider of length 12.4 cm moves on an air track...Ch. 2 - In the particle under constant acceleration model,...Ch. 2 - At t = 0, one toy car is set rolling on a straight...Ch. 2 - You are observing the poles along the side of the...Ch. 2 - Prob. 25PCh. 2 - An attacker at the base of a castle wall 3.65 m...Ch. 2 - The height of a helicopter above the ground is...Ch. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - At time t = 0, a student throws a set of keys...Ch. 2 - Prob. 31PCh. 2 - A student drives a moped along a straight road as...Ch. 2 - Automotive engineers refer to the time rate of...Ch. 2 - In Figure 2.11b, the area under the velocitytime...Ch. 2 - The froghopper Philaenus spumarius is supposedly...Ch. 2 - A woman is reported to have fallen 144 ft from the...Ch. 2 - At t = 0, one athlete in a race running on a long,...Ch. 2 - Prob. 38APCh. 2 - Hannah tests her new sports car by racing with...Ch. 2 - Two objects, A and B, are connected by hinges to a...Ch. 2 - Prob. 41APCh. 2 - Two thin rods are fastened to the inside of a...Ch. 2 - In a womens 100-m race, accelerating uniformly,...
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- Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that 92 is between q₁ and 93. The sum of the charge on 9₁ and 92 is 9₁ + 92 = −2.9 µС, and the net charge of the system of all three beads is zero. E field lines 93 92 What charge does each bead carry? 91 92 -1.45 What is the net charge of the system? What charges have to be equal? μC 2.9 ✓ What is the net charge of the system? What charges have to be equal? μC 93 2.9 μεarrow_forwardNo chatgpt pls will upvotearrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.49 xm to the right of the 2.50 μC chargearrow_forward
- Find the electric field at the location of q, in the figure below, given that q₁ =9c9d = +4.60 nC, q = -1.00 nC, and the square is 20.0 cm on a side. (The +x axis is directed to the right.) magnitude direction 2500 x What symmetries can you take advantage of? What charges are the same magnitude and the same distance away? N/C 226 × How does charge sign affect the direction of the electric field? counterclockwise from the +x-axis 9a 9b % 9 9darrow_forwardwould 0.215 be the answer for part b?arrow_forwardSuppose a toy boat moves in a pool at at a speed given by v=1.0 meter per second at t=0, and that the boat is subject to viscous damping. The damping on the boat causes the rate of speed loss to be given by the expression dv/dt=-2v. How fast will the boat be traveling after 1 second? 3 seconds? 10 seconds? Use separation of variables to solve this.arrow_forward
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- What is the net charge on a sphere that has the following? x (a) 5.75 × 106 electrons and 8.49 × 106 protons 4.39e-13 What is the charge of an electron? What is the charge of a proton? C (b) 200 electrons and 109 protons 1.60e-10 What is the charge of an electron? What is the charge of a proton? Carrow_forwardA spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of 3.5 μC. A second spider with a charge of 4.2 μC rests in her own web exactly 2.1 m vertically below the first spider. (a) What is the magnitude of the electric field due to the charge on the second spider at the position of the first spider? 8.57e3 N/C (b) What is the tension in the silk fiber above the first spider? 0.125 How does the electric field relate to the force? How do you calculate the net force? Narrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.185 xm to the right of the 2.50 μC chargearrow_forward
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